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\(a,x:\left(354-293\right)=32\cdot6\\ \Leftrightarrow x:61=192\\ \Leftrightarrow x=11712\)
b, x : 65 = 36 dư 7
\(\Rightarrow x=36\cdot65+7\\ \Leftrightarrow x=2347\)
\(c,\left(376+534\right):x=175:35\\ \Leftrightarrow910:x=5\\ \Leftrightarrow x=182\\ d,5\cdot\left(4+6x\right)=290\\ \Leftrightarrow6x+4=58\\ \Leftrightarrow6x=54\\ \Leftrightarrow x=9\)
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a: \(=\dfrac{21\cdot11}{22\cdot9}=\dfrac{1}{2}\cdot\dfrac{7}{3}=\dfrac{7}{6}\)
b: \(=\dfrac{49\cdot8}{10}=49\cdot\dfrac{4}{5}=\dfrac{196}{5}\)
c: \(=\dfrac{12\cdot\left(-4\right)}{32\cdot6}=\dfrac{-48}{192}=-\dfrac{1}{4}\)
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Đáp án cần chọn là: D
x : − 2 5 = 3 54 x = 3 54 . − 2 5 x = 1 18 . − 2 5 x = − 1 45
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( 4 + x ) + ( 9 + x ) + ( 14 + x ) +...+ ( 54 + x ) =354
4+x+9+x+14+x+...+54+x=354
(4+9+14+...+54)+ 11x =354
319 + 11x =354
11x=35
x=35/11
( 4 + x ) + ( 9 + x) + ( 14 + x) + ... + ( 54 + x) = 354
(4+96)+(9+49)+(14+136)+(54+0)
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Bài 1 :
a) \(...=45\left(56+44\right)-500=45.100-500=4500-500=4000\)
b) \(...=3^2.6-6^{18}+1=45+1-6^{18}=46-6^{18}\)
c) \(...=756\left(66+48-14\right)=756.100=75600\)
d) \(...=8.15-\left(149-7^2\right)=120-\left(149-49\right)=120-100=20\)
Bài 2 :
a) \(x-21=46\Rightarrow x=21+46\Rightarrow x=87\)
b) \(2^x.4=128\Rightarrow2^x=32\Rightarrow2^x=2^5\Rightarrow x=5\)
c) \(3x+27=162\Rightarrow3x=162-27\Rightarrow3x=135\Rightarrow x=45\)
d) \(4x-8=4^{2023}.4^{2021}\)
\(\Rightarrow4x-8=4^{2023+2021}\)
\(\Rightarrow4x-8=4^{4044}\)
\(\Rightarrow4x=4^{4044}+8\)
\(\Rightarrow x=\left(4^{4044}+8\right):4\)
\(\Rightarrow x=4^{4043}+2\)
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=>31x=354+18=372
=>x=372:31=12
Vậy x=12.
Hok tốt!!
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=>\(\frac{x+\frac{2}{7}+\frac{2}{17}-\frac{2}{293}}{\frac{3}{7}+\frac{3}{5}+\frac{3}{17}-\frac{3}{293}}-\frac{2}{3}=0\)
=>\(\frac{x+0,396535406}{1,194803109}-\frac{2}{3}=0\)
=>x+0,396535406:1,194803109-2/3=0
x+0,396535406:1,194803109=0+2/3=2/3
còn lại tự giải nha nhiều quá
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Bài này được cái dễ lộn số =.=
Ta có :
\(B=\frac{352+353+354}{353+354+355}=\frac{352}{343+354+355}+\frac{353}{353+354+355}+\frac{354}{353+354+355}\)
Vì :
\(\frac{352}{343}>\frac{352}{353+354+355}\)
\(\frac{353}{354}>\frac{353}{353+354+355}\)
\(\frac{354}{355}>\frac{354}{353+354+355}\)
Nên \(\frac{352}{353}+\frac{353}{354}+\frac{354}{355}>\frac{352+353+354}{353+354+355}\)
Hay \(A>B\)
Vậy \(A>B\)
Chúc bạn học tốt ~
Ta có : \(B=\frac{352+353+354}{353+354+355}\)
\(\Rightarrow B=\frac{352}{353+354+355}+\frac{353}{353+354+355}+\frac{354}{353+354+355}\)
Ta có : \(\frac{352}{353}>\frac{352}{353+354+355}\)
\(\frac{353}{354}>\frac{353}{353+354+355}\)
\(\frac{354}{355}>\frac{354}{353+354+355}\)
Cộng vế theo vế, ta có : \(\frac{352}{353}+\frac{353}{354}+\frac{354}{355}>\frac{352+353+354}{353+354+355}\)
\(\Rightarrow A>B\)
x: (354 - 293 ) = 32.6
X : 61 = 192
x = 192 x 61
x = 11712
x: (354 - 293 ) =32.6
X : 61 =192
x =192 x 61
x =11712