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S = 1/3+1/9+1/27+1/81+1/243+1/729+1/2187 ( 1 )
Nhân S với 3. Ta có:
S x 3 = 1 + 1/3 + 1/9 + 1/27 + 1/81 + 1/243 + 1/729 ( 2 )
Trừ ( 2 ) với ( 1 ) ta có:
S x 3 - S = 1 - 1/ 2187
2S = 2186/ 2187
S = 2186/ 2187 : 2
S = 1093/ 2187
P = 78 × 31 + 78 × 24 + 78 × 17 + 22 × 72
P = 78 × (31 + 24 + 17) + 22 × 72
P = 78 × 72 + 22 × 72
P = 72 × (78 + 22)
P = 72 × 100
P = 7200
S = 1 + 1/3 + 1/9 + 1/27 + ... + 1/2187
3S = 3 + 1 + 1/3 + 1/9 + ... + 1/729
3S - S = (3 + 1 + 1/3 + 1/9 + ... + 1/729) - (1 + 1/3 + 1/9 + 1/27 + ... + 1/2187)
2S = 3 - 1/2187
2S = 6560/2187
S = 6560/2187 : 2
S = 6560/2187 × 1/2
S = 3280/2187
\(B=\dfrac{1}{3}+\dfrac{1}{9}+\dfrac{1}{27}+...+\dfrac{1}{2187}+\dfrac{1}{6561}\)
\(3B=3\cdot\left(\dfrac{1}{3}+\dfrac{1}{9}+\dfrac{1}{27}+...+\dfrac{1}{6561}\right)\)
\(3B=1+\dfrac{1}{3}+\dfrac{1}{9}+...+\dfrac{1}{729}+\dfrac{1}{2187}\)
\(3B-B=\left(1+\dfrac{1}{3}+\dfrac{1}{9}+...+\dfrac{1}{2187}\right)-\left(\dfrac{1}{3}+\dfrac{1}{9}+...+\dfrac{1}{6561}\right)\)
\(2B=\left(\dfrac{1}{3}-\dfrac{1}{3}\right)+\left(\dfrac{1}{9}-\dfrac{1}{9}\right)+...+\left(1-\dfrac{1}{6561}\right)\)
\(2B=0+0+...+1-\dfrac{1}{6561}\)
\(2B=1-\dfrac{1}{6561}\)
\(B=\left(1-\dfrac{1}{6561}\right):2\)
\(B=\dfrac{6560}{6561}:2\)
\(B=\dfrac{3280}{6561}\)
= 1 x 27/3x27 + 1x9/9x9 + 1x3 / 27 x 3 + 1/81
=27/81 + 9/81 + 3/81 + 1/81
= 40/81
C = 1 + 2 + 4 + 8 + ... + 1024
2 x C = 2 + 4 + 8 + ... + 1024 + 2048
2 x C - C = C = (2 + 4 + 8 + ... + 1024 + 2048) - (1 + 2 + 4 + 8 + ... + 1024) = 2048 - 1 = 2047
D = 1 + 3 + 9 + 27 + ... + 2187
3 x D = 3 + 9 + 27 + ... + 2187 + 6561
3 x D - D = 2 x D = (3 + 9 + 27 + ... + 2187 + 6561) - (1 + 3 + 9 + 27 + ... + 2187) = 6561 - 1 = 6560
D = 6560 : 2 = 3280
Có số số hạng trong dãy số là
(10345-1):2=5172 số
Tổng dãy số đó là
(10345+1)*5172:2=26754756
Đáp số:26754756
\(S=1+\dfrac{1}{3}+\dfrac{1}{9}+...+\dfrac{1}{2187}\)
=>\(S=1+\left(\dfrac{1}{3}\right)+\left(\dfrac{1}{3}\right)^2+...+\left(\dfrac{1}{3}\right)^7\)
=>\(3S=3+1+\dfrac{1}{3}+...+\left(\dfrac{1}{3}\right)^6\)
=>\(3S-S=3+1+\dfrac{1}{3}+...+\left(\dfrac{1}{3}\right)^6-1-\dfrac{1}{3}-...-\left(\dfrac{1}{3}\right)^7\)
=>\(2S=3-\left(\dfrac{1}{3}\right)^7=3-\dfrac{1}{3^7}=\dfrac{3^8-1}{3^7}\)
=>\(S=\dfrac{3^8-1}{2\cdot3^7}\)
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