Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
A=22+22+23+24+.........+22005
\(2A=2^3+2^3+2^4+2^5+...+2^{2006}\)
\(2A-A=\left(2^3+2^3+2^4+2^5+...+2^{2006}\right)-\left(2^2+2^2+2^3+2^4+...+2^{2005}\right)\)
\(A=\left(2^{2006}+2^3\right)-\left(2^2+2^2\right)\)
\(A=\left(2^{2006}+2^3\right)-2^3\)
\(A=2^{2006}\)
\(2\cdot8^{15}\cdot4\cdot8^{20}=\left(2\cdot4\right)\cdot8^{15+20}=8\cdot8^{35}=8^{36}\)
\(A=1+2+2^2+2^3+...+2^{100}\)
\(\Rightarrow2A=2+2^2+2^3+...+2^{200}+2^{201}\)
\(2A-A=A=\left(2+2^2+2^3+...+2^{201}\right)-\left(1+2+2^2+2^3+...+2^{200}\right)\)
\(\Rightarrow A=2^{201}-1\Rightarrow A+1=2^{201}-1+1=2^{201}\)
ta có
A= 1+2+22+23+...+2200
2A= 2+22+23+...+2201
2A-A=(2+22+23+...+2201)-(1+2+22+23+...+2200)
A=2201 - 1
A+1=2201
\(3\cdot9\cdot81\cdot729=3^1\cdot3^2\cdot3^4\cdot3^6=3^{1+2+4+6}=3^{13}\)
a) \(3^5.4^5=\left(3.4\right)^5=12^5\)
b) \(8^5.2^3=\left(2^3\right)^5.2^3=2^{15}.2^3=2^{15+3}=2^{18}\)
\(3^5.4^5=3+4^5=7^5\)
\(8^5.2^3=8+2^{5+3}=10^8\)
Ko biết nữa !
Nguyen Thi Phuong Anh lừa đảo hả
Haaaaah đừng bấm
Chớt người đó
\(\text{Câu hỏi :}\)
\(\text{5 x 5 x 5 x 5 x 3 x 3 = ?}\)
\(\text{Trả lời :}\)
\(\text{5 x 5 x 5 x 5 x 3 x 3 = 5^4 x 3^2}\)
\(A=2^2+2^2+2^3+2^4+...+2^{2005}\)
\(\Rightarrow2A=2^3+2^3+2^4+2^5+...+2^{2005}+2^{2006}\)
\(\Rightarrow2A-A=\left(2^3+2^3+2^4+2^5+...+2^{2006}\right)-\left(2^2+2^2+2^3+2^4+...+2^{2005}\right)\)
Triệt tiêu hai vế \(\Rightarrow A=\left(2^{2006}+2^3\right)-\left(2^2+2^2\right)=2^{2006}+2^3-2^3\)
\(\Rightarrow A=2^{2006}\)