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a: 3/8=36/96
5/12=40/96
b: -2/9=-24/108
-5/12=-45/108
c: -3/16=-63/336
-5/24=-70/336
-21/56=-126/336
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a) \(\dfrac{-1}{20}=\dfrac{-7}{140}\)
\(\dfrac{5}{7}=\dfrac{100}{140}\)
mà -7<100
nên \(-\dfrac{1}{20}< \dfrac{5}{7}\)
b) \(\dfrac{216}{217}< 1\)
\(1< \dfrac{1164}{1163}\)
nên \(\dfrac{216}{217}< \dfrac{1164}{1163}\)
c) \(\dfrac{-12}{17}=\dfrac{-180}{255}\)
\(\dfrac{-14}{15}=\dfrac{-238}{255}\)
mà -180>-238
nên \(-\dfrac{12}{17}>\dfrac{-14}{15}\)
d) \(\dfrac{27}{29}>0\)
\(0>-\dfrac{2727}{2929}\)
nên \(\dfrac{27}{29}>-\dfrac{2727}{2929}\)
\(a,\dfrac{13}{14}\cdot\dfrac{-7}{8}+\dfrac{-3}{2}\)
\(=-\dfrac{13}{16}+\dfrac{-3}{2}\)
\(=-\dfrac{13}{16}+\dfrac{-24}{16}\)
\(=-\dfrac{37}{16}\)
\(b,\dfrac{5}{17}+\dfrac{-15}{34}\cdot\dfrac{2}{5}\)
\(=\dfrac{5}{17}+\dfrac{-3}{17}\)
\(=\dfrac{2}{17}\)
\(c,\dfrac{1}{5}:\dfrac{1}{10}-\dfrac{1}{3}\cdot\left(\dfrac{6}{5}-\dfrac{2}{4}\right)\)
\(=2-\dfrac{1}{3}\cdot\dfrac{7}{10}\)
\(=2-\dfrac{7}{30}\)
\(=\dfrac{53}{30}\)
\(d,\dfrac{-3}{4}:\left(\dfrac{12}{-5}-\dfrac{-7}{10}\right)\)
\(=\dfrac{-3}{4}:\dfrac{-17}{10}\)
\(=\dfrac{15}{34}\)
a: \(A=\dfrac{-7}{28}\cdot\dfrac{15}{25}=\dfrac{-1}{4}\cdot\dfrac{3}{5}=\dfrac{-3}{20}\)
b: \(B=\dfrac{-5\cdot7}{14\cdot\left(-3\right)}=\dfrac{35}{42}=\dfrac{5}{6}\)
c: \(C=\dfrac{-1}{5}-\dfrac{1}{5}\cdot\dfrac{3}{5}=\dfrac{-1}{5}-\dfrac{3}{25}=\dfrac{-8}{25}\)
d: \(D=\dfrac{-3}{4}-\dfrac{1}{4}=-1\)
e: \(E=\dfrac{-4}{5}\left(1-\dfrac{15}{16}\right)=\dfrac{-4}{5}\cdot\dfrac{1}{16}=\dfrac{-1}{20}\)
f: \(F=\dfrac{6-7}{4}\cdot\dfrac{4+12}{22}=\dfrac{-1}{4}\cdot\dfrac{8}{11}=\dfrac{-2}{11}\)
a) \(-\dfrac{5}{14}=-\dfrac{5.3}{14.3}=-\dfrac{15}{42}\)
\(\dfrac{1}{-21}=-\dfrac{1}{21}=-\dfrac{1.2}{21.2}=-\dfrac{2}{42}\)
b) \(\dfrac{17}{60}=\dfrac{17.3}{60.3}=\dfrac{51}{180}\)
\(\dfrac{-5}{18}=\dfrac{-5.10}{18.10}=-\dfrac{50}{180}\)
\(-\dfrac{64}{90}=-\dfrac{64.2}{90.2}=-\dfrac{128}{180}\)
a)-5/14 và 1/-21
-5/14=-5.-21/14.-2=105/-28
a: \(=\dfrac{1}{3}\cdot\dfrac{1}{3}\cdot\dfrac{-17}{18}\cdot\dfrac{14}{17}=\dfrac{-14}{18\cdot9}=\dfrac{-14}{162}=\dfrac{-7}{81}\)
b: \(=\dfrac{12}{4}+\dfrac{35}{11}\cdot\dfrac{121}{245}=3+\dfrac{11}{7}=\dfrac{32}{7}\)
a: \(=\dfrac{15}{135}\cdot\dfrac{-17}{18}\cdot\dfrac{14}{17}=\dfrac{1}{9}\cdot\dfrac{-7}{9}=\dfrac{-7}{81}\)
b: \(=3+\dfrac{35}{11}\cdot\dfrac{121}{245}=3+\dfrac{11}{7}=\dfrac{32}{7}\)
\(\dfrac{-14}{21};\dfrac{-2}{15};\dfrac{14}{-35}\)
\(\dfrac{-17}{21}=\dfrac{-85}{105}\);\(\dfrac{-2}{15}=\dfrac{-14}{105};\dfrac{14}{-35}=\dfrac{-14}{35}=\dfrac{-42}{105}\)
\(\dfrac{17}{60};\dfrac{5}{12};\dfrac{64}{90}\)
\(\dfrac{17}{60}=\dfrac{51}{180};\dfrac{-5}{12}=\dfrac{-75}{180};\dfrac{-64}{90}=\dfrac{-32}{45}=\dfrac{-128}{180}\)
bài2:
a)\(\dfrac{3}{5}>\dfrac{4}{7}\)
b)\(\dfrac{-5}{8}< \dfrac{-7}{12}\)
c)\(\dfrac{5}{-3}< \dfrac{-9}{12}\)