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\(\frac{6^3+3.6^2+3^3}{-13}=\frac{3^3\left(8+4+1\right)}{-13}=\frac{27.13}{-13}=-27\)
\(=\frac{2^3.3^3+3^3.2^2+3^3}{-13}=\frac{3^3\left(2^3+2^2+1\right)}{-13}=\frac{3^3.13}{-13}=-3^3=-27\)
\(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}=\frac{\left(0,2\right)^5\cdot3^5}{\left(0,2\right)^6}=\frac{3^5}{0.2}=243:\frac{1}{5}=1215\)
\(\frac{2^7\cdot9^3}{6^5\cdot8^2}=\frac{2^7\cdot\left(3^2\right)^3}{2^5\cdot3^5\cdot\left(2^3\right)^2}=\frac{2^7\cdot3^6}{2^{11}\cdot3^5}=\frac{3}{2^4}=\frac{3}{16}\)
câu cuối ko bt
Xin lỗi vì đã ns dối, ko phải tớ ko bt giải mà là tại mama kêu ghê quá nên ko kịp viết lời giải câu cuối 
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\(\frac{6^3+3\cdot6^2+3^3}{-13}=\frac{2^3\cdot3^3+3\cdot2^2\cdot3^2+3^3}{-13}=\frac{2^3\cdot3^3+3^3\cdot2^2+3^3}{-13}=\frac{3^3\left(2^3+2^2+1\right)}{-13}=\frac{27\cdot13}{-13}=-27\)
\(\begin{array}{l}a)\left( {\frac{2}{3} + \frac{1}{6}} \right):\frac{5}{4} + \left( {\frac{1}{4} + \frac{3}{8}} \right):\frac{5}{2}\\ = \left( {\frac{4}{6} + \frac{1}{6}} \right).\frac{4}{5} + \left( {\frac{2}{8} + \frac{3}{8}} \right).\frac{2}{5}\\ = \frac{5}{6}.\frac{4}{5} + \frac{5}{8}.\frac{2}{5}\\ = \frac{2}{3} + \frac{1}{4}\\ = \frac{8}{{12}} + \frac{3}{{12}}\\ = \frac{{11}}{{12}}\\b)\frac{5}{9}:\left( {\frac{1}{{11}} - \frac{5}{{22}}} \right) + \frac{7}{4}.\left( {\frac{1}{{14}} - \frac{2}{7}} \right)\\ = \frac{5}{9}:\left( {\frac{2}{{22}} - \frac{5}{{22}}} \right) + \frac{7}{4}.\left( {\frac{1}{{14}} - \frac{4}{{14}}} \right)\\ = \frac{5}{9}:\frac{{ - 3}}{{22}} + \frac{7}{4}.\frac{{ - 3}}{{14}}\\ = \frac{5}{9}.\frac{{ - 22}}{3} + \frac{{ - 3}}{8}\\ = \frac{{ - 110}}{{27}} + \frac{{ - 3}}{8}\\ = \frac{{ - 880}}{{216}} + \frac{{ - 81}}{{216}}\\ = \frac{{ - 961}}{{216}}\end{array}\)
E = \(\frac{\left(2^2\right)^6.\left(3^2\right) ^5+\left(2.3\right)^9.2^3.3.5}{-\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)
E = \(\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{-2^{12}.3^{12}-2^{11}.3^{11}}\)
E = \(\frac{2^{12}.3^{10}+2^{13}.3^{10}.5}{-2^{11}.3^{11}.\left(2.3+1\right)}\)
E = \(\frac{2^{12}.3^{10}.\left(1+5\right)}{-2^{11}.3^{11}.7}\)
E = \(\frac{2^{12}.3^{10}.6}{-2^{11}.3^{11}.7}\)
E=\(\frac{-2^{11}.\left(-2\right).3^{10}.6}{-2^{11}.3^{10}.3.7}\)
E = \(\frac{-2.6}{3.7}=-\frac{4}{7}\)
Vậy E = -4/7
Ý F bn lm tương tự nha
63 + 3 . 62 + 33 / -13
= 23 . 33 + 3 . 22 . 32 + 33 / -13
= 33 . 8 + 33 . 4 + 33 / -13
= 33 . (8 + 4 + 1) / -13
= 27 . 13 / -13
= -27
a) \(\frac{4^2.4^3}{2^{10}}=\frac{\left(2^2\right)^2.\left(2^2\right)^3}{2^{10}}=\frac{2^4.2^6}{2^{10}}=\frac{2^{10}}{2^{10}}=1\)
b) \(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}=\frac{\left(0,2.3\right)^5}{\left(0,2\right)^6}=\frac{3^5.0,2^5}{0,2^6}=\frac{3^5}{0,2}=\frac{243}{0,2}=1215\)
c) \(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{2^5.3^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3}{2^{11}}=\frac{3}{2^4}=\frac{3}{16}\)
d) \(\frac{6^3+3.6^2+3^3}{-13}=\frac{6^2\left(6+3\right)+3^3}{-13}=\frac{6^2.9+3^2}{-13}=\frac{3^2\left(6^2+1\right)}{-13}=\frac{9.37}{-13}=\frac{333}{-13}\)
a,\(\frac{4^2.4^3}{2^{10}}=\frac{4^5}{2^{10}}=\frac{4^5}{4^5}=1\)
\(\frac{\left(0.6\right)^5}{\left(0.2\right)^6}=1215\)
còn lại làm đc mà
a) \(\frac{2^7}{6^5}\times\frac{9^3}{8^8}=\frac{2^7}{2^5\times3^5}\times\frac{3^6}{2^{24}}=\frac{2^7\times3^6}{2^{29}\times3^5}=\frac{3}{4194304}\)
b) \(\frac{6^3+3\times6^2+3^3}{-13}=\frac{2^3\times3^3+3\times2^2\times3^2+3^3}{-13}=\frac{3^3\left(2^3+2^2+1\right)}{-13}=\frac{27\times13}{-13}=-27\)