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x:0,2=0,8:x
\(\dfrac{x}{0,2}=\dfrac{0,8}{x}\\ \Leftrightarrow x.x=0,8.0,2\\ \Rightarrow x^2=0,16\\ \Rightarrow x^2=\left(\pm0,4\right)^2\\ \Rightarrow x=\pm0,4\)
Vậy...
\(\dfrac{x}{0,2}=\dfrac{0,8}{x}\)
\(\Leftrightarrow x.x=0,2.0,8\)
\(\Leftrightarrow x^2=0,16\)
\(\Leftrightarrow x^2=\left(0,4\right)^2\)
\(\Leftrightarrow x=0,4\)
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a,\(\Leftrightarrow\frac{x}{0,2}=\frac{x}{0,8}\Leftrightarrow0,8x=0,2x\Leftrightarrow0,6x=0\Leftrightarrow x=0\)
b,\(\Leftrightarrow\frac{x+11}{14-x}=\frac{2}{3}\)
\(\Leftrightarrow3\left(x+11\right)=2\left(14-x\right)\)
\(\Leftrightarrow3x+33=28-2x\)
\(\Leftrightarrow3x+2x=28-33\)
\(\Leftrightarrow5x=-5\Leftrightarrow x=-1\)
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\(\frac{x+2}{0,8}=\frac{0,2}{x+2}\)
=> \(\left(x+2\right)^2=0,2\cdot0,8\)
=> \(\left(x+2\right)^2=0,16\)
=> \(x+2=0,4\) và \(x+2=-0,4\)
=> \(x=0,4-2=-1,6\) và \(x=-0,4-2=-2,4\)
\(\frac{x+2}{0,8}=\frac{0,2}{x+2}\Leftrightarrow\left(x+2\right)\left(x+2\right)=0,2.0,8\Leftrightarrow\left(x+2\right).\left(x+2\right)=0,16\)
\(\Leftrightarrow\left(x+2\right)^2=0,16\)
(+) x + 2 =\(\sqrt{0,16}\) => x + 2 = 0,4 => x = 0,4 - 2 = - 1 ,6
(+) x + 2 = - căn 0,16 => x + 2 = - 0,4 => x = -0,4 - 2 = -2,4
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a: \(\dfrac{x}{0.9}=\dfrac{5}{6}\)
\(\Leftrightarrow x=\dfrac{3}{4}\)
b: \(\dfrac{-6}{x}=\dfrac{9}{-15}\)
\(\Leftrightarrow x=10\)
c: \(\dfrac{\dfrac{14}{15}}{\dfrac{9}{10}}=\dfrac{x}{\dfrac{3}{7}}\)
\(\Leftrightarrow x=\dfrac{3}{7}\cdot\dfrac{14}{15}:\dfrac{9}{10}=\dfrac{2}{5}\cdot\dfrac{10}{9}=\dfrac{20}{45}=\dfrac{4}{9}\)
\(x\div0,2=0,8\div x.\)
\(\Leftrightarrow\)\(\frac{x}{0,2}=\frac{0,8}{x}\)
\(\Leftrightarrow\)\(x\times x=0,8\times0,2\)
\(\Leftrightarrow\)\(x^2=0,16\)
\(\Leftrightarrow\)\(x^2=\left(0,4\right)^2\)hoặc \(\left(-0,4\right)^2\)
\(\Leftrightarrow\)\(x=\pm0,4\)
thank maii