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\(\Rightarrow\left[3\left(x+1\right)+8\right]⋮\left(x+1\right)\\ \Rightarrow x+1\inƯ\left(8\right)=\left\{-8;-4;-2;-1;1;2;4;8\right\}\\ \Rightarrow x\in\left\{-9;-5;-3;-2;0;1;3;7\right\}\)
Pikachu đơn giản thì làm thử đừng nói mà ko làm nha ^_^
duyệt đi
câu đầu bạn dưới làm rồi nên mình k làm lại
(2x+9)2=0
=> 2x+9=0
=> 2x=-9
=> x=-9/2
(2x-1)3=8
=> 2x-1=2
=> 2x=3
=> x=3/2
(1-3x)2=16
=> 1-3x=4
=> 3x=-3
=> x=-1
(3x+1)+1=-26
=> 3x=-27
=> x=-9
(x+1)+(x+3)+(x+5)+...+(x+2017)=0
(x+x+x+...+x)+(1+3+5+...+2017)=0
=> 1009x+1018081=0
1009x=-1018081
=> x=-1009
A. 5(x-11) + 4(x-3) =10
<=>5x -55 + 4x -12 =10
<=>9x -67 =10
<=>9x =10+67 =77
<=>x =77 : 9 =77/9
B.21 - 5 ( x-7) = 2-3(x-5)
<=>21-5x+35 = 2 - 3x +15
<=>-5x + 56 = -3x + 17
<=>-5x +3x=17-56=-39
<=> -2x =-39
<=> x = -39 : -2 =39/2
C.3(2x-1)-7(x+4)=8-9x
<=>6x -4 -7x-28=-9x+8
<=>-x + 9x = 8+4+28=40
<=> 8x = 40
<=> x = 40:8=5
D. l 4-x l =11
<=>\(\orbr{\begin{cases}4-x=11\\4-x=-11\end{cases}}\)<=> \(\orbr{\begin{cases}x=-7\\x=15\end{cases}}\)
E. 5-3 l x+2 l = -28
<=> 3 l x+2 L = -28 -5 =-33
<=> l x+2 l = -33 :3 =11
<=>\(\orbr{\begin{cases}x+2=11\\x+2=-11\end{cases}}\)<=> \(\orbr{\begin{cases}x=9\\-13\end{cases}}\)
T I C K mk nhé!!!^_^
\(A=7+9+11+...+99\)(có (99-7):2+1=47 số hạng)
\(A=\frac{47\left(99+7\right)}{2}=\frac{47\cdot106}{2}=47\cdot53=2491\)
\(B=10+15+20+...+200\)(có (200-10):5+1=39 số hạng)
\(B=\frac{39\left(200+10\right)}{2}=\frac{39\cdot210}{2}=39\cdot105=18585\)
Câu 1:
a) Ư(-12)={1;-1;2;-2;3;-3;4;-4;6;-6;12;-12}
b) B(-4)={0;-4;-8;4;8;...}
Câu 2:
a) Ta có: \(x-15=11-\left(-32\right)\)
\(\Leftrightarrow x-15=11+32\)
\(\Leftrightarrow x=43+15=58\)
Vậy: x=58
b) Ta có: \(13-\left(5-x\right)=7\)
\(\Leftrightarrow13-5+x=7\)
\(\Leftrightarrow x+8=7\)
hay x=-1
Vậy: x=-1
c) Ta có: \(x-\dfrac{3}{5}=5.12\)
\(\Leftrightarrow x-0.6=5.12\)
hay x=5,72
Vậy: x=5,72
d) Ta có: \(\dfrac{x+1}{-2}=\dfrac{-8}{x+1}\)
\(\Leftrightarrow\left(x+1\right)^2=\left(-2\right)\cdot\left(-8\right)=16\)
\(\Leftrightarrow\left[{}\begin{matrix}x+1=4\\x+1=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)
Vậy: \(x\in\left\{3;-5\right\}\)
`@` `\text {Ans}`
`\downarrow`
`a)`
\(\left(\dfrac{x}{2}-1\right)^3+2=-\dfrac{11}{8}\) phải k bạn nhỉ? `11/8` k có bậc lũy thừa nào `=5` á.
`=>`\(\left(\dfrac{x}{2}-1\right)^3=-\dfrac{11}{8}-2\)
`=>`\(\left(\dfrac{x}{2}-1\right)^3=-\dfrac{27}{8}\)
`=>`\(\left(\dfrac{x}{2}-1\right)^3=\left(-\dfrac{3}{2}\right)^3\)
`=>`\(\dfrac{x}{2}-1=-\dfrac{3}{2}\)
`=>`\(\dfrac{x}{2}=-\dfrac{3}{2}+1\)
`=>`\(\dfrac{x}{2}=-\dfrac{1}{2}\)
`=> x=1`
Vậy, `x=1`
`b)`
\(\left(\dfrac{x}{3}+\dfrac{1}{2}\right)\left(75\%-1\dfrac{1}{2}\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}\dfrac{x}{3}+\dfrac{1}{2}=0\\0,75-1\dfrac{1}{2}x=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}\dfrac{x}{3}=-\dfrac{1}{2}\\-\dfrac{3}{2}x=\dfrac{75}{100}\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}2x=-3\\-3x\cdot100=2\cdot75\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=-\dfrac{3}{2}\\-3x\cdot100=150\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=-\dfrac{3}{2}\\-3x=1,5\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=-\dfrac{3}{2}\\x=-\dfrac{1}{2}\end{matrix}\right.\)
Vậy, `x={-3/2; -1/2}.`
\(a)\)
\(x+\frac{1}{10}+x+\frac{11}{11}=x+\frac{11}{12}\)
\(\Leftrightarrow x=\frac{11}{12}-\frac{1}{10}-\frac{11}{11}\)
\(\Leftrightarrow x=\frac{-11}{60}\)
\(b)\)
\(-\left|x-\frac{1}{2}\right|=\frac{1}{2}\)
\(\Leftrightarrow\left|x-\frac{1}{2}\right|=\frac{-1}{2}\) (Vô lý)
Vậy \(x\in\varnothing\)