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a)
= (45 + 55) + (127 + 303)
= 100 + 43= 530
b)
= 127 x (35 + 54 + 1)
= 127 x 90 = 11 430
a)
=(45 + 55) + (127 + 303)
=100 + 500
= 600
b)
= 127 x (35 + 54 + 1)
=127 x 100
= 12700
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a)
`127+246+273+354`
`=(127+273)+(246+354)`
`=400+600`
`=1000`
b)
`1,58+3,04+6,96+3,42`
`=(1,58+3,42)+(3,04+6,96)`
`=5+10`
`=15`
c)
`1/2+1/3+1/5+1/6`
`=(1/2+1/3+1/6)+1/5`
`=(3/6+2/6+1/6)+1/5`
`=6/6+1/5`
`=1+1/5`
`=5/5+1/5`
`=6/5`
a, 127 + 246 + 273 + 354
= ( 127 + 273) + ( 246 + 354)
= 400 + 600
= 1000
b, 1,58 + 3,04 + 6,96 + 3,42
= ( 1,58 + 3,42) + ( 3,04 + 6,96)
= 5 + 10
= 15
c, \(\dfrac{1}{2}\) + \(\dfrac{1}{3}\) + \(\dfrac{1}{5}\) + \(\dfrac{1}{6}\)
= ( \(\dfrac{1}{2}\) + \(\dfrac{1}{3}\) + \(\dfrac{1}{6}\)) + 0,2
= 1 + 0,2
= 1,2
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a, (1 + 3 + 5 + 7+ ... + 2003 + 2005) x (125125 x 127 - 127127 x125)
= (1 + 3 + 5 +...+2003 + 2005) x (125 x 1001 x 127 - 127x1001 x 125)
= (1 + 3 + 5 +...+ 2003 + 2005) x 0
= 0
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Ta cho x : 3 vào trong ngoặc :
Cộng dãy 1 + 3 + 5 + 7 ... + 99 = 2500
Cộng dãy 2 + 4 + 6 + 8 ... + 98 = 2450
( x : 3 ) + 2500 - 2450 = 127
( x : 3 ) + 50 = 127
( x : 3 ) = 127 - 50
x = 77 x 3
x = 231
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5,5 + \(\dfrac{3}{4}\) - 5 + \(\dfrac{1}{4}\)
(5,5 - 5) + (\(\dfrac{3}{4}\) + \(\dfrac{1}{4}\))
= 0,5 + 1
= 1,5
\(\dfrac{5}{2}\) x \(\dfrac{2}{3}\) + \(\dfrac{1}{4}\) : \(\dfrac{3}{2}\)
= \(\dfrac{5}{2}\) x \(\dfrac{2}{3}\) + \(\dfrac{1}{4}\) x \(\dfrac{2}{3}\)
= (\(\dfrac{5}{2}\) + \(\dfrac{1}{4}\)) x \(\dfrac{2}{3}\)
= (\(\dfrac{10}{4}\) + \(\dfrac{1}{4}\)) x \(\dfrac{2}{3}\)
= \(\dfrac{11}{4}\) x \(\dfrac{2}{3}\)
= \(\dfrac{11}{6}\)
Tính \(x\):
435 - [\(x\) + 16] = 425 : 17
435 - [\(x\) + 16] = 25
[\(x\) + 16] = 435 - 25
\(x\) + 16 = 410
\(x\) = 410 - 16
\(x\) = 394
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= 3,8x (2 x 2) x 2 + 3,8 x 8 + 3,8 x (4 x 2) - 46
= 3,8 x 4 + 3,8 x 8 + 3,8 x 8 -46
= 3,8 x (4 + 8+8) - 46
= 3,8 x 20 - 46
= 76 - 46
= 30
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Cách 1:
\(\left(\dfrac{1}{3}+\dfrac{2}{9}\right)\times\dfrac{4}{9}\)
\(=\dfrac{5}{9}\times\dfrac{4}{9}\)
\(=\dfrac{20}{81}\)
Cách 2:
\(\left(\dfrac{1}{3}+\dfrac{2}{9}\right)\times\dfrac{4}{9}\)
\(=\dfrac{1}{3}\times\dfrac{4}{9}+\dfrac{2}{9}\times\dfrac{4}{9}\)
\(=\dfrac{4}{27}+\dfrac{8}{81}\)
\(=\dfrac{20}{81}\)
C1: \(\left(\dfrac{1}{3}+\dfrac{2}{9}\right)\)x\(\dfrac{4}{9}\)=\(\left(\dfrac{3}{9}+\dfrac{2}{9}\right)\text{x}\dfrac{4}{9}\)=\(\dfrac{5}{9}\text{x}\dfrac{4}{9}=\dfrac{20}{81}\)
C2: \(\left(\dfrac{1}{3}+\dfrac{2}{9}\right)\)x\(\dfrac{4}{9}\)=\(\dfrac{1}{3}\text{ x}\dfrac{4}{9}+\dfrac{2}{9}\text{ x}\dfrac{4}{9}\)=\(\dfrac{4}{27}+\dfrac{8}{81}=\dfrac{12}{81}+\dfrac{8}{81}=\dfrac{20}{81}\)
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`#3107.101107`
b)
\(0,5\times\dfrac{3}{4}-\dfrac{1}{2}\times\dfrac{1}{4}\\ =\dfrac{1}{2}\times\dfrac{3}{4}-\dfrac{1}{2}\times\dfrac{1}{4}\\ =\dfrac{1}{2}\times\left(\dfrac{3}{4}-\dfrac{1}{4}\right)\\=\dfrac{1}{2}\times\dfrac{1}{2}\\ =\dfrac{1}{4}\)
C1 : 127 x ( 4 + 2 )
= 127 x 6
= 762
C2:
127 x ( 4 + 2 )
= 127 x 4 + 127 x 2
= 508 + 254
= 762
127x(4+2)=127x6=762
127x(4+2)=127x4+127x2=508+254=762