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`@` `\text {Ans}`
`\downarrow`
`(x-3)^2 - x^2 + 10x - 7`
`= x^2 - 6x + 9 - x^2 + 10x - 7`
`= (x^2 - x^2) + (-6x + 10x) + (9-7)`
`= 4x + 2`
\(\left(x-3\right)^2-x^2+10x-7\)
\(=\left(x^2-6x+9\right)-x^2+10x-7\)
\(=\left(x^2-x^2\right)-\left(6x-10x\right)+\left(9-7\right)\)
\(=4x+2\)
\(=2\left(2x+1\right)\)
\(\left(x-\dfrac{1}{2}\right)^3=81=\left(\sqrt[3]{81}\right)^3\)
\(\Leftrightarrow x-\dfrac{1}{2}=\sqrt[3]{81}\)
\(\Leftrightarrow x=\sqrt[3]{81}+\dfrac{1}{2}\)
`#3107.101107`
`(x - 1/2)^2 = 81?`
`=> (x - 1/2)^2 = (+-9)^2`
`=>`\(\left[{}\begin{matrix}x-\dfrac{1}{2}=9\\x-\dfrac{1}{2}=-9\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=9+\dfrac{1}{2}\\x=-9+\dfrac{1}{2}\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=\dfrac{19}{2}\\x=-\dfrac{17}{2}\end{matrix}\right.\)
Vậy, `x \in {-17/2; 19/2}.`
27x : 3x = 9
( 33 ) : 3x = 32
33 - x = 32
3 - x = 2
x = 1
Vậy x = 1
\(\begin{array}{l}x.(2x + 3)\\ = x.2x + 3.x\\ = 2{x^2} + 3x\end{array}\)
a)
\(-7x^2\left(3x-4y\right)\)
\(=-21x^3+28x^2y\)
b)
\(\left(x-3\right)\left(5x-4\right)\)
\(=x\left(5x-4\right)-3\left(5x-4\right)\)
\(=5x^2-4x-15x+12\)
\(=5x^2-\left(4x+15x\right)+12\)
\(=5x^2-19x+12\)
a: =-7x^2*3x+7x^2*4y
=-21x^3+28x^2y
b: =5x^2-4x-15x+12
=5x^2-19x+12
`!`
`(x^3-3x^2):(x-3)`
`= x^2(x-3) :(x-3)`
`=x^2`
`----`
`(2x^2+2x-4):(x+2)`
`=2(x^2+x-2) :(x+2)`
`= 2 (x^2+2x-x-2) :(x+2)`
\(=2\left[x\left(x+2\right)-\left(x+2\right)\right]:\left(x+2\right)\)
`= 2(x+2)(x-1) :(x+2)`
`=2(x-1)`
`-------`
`(x^4-x-14):(x-2)`
https://hoc24.vn/cau-hoi/x4-x-14-x-2-giup-minh.204306769717
bn tham khảo ở đây nha
`----`
`(x^3-3x^2+x-3):(x-3)`
`= x^2(x-3) +(x-3) :(x-3)`
`=(x-3)(x^2+1):(x-3)`
`=x^2+1`
(\(x\) - 3).(3 + \(x\))
= 3\(x\) + \(x^2\) - 9 - 3\(x\)
= \(x^2\) - 9
\(\left(x-3\right)\left(3+x\right)\\ =\left(x-3\right).3+\left(x-3\right).x\\ =3x-9+2x-3x\\ =3x-9-x\\ =3x-x+9\\ =2x+9.\)