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ND
Nguyễn Đăng Nhân
CTVHS
18 tháng 9 2023
a) \(=\left(13\dfrac{2}{7}+2\dfrac{5}{7}\right):\left(-\dfrac{8}{9}\right)\)
\(=16:\dfrac{-8}{9}=\dfrac{-8\cdot\left(-2\right)\cdot9}{-8}=-18\)
b)
\(=\left(\dfrac{-6}{11}\cdot\dfrac{11}{-6}\right)\cdot\dfrac{7\cdot10\cdot\left(-2\right)}{10}\)
\(=-14\)
c) \(=\dfrac{-1}{2}\cdot\dfrac{4}{3}\cdot\dfrac{-7}{2}\)
\(=\dfrac{-1\cdot2\cdot2\cdot\left(-7\right)}{2\cdot3\cdot2}=\dfrac{7}{3}\)
17 tháng 9 2023
\(a.\left[-\dfrac{6}{11}.\dfrac{11}{-6}\right].\dfrac{7}{10}.\left(-20\right)=1.7.\left(-2\right)=-14\)
\(b.\dfrac{-1}{2}:\dfrac{3}{4}.\dfrac{-7}{2}=\dfrac{7}{4}:\dfrac{3}{4}=\dfrac{7}{3}\)
\(c.\dfrac{93}{7}:-\dfrac{8}{9}+\dfrac{19}{7}:\dfrac{-8}{9}=\left(\dfrac{93}{7}+\dfrac{19}{7}\right):-\dfrac{8}{9}=\dfrac{-9}{8}.\dfrac{112}{7}=-18\)
DQ
1
VN
Võ Ngọc Phương
CTVHS
VIP
15 tháng 10 2023
\(\dfrac{4^{10}.9^6+3^{12}.8^5}{6^{13}.4-2^{16}.3^{12}}\)
\(=\dfrac{\left(2^2\right)^{10}.\left(3^2\right)^6+3^{12}.\left(2^3\right)^5}{\left(2.3\right)^{13}.2^2-2^{16}.3^{12}}\)
\(=\dfrac{2^{20}.3^{12}+3^{12}.2^{15}}{2^{13}.3^{13}.2^2-2^{16}.3^{12}}\)
\(=\dfrac{2^{20}.3^{12}+3^{12}.2^{15}}{2^{15}.3^{13}-2^{16}.3^{12}}\)
\(=\dfrac{2^{15}.3^{12}.\left(2^5+1\right)}{2^{15}.3^{13}.\left(3-2\right)}\)
\(=\dfrac{2^5+1}{3-2}\)
\(=\dfrac{32+1}{1}=33\)
ND
Nguyễn Đăng Nhân
CTVHS
1 tháng 10 2023
\(\dfrac{4^5\cdot9^4}{8^3\cdot27^3}=\dfrac{\left(2^2\right)^5\cdot\left(3^2\right)^4}{\left(2^3\right)^3\cdot\left(3^3\right)^3}=\dfrac{2^{10}\cdot3^8}{2^9\cdot3^9}=\dfrac{2}{3}\)
\(\dfrac{4^{20}\cdot3^{35}}{2^{37}\cdot27^{12}}=\dfrac{\left(2^2\right)^{20}\cdot3^{35}}{2^{37}\cdot\left(3^3\right)^{12}}=\dfrac{2^{40}\cdot3^{35}}{2^{37}\cdot3^{36}}=\dfrac{2^3}{3}\)
\(\dfrac{5^4\cdot20^4}{25^5\cdot4^5}=\dfrac{5^4\cdot5^4\cdot4^4}{5^5\cdot5^5\cdot4^5}=\dfrac{1}{5^2\cdot4}=\dfrac{1}{100}\)
\(\dfrac{2^{15}\cdot9^4}{6^6\cdot8^3}=\dfrac{2^{15}\cdot\left(3^2\right)^4}{2^6\cdot3^6\cdot\left(2^3\right)^3}=\dfrac{2^{15}\cdot3^8}{2^6\cdot3^6\cdot2^9}=3^2\)
VD
6 tháng 10 2023
-3^7.2^8/2^.3^7
=-3.2
=-6
5^3.3^5/5^3(0,5+2,5)
=5^3.3^5/5^3.3\
3^4
=81
5.7^4+7^3.25/7^5.125-7^3.50
=5.7^3(7+5
VD
6 tháng 10 2023
5.7^4+7^3.25/7^5.125-7^3.50
=5.7^4+7^3.5^2/7^5.5^3-7^3.11.5
=5.7^3(1.7+1.5)/7^3.5(7^2.25-11)
12/1250
H9
HT.Phong (9A5)
CTVHS
5 tháng 7 2023
a) \(2\cdot31\cdot12+4\cdot6\cdot41+8\cdot28\cdot3\)
\(=24\cdot31+24\cdot41+24\cdot28\)
\(=24\cdot\left(31+41+28\right)\)
\(=24\cdot\left(72+28\right)\)
\(=24\cdot100\)
\(=2400\)
b) \(3,9\cdot\dfrac{13}{10}+\dfrac{0,87}{0,01}\cdot0,39\)
\(=\dfrac{3,9}{10}\cdot13+87\cdot0,39\)
\(=0,39\cdot13+87\cdot0,39\)
\(=0,39\cdot\left(13+87\right)\)
\(=0,39\cdot100\)
\(=39\)
VL
1
F
9 tháng 10 2017
\(\frac{4^{10}.9^6+3^{12}.8^5}{6^{13}.4-2^{16}.3^{12}}\)
\(=\frac{\left(2^2\right)^{10}.\left(3^2\right)^6+3^{12}.\left(2^3\right)^5}{\left(2.3\right)^{13}.2^2-2^{16}.3^{12}}\)
\(=\frac{2^{20}.3^{12}+3^{12}.2^{15}}{2^{13}.3^{13}.2^2-2^{16}.3^{12}}\)
\(=\frac{2^{20}.3^{12}+3^{12}.2^{15}}{2^{15}.3^{12}.3-3^{12}.2^{16}}\)
\(=\frac{2^4}{3}\)
\(\dfrac{4^5.3^{10}+6^8}{8^3.27^3+6^7}\)
\(=\dfrac{2^{10}.3^{10}+6^8}{2^9.3^9+6^7}\)
\(=\dfrac{6^{10}+6^8}{6^9+6^7}\)
\(=\dfrac{6^8.\left(6^2+1\right)}{6^7.\left(6^2+1\right)}\)
\(=6.\)
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