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y+yx2+yx3+yx4-566=2015
yx[1+2+3+4]-566=2015
yx10-566=2015
yx10=2015+566
yx10=2581
y=2591:10
y=259,1
a)13/17 < 15/19
a) 2/3 x X + 3/4 = 3
2/3 x X = 3 - 3/4
2/3 x X = 9/4
X = 9/4 : 2/3
X = 27/8
a. Ta có : \(\frac{13}{17}=\frac{247}{323};\frac{15}{19}=\frac{255}{323}\)
Vì 255 > 247 nên 247/323 < 255/323
Hay \(\frac{13}{17}< \frac{15}{19}\)
b. \(\frac{2}{3}\times x+\frac{3}{4}=3\)
\(\frac{2}{3}\times x=3-\frac{3}{4}\)
\(\frac{2}{3}\times x=\frac{9}{4}\)
\(x=\frac{9}{4}:\frac{2}{3}\)
\(x=\frac{27}{8}\)
c. \(720:\left[41-\left(2\times x-5\right)\right]=120\)
\(\left[41-\left(2\times x-5\right)\right]=720:120\)
\(41-\left(2\times x-5\right)=6\)
\(2\times x-5=35\)
\(2\times x=40\)
\(x=20\)
\(\frac{4}{7}+x\times2=\frac{5}{3}\)
\(x\times2=\frac{5}{3}-\frac{4}{7}\)
\(x\times2=\frac{23}{21}\)
\(x=\frac{23}{21}:2\)
\(x=\frac{23}{42}\)
\(\frac{4}{7}+x\times2=\frac{5}{3}\)
\(x\times2=\frac{5}{3}-\frac{4}{7}\)
\(x\times2=\frac{23}{21}\)
\(x=\frac{23}{21}:2\)
\(x=\frac{23}{42}\)
Vậy x = 23/42
a)[ 3 x ( x + 2 ) : 7 ] x 4 = 120
[ 3 x ( x + 2 ) : 7 ] = 120 : 4
[ 3 x ( x + 2 ) : 7 ] = 30
3 x ( x + 2 ) = 30 x 7.
3 x ( x + 2 ) = 210
( x + 2 ) = 210 : 3
( x + 2 ) = 70
=>x = 70 ‐ 2
x =68
b) 2480 - 720 : 3 + [200 - (x - 5)] = 1010
<=>2240 + 200 - (x-5) =1010
<=> -x+5 =-1430
<=> -x = -1435
<=> x =1435
NHỚ TK MK NHA
a)[ 3 x ( x + 2 ) : 7 ] x 4 = 120
[ 3 x ( x + 2 ) : 7 ] = 120 : 4
[ 3 x ( x + 2 ) : 7 ] = 30
3 x ( x + 2 ) = 30 x 7.
3 x ( x + 2 ) = 210
( x + 2 ) = 210 : 3
( x + 2 ) = 70
=>x = 70 ‐ 2
x =68
b) 2480 - 720 : 3 + [200 - (x - 5)] = 1010
<=>2240 + 200 - (x-5) =1010
<=> -x+5 =-1430
<=> -x = -1435
<=> x =1435
NHỚ TK MK NHA