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1978x1979 + 1980x21+ 1958 / 1980x1979 - 1978x1979
= 1978x1979+ (1978+2)x21 + 1958 / (1980 - 1978) x 1979
= 1978x1979+ 1978x21+2x21+1958 / 2x1979
= 1978x1979 + 1978x21+ 2000 / 2x1979
= 1978 x (1979 + 21) + 2000 / 1979 x 2
= 1978x 2000+2000 / 1979 x2
= 1978 x 2000+2000 / (1978 +1) x2
= 1978 x 2000+2000/ 1978x2 + 2
= 2000+2000 / 2+2
= 4000 / 4
= 1000
L - i - k - e nha
\(=\frac{1978x1979+\left(1979+1\right)x21+1958}{1979x\left(1980-1978\right)}\)
\(=\frac{1978x1979+1979x21+21+1958}{1979x2}\)
\(=\frac{1978x1979+1979x21+1979}{1979x2}\)
\(=\frac{1979x\left(1978+21+1\right)}{1979x2}\)
\(=\frac{2000}{2}\)(rút gọn 1979 ở cả tử và mẫu)
=1000
a. 2006/2005 x 2007/2006 x 2008/2007 x 2009/2008 x 2010/2009'
= 2006 x 2007 x 2008 x 2009 x 2010 / 2005 x 2006 x 2007 x 2008 x 2009
= 2010/2005
= 402/401
\(\left(1+\frac{1}{2005}\right)x\left(1+\frac{1}{2006}\right)x\left(1+\frac{1}{2007}\right)x\left(1+\frac{1}{2008}\right)x\left(1+\frac{1}{2009}\right)\)
\(=\frac{2006}{2005}x\frac{2007}{2006}x\frac{2008}{2007}x\frac{2009}{2008}x\frac{2010}{2009}\)
\(=\frac{2010}{2005}\)
\(=\frac{402}{401}\)
A/ \(\left(10\frac{3}{4}+3\frac{4}{5}\right)-\left(5\frac{3}{4}-1\frac{1}{5}\right)\)
\(=\left(10\frac{3}{4}-5\frac{3}{4}\right)+\left(3\frac{4}{5}+1\frac{1}{5}\right)\)
\(=5+5\)
\(=10\)
chúc bạn học tốt nha
\(A=\frac{2015+2016+2017}{2014+2015+2016+2017+2018}x1000\)
\(A=\frac{1}{2}x\frac{2}{3}x\frac{3}{4}x...x\frac{2006}{2007}=\frac{1}{2007}\)
k nha bạn
\(x\)là dấu nhân hả bạn? Nếu vậy thì mk làm cho nhé
\(A=\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot....\cdot\left(1-\frac{1}{20}\right)\)
\(A=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot.......\cdot\frac{17}{18}\cdot\frac{18}{19}\cdot\frac{19}{20}=\frac{1}{20}\)
Vậy \(A=\frac{1}{20}\)
\(B=1\frac{1}{2}\cdot1\frac{1}{3}\cdot1\frac{1}{4}\cdot........\cdot1\frac{1}{2005}\cdot1\frac{1}{2006}\cdot1\frac{1}{2007}\)
\(B=\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}\cdot......\cdot\frac{2006}{2005}\cdot\frac{2007}{2006}\cdot\frac{2008}{2007}=\frac{2008}{2}=1004\)
Vậy \(B=1004\)
DẤU CHẤM LÀ DẤU NHÂN
a,
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}....\frac{19}{20}=\frac{1}{20}\)
b, \(1\frac{1}{2}.1\frac{1}{3}....1\frac{1}{2017}=\frac{3}{2}.\frac{4}{3}....\frac{2018}{2017}=\frac{2018}{2}=1009\)
\(A=\frac{2007\cdot\left(2008-1008\right)}{\left(2007-1007\right)+\left(2008-1008\right)}=\frac{2007\cdot1000}{1000+1000}=\frac{2007}{2}\)
\(B=\frac{1978\cdot1979+\left(1979+1\right)\cdot21+\left(1979-21\right)}{1979\cdot\left(1980-1978\right)}=\frac{1979\cdot\left(1978+21\right)}{1979\cdot2}=\frac{1999}{2}\)