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Theo bài ra ta có,hiệu của tử và mẫu là: 24.2=48 Tử là:(210-48):2=81 Mẫu là:210-81=129 Vậy phân số cần tìm là:81/129
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Đây là toán CẤP 1, bạn không được sử dụng cách giải "Giải bài toán bằng cách lập phương trình" của chương trình lớp 8.
Giả sử số cần tìm là x. Theo đó, phép tính trên có thể được biểu diễn như sau:
(32 - x)/(24 + x) = 3/5
Để giải phương trình này, ta có thể sử dụng phương pháp giải tương đương:
5(32 - x) = 3(24 + x)
160 - 5x = 72 + 3x
8x = 88
x = 11
Vậy, số cần tìm là 11.
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Gọi n là thương của phép chia cho 26, ta được:
26 x n + 5 = 24 x (n+2) + 5 = 24 x n + 48 + 5
2 x n = 48
n = 48 : 2 = 24
Số cần tìm là:
26 x 24 + 5 = 629
Đáp số:629
Ai tích mình mình tích lại cho(đi mà)
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Tử số là :
24 : ( 5 - 2 ) x 2 = 16
Mẫu số là :
24 + 16 = 40
Vậy phân số đó là \(\frac{16}{40}\)
Giải
Hiệu số phần bằng nhau là:
5-2=3(phần)
Tử số của phân số đó là:
24:3*2=16
Mẫu của phân số đó là:
16+24=40
Vậy phân số đó là 16/40
Đáp số:16/40
\(\frac{1}{5}\)số đó là 24
\(\Rightarrow\)số đó là:
24 * 5 = 120
Số đó là : 24 : 1/5 = 120
Đáp số : 120