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d, X/8*32+X/3*18-X/5*10=120
X*32/8+X*18/3-X*10/5=120
32X/8+18X/3-10X/5=120
4X+6X-2X=120
8X=120
X=120/8
X=15
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a) x - \(\frac{1}{8}\)= \(\frac{7}{3}\)x \(\frac{21}{4}\)
x - \(\frac{1}{8}\)= \(\frac{49}{4}\)
x = \(\frac{49}{4}\)+ \(\frac{1}{8}\)
x = 98
b) x : \(\frac{3}{2}\) = \(\frac{1}{4}\)
x = \(\frac{1}{4}\)x \(\frac{3}{2}\)
x = \(\frac{3}{8}\)
c) \(\frac{103}{10}\) - x = \(\frac{4}{5}\)
x = \(\frac{103}{10}\)- \(\frac{4}{5}\)
x = \(\frac{19}{5}\)
d) x = 51 x \(\frac{4}{17}\)
x = \(12\)
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180 - ( x + 15 ) : x x 20 = 100
( x + 15 ) : x x 20 = 80
( x + 15 ) : x = 4
x : x + 15/x = 4
1 + 15/x = 4
15/x = 3
x = 5
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`@` `\text {Ans}`
`\downarrow`
`a)`
`x - 452 \times 2 = 180`
`x - 904 = 180`
`x = 180 + 904`
`x = 1084`
`b)`
`x + 58 \div 2 = 60`
`x + 29 = 60`
`x = 60 - 29`
`x = 31`
`c)`
`x - 1 - 2 - 3 - 4 = 0`
`x - (1 + 2 + 3 + 4) = 0`
`x - 10 = 0`
`x = 0 + 10`
`x = 10`
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a 180 -(x + 15) : 4 =80:5 180 - (x + 15) : 4 = 16 180 - ( x + 15) = 16 x 4 180 - ( x + 15 ) = 64 x + 15 = 180 - 64 x + 15 = 116 x= 116 - 15 x = 101
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180 : ( 18 x 5 )
= 180 : 90
= 2
b) 240 : ( 2 x 3 x 4 )
= 240 : 24
= 10
c) 4400 : ( 22 x 35 )
= 4400 : 770
= \(\dfrac{40}{7}\)
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c.từ 7 đến 43 có:(43-7):4+1=10(số)
từ 7 đến 43 có 10 số=>có 10 số X
[X+7]+[X+11]+[X+15]+...+[X+43]=1980
X*10+(7+11+15+...+43)=1980
X*10+250=1980
X*10=1980-250
X*10=1730
X=1730:10
X=173
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a) \(2900\times94+2900\times5+2900\)
\(=2900\times\left(94+5+1\right)\)
\(=2900\times100\)
\(=290000\)
b) \(34000:125:8\)
\(=34000:\left(125\times8\right)\)
\(=34000:1000\)
\(=34\)
x + c = 2000 , x - c = 180
\(\Rightarrow\)x = ( 2000 + 180 ) : 2 = 1090
\(\Rightarrow\)c = 2000 - 1090 = 910
Vậy x = 1090, c = 910
x = ( 2000 + 180 ) / 2 = 1090
c = ( 2000 - 180) / 2 = 910