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Bài 1:
0,5\(x\) - \(\dfrac{2}{3}\)\(x\) = \(\dfrac{7}{12}\)
\(\dfrac{1}{2}\)\(x\) - \(\dfrac{2}{3}x\) = \(\dfrac{7}{12}\)
(\(\dfrac{1}{2}-\dfrac{2}{3}\))\(x\) = \(\dfrac{7}{12}\)
- \(\dfrac{1}{6}\)\(x\) = \(\dfrac{7}{12}\)
\(x\) = \(\dfrac{7}{12}\) : (- \(\dfrac{1}{6}\))
\(x\) = - \(\dfrac{7}{2}\)
Vậy \(x\) = - \(\dfrac{7}{2}\)
a: \(=\dfrac{17}{4}-\dfrac{37}{100}+\dfrac{1}{8}-\dfrac{32}{25}-\dfrac{5}{2}+\dfrac{7}{2}\)
\(=\dfrac{35}{8}+\dfrac{8}{8}-\dfrac{37}{100}-\dfrac{128}{100}\)
\(=\dfrac{43}{8}-\dfrac{165}{100}=\dfrac{149}{40}\)
b: \(=\left(\dfrac{22\cdot26+3\cdot10-65}{130}\right):\left(\dfrac{4\cdot22-2\cdot26+3\cdot143}{286}\right)\)
\(=\dfrac{537}{130}\cdot\dfrac{286}{465}=\dfrac{1969}{775}\)
