Question

[Nguyễn Minh Hoàng]

Tính:

\(\frac{4n+3}{7n+1}-\frac{3n-2}{7n+1}+\frac{2n-3}{7n+1}.\)

Answer 1

[Phùng Minh Quân]

Đặt \(A=\frac{4n+3}{7n+1}-\frac{3n-2}{7n+1}+\frac{2n-3}{7n+1}\) ta có : 

\(A=\frac{4n+3-3n+2+2n-3}{7n+1}\)

\(A=\frac{3n+2}{7n+1}\)

Vậy \(A=\frac{3n+2}{7n+1}\)

Chúc bạn học tốt ~ 

Answer 2

[Do Thuy Quynh]

(4n+3-(3n-2)+(2n-3))/7n+1

(4n+3-3n+2+2n-3)/7n+1

=(3n-2)/7n+1