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Bài 12:
a) \(\left(\dfrac{1}{2}x+4\right)^2\)
\(=\left(\dfrac{1}{2}x\right)^2+2\cdot\dfrac{1}{2}x\cdot4+4^2\)
\(=\dfrac{1}{4}x^2+4x+16\)
b) \(\left(7x-5y\right)^2\)
\(=\left(7x\right)^2-2\cdot7x\cdot5y+\left(5y\right)^2\)
\(=49x^2-70xy+25y^2\)
c) \(\left(6x^2+y^2\right)\left(y^2-6x^2\right)\)
\(=\left(y^2+6x^2\right)\left(y^2-6x^2\right)\)
\(=y^4-36x^4\)
d) \(\left(x+2y\right)^2\)
\(=x^2+2\cdot x\cdot2y+\left(2y\right)^2\)
\(=x^2+4xy+4y^2\)
e) \(\left(x-3y\right)\left(x+3y\right)\)
\(=x^2-\left(3y\right)^2\)
\(=x^2-9y^2\)
f) \(\left(5-x\right)^2\)
\(=5^2-2\cdot5\cdot x+x^2\)
\(=25-10x+x^2\)
Ta có:
( 5 2 - 1).P = ( 5 2 – 1).12.( 5 2 + 1)( 5 4 + 1)( 5 8 + 1)( 5 16 + 1)
= 12.( 5 2 – 1).( 5 2 + 1)( 5 4 + 1)( 5 8 + 1)( 5 16 + 1)
= 12.( 5 4 - 1)( 5 4 + 1)( 5 8 + 1)( 5 16 + 1)
= 12.( 5 8 - 1)( 5 8 + 1)( 5 16 + 1)
= 12.( 5 16 - 1)( 5 16 + 1)
= 12.( 5 32 - 1)
\(C=48\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)=2\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)=2\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)
\(=2\left(5^{128}-1\right)=2.5^{128}-2\)
c: Ta có: \(C=48\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\cdot\left(5^{32}+1\right)\left(5^{64}+1\right)\)
\(=2\cdot\left(5^2-1\right)\left(5^2+1\right)\cdot\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)
\(=2\cdot\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)
\(=2\cdot\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)
\(=2\cdot\left(5^{16}-1\right)\cdot\left(5^{16}+1\right)\cdot\left(5^{32}+1\right)\left(5^{64}+1\right)\)
\(=2\cdot\left(5^{32}-1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)
\(=2\cdot\left(5^{64}-1\right)\left(5^{64}+1\right)\)
\(=2\cdot\left(5^{128}-1\right)\)
\(=2\cdot5^{128}-2\)
a) M = (x + 3y)² - (x - 3y)²
= [(x + 3y) - (x - 3y)][(x + 3y) + (x - 3y)]
= (x + 3y - x + 3y)(x + 3y + x - 3y)
= 6y.2x
= 12xy
b) Q = (x - y)² - 4(x - y)(x + 2y) + 4(x + 2y)²
= [(x - y) - 2(x + 2y)]²
= (x - y - 2x - 4y)²
= (-x - 5y)²
a) M = (x + 3y)² - (x - 3y)²
= [(x + 3y) - (x - 3y)][(x + 3y) + (x - 3y)]
= (x + 3y - x + 3y)(x + 3y + x - 3y)
= 6y.2x
= 12xy
b: Q=(x-y)^2-2(x-y)(2x+4y)+(2x+4y)^2
=(x-y-2x-4y)^2
=(-x-5y)^2
=x^2+10xy+25y^2
a) \(=x^2-5-x^2+49=44\)
b) Nhân tử cuối cùng bạn ghi gì vậy?
a: \(=\dfrac{5}{3}x^2-x+\dfrac{1}{3}\)
b: \(=-5y-9+xy\)
a. (\(x\) + 2\(y\))2 = \(x^2\) +2.x.2\(y\) + (2y)2
= \(x^2\) + 4\(xy\) + 4\(y^2\)
b. (\(x\) – 3\(y\))(\(x\) + 3\(y\)) = \(x^2\) – (3\(y\))2 = \(x^2\) – 9\(y^2\)
c. (5 – \(x\))2 = 52 – 2.5\(x\) + \(x^2\) = 25 – 10\(x\) + \(x^2\)
Rút gọn biểu thức:
(52 - 1).P = ( 52 – 1).12.(52 + 1)(54 + 1)(58 + 1)(516 + 1)
= 12.( 52 – 1).(52 + 1)(54 + 1)(58 + 1)(516 + 1)
= 12.( 54 - 1)( 54 + 1)( 58 + 1)(516 + 1)
= 12.( 58 - 1)( 58 + 1)(516 + 1)
= 12.( 516 - 1)(516 + 1)
= 12.( 532 - 1)
a, = \(x^2+4xy+4y^2\)
b, = \(x^2-9y^2\)
học tốt