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1. A) 225886 + 779 × 8
= 225886 + 6232
= 232118
B) 125 × 5 × 20 × 8
= (125 × 8) × (5 × 20)
= 1000 × 100
= 100000
C) 47286 : 2 + 14765
= 23643 + 14765
= 38408
D) 91428 - 23560 : 5
= 91428 - 4712
= 86716
3. A) 36 × 532 + 63 × 532 + 532
= 532 × (36 + 63 + 1)
= 532 × 100
= 53200
B) 679 × 123 + 679 - 679 × 24
= 679 × (123 + 1 - 24)
= 679 × 100
= 67900
C) 245 × 327 - 245 × 18 - 9 × 245
= 246 × (327 - 18 - 9)
= 245 × 300
= 73500
( 8/14 + 6/14 ) + ( 5/12 - 1/12 + 8/12 )
= 1 + ( 4/12 + 8/12 )
= 1 + 1 = 2
\(\frac{8}{14}+\frac{5}{12}+\frac{6}{14}+\frac{8}{12}-\frac{1}{12}\)
\(=\left(\frac{8}{14}+\frac{6}{14}\right)+\left(\frac{5}{12}+\frac{8}{12}-\frac{1}{12}\right)\)
\(=1+1\)
\(=2\)
\(\frac{8}{14}+\frac{5}{12}+\frac{6}{14}+\frac{8}{12}-\frac{1}{12}\)
\(=\)\(\left(\frac{8}{14}+\frac{6}{14}\right)+\left(\frac{5}{12}+\frac{8}{12}-\frac{1}{12}\right)\)
\(=\)\(1+1\)
\(=\)\(2\)
3. Tính bằng cách thuận tiện nhất
A, 36 x 532 + 63 x 532 + 532
= (36 + 63 + 1) x 532 = 100 x 532 = 53 200
B, 679 x 123 + 679 - 679 x 24
= 679 x (123 + 1 - 24)
= 679 x 100 = 67 900
C, 245 x 327 - 245 x 18 - 9 x 245
= 245 x (327 - 18 - 9)
= 245 x 300
= 73 500
Bài 2:
a: \(6\cdot\left(x+9845\right)=29042\)
=>\(x+9845=\dfrac{29042}{6}=\dfrac{14521}{3}\)
=>\(x=\dfrac{14521}{3}-9845=-\dfrac{15014}{3}\)
b: \(\left(x:3\right)\cdot8=8\cdot3198\)
=>\(x:3=3198\)
=>\(x=3198\cdot3=9594\)
Bài 1:
a: \(225886+779\cdot8\)
\(=225886+6232\)
\(=232118\)
b: \(125\cdot5\cdot20\cdot8\)
\(=\left(125\cdot8\right)\cdot\left(5\cdot20\right)\)
\(=1000\cdot100=100000\)
c: \(47286:2+14765\)
\(=23643+14765\)
=38408
d: \(91428-23560:5\)
\(=91428-4712\)
=86716
2021 x 31 + 17 x 2021 + 47 x 2021 - 100 x 2021 + 5 x 2021
= 2021 x ( 31 + 17 +47 + 5 - 100 )
= 2021 x 0
= 0 .
N H Ớ T I C K C H O TUI NHA !
~ HT~
\(\dfrac{11}{34}+\dfrac{5}{23}+\dfrac{23}{34}+\dfrac{18}{23}\)
\(=\left(\dfrac{11}{34}+\dfrac{23}{34}\right)+\left(\dfrac{5}{23}+\dfrac{18}{23}\right)\)
\(=1+1\)
\(=2\)
#DatNe
1.
= 10 000 - 29 x 11
= 10 000 - 319
= 9681
2.
= ( 3/7 + 4/7 ) + ( 4/9 + 5/9 )
= 1 + 1
= 2
a) 103 + 91 + 47 + 9
= (103 + 47) + (91 + 9)
= 150 + 100
= 250
Vậy giá trị cần tìmlaf: 250
b) 261 + 192 - 11 + 8
= (261 - 11) + (192 + 8)
= 250 + 200
= 450
Vậy giá trị cần tìm là: 450
a) \(103+91+47+9\)
\(=\left(103+47\right)+\left(91+9\right)\)
\(=150+100\)
\(=250\)
b) \(261+192-11+8\)
\(=\left(261-11\right)+\left(192+8\right)\)
\(=250+200\)
\(=450\)