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giúp mình với ban ơi (っ◔◡◔)っ ♥ Aurora ♥

⭐Hannie⭐ · Accepted Answer

`!``a, x+1/2=3/4``=>x=3/4-1/2``=>x=3/4-2/4``=>x=1/4``b, -2/3-x=1``=> x=-2/3-1``=>x=-2/3 -3/3``=>x=-5/3``c, (x-1/2)+3/5=1/5``=>x-1/2=1/5-3/5``=>x-1/2=-2/5``=>x=-2/5+1/2``=>x= 1/10``d, 1/4+3/4 :x=5/2``=> 3/4 :x=5/2-1/4``=> 3/4 :x=9/4``=>x= 3/4 : 9/4``=>x= 3/4 . 4/9``=>x= 1/3``e, (x+1/4).3/4=-5/8``=> x+1/4=-5/8 : 3/4``=> x+1/4=-5/8 . 4/3``=> x+1/4=-5/6``=>x=-5/6 -1/4``=>x= -13/12``f, x/(-24) =2/3``=> 3x=2.(-24)``=> 3x=-48``=>x=-48:3``=>x= -16`Bn tách ra nữa nha , nhiều quá áCâu trả lời: `!``a, x+1/2=3/4``=>x=3/4-1/2``=>x=3/4-2/4``=>x=1/4``b, -2/3-x=1``=> x=-2/3-1``=>x=-2/3 -3/3``=>x=-5/3``c, (x-1/2)+3/5=1/5``=>x-1/2=1/5-3/5``=>x-1/2=-2/5``=>x=-2/5+1/2``=>x= 1/10``d, 1/4+3/4 :x=5/2``=> 3/4 :x=5/2-1/4``=> 3/4 :x=9/4``=>x= 3/4 : 9/4``=>x= 3/4 . 4/9``=>x= 1/3``e, (x+1/4).3/4=-5/8``=> x+1/4=-5/8 : 3/4``=> x+1/4=-5/8 . 4/3``=> x+1/4=-5/6``=>x=-5/6 -1/4``=>x= -13/12``f, x/(-24) =2/3``=> 3x=2.(-24)``=> 3x=-48``=>x=-48:3``=>x= -16`Bn tách ra nữa nha , nhiều quá á

⭐Hannie⭐ · Answer

`!``g, (x-3)/15=-2/5``=> (x-3).5= 15.(-2)``=> (x-3).5= -30``=>x-3=-30:5``=>x-3=-6``=>x=-6+3``=>x=-3``h, x/(-2)=-8/x``=> x.x=-2.(-8)``=>x^2 =16`$\Rightarrow x=\left[{}\begin{matrix}4\-4\end{matrix}\right.$`i, (x+3)/4 =16/(x+3)``=> (x+3)^2 =4.16``=> (x+3)^2 = 64``=> (x+3)^2 = +-8^2`$\Rightarrow\left[{}\begin{matrix}x+3=8\x+3=-8\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}x=5\x=-11\end{matrix}\right.$`k, (x+2)/3=(x-3)/5``=> (x+2).5 = 3(x-3)``=> 5x+10 = 3x-9``=> 5x-3x=9-10``=> 2x= -1``=>x=-1/2``m, (2x-1)^2=4``=>  (2x-1)^2= +-2^2`$\Rightarrow\left[{}\begin{matrix}2x-1=2\2x-1=-2\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}2x=3\2x=-1\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\x=-\dfrac{1}{2}\end{matrix}\right.$`p, (x+1/3)^2=4/9``=> (x+1/3)^2=(+- 2/3)^2`$\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=\dfrac{2}{3}\x+\dfrac{1}{3}=-\dfrac{2}{3}\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\x=-1\end{matrix}\right.$`q , (x-2)(2x-1)=0``@ TH1``x-2=0``=>x=0+2``=>x=2``@ TH2``2x-1=0``=>2x=0+1``=>2x=1``=>x=1/2``r, (2/3x +1/2)(-2x+3)=0``@ TH1``2/3x+1/2=0``=>2/3x=0-1/2``=>2/3x=-1/2``=>x=-1/2 : 2/3``=>x= -1/12``@ TH2``-2x+3=0``=> -2x=0-3``=>-2x=-3``=>x=3/2``s, (x^2 - 1 9/16 )(x^3+1/8)=0``@ TH1``x^2 -1 9/16=0``=>x^2 - 25/16=0``=>x^2=25/16``=>x^2=(+- 5/4)^2``=> x=(+-5/4)``@ TH2``x^3+1/8=0``=>x^3=1/8``=>x^3= (1/2)^3``=>x=1/2` Câu trả lời: `!``g, (x-3)/15=-2/5``=> (x-3).5= 15.(-2)``=> (x-3).5= -30``=>x-3=-30:5``=>x-3=-6``=>x=-6+3``=>x=-3``h, x/(-2)=-8/x``=> x.x=-2.(-8)``=>x^2 =16`$\Rightarrow x=\left[{}\begin{matrix}4\-4\end{matrix}\right.$`i, (x+3)/4 =16/(x+3)``=> (x+3)^2 =4.16``=> (x+3)^2 = 64``=> (x+3)^2 = +-8^2`$\Rightarrow\left[{}\begin{matrix}x+3=8\x+3=-8\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}x=5\x=-11\end{matrix}\right.$`k, (x+2)/3=(x-3)/5``=> (x+2).5 = 3(x-3)``=> 5x+10 = 3x-9``=> 5x-3x=9-10``=> 2x= -1``=>x=-1/2``m, (2x-1)^2=4``=>  (2x-1)^2= +-2^2`$\Rightarrow\left[{}\begin{matrix}2x-1=2\2x-1=-2\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}2x=3\2x=-1\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\x=-\dfrac{1}{2}\end{matrix}\right.$`p, (x+1/3)^2=4/9``=> (x+1/3)^2=(+- 2/3)^2`$\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=\dfrac{2}{3}\x+\dfrac{1}{3}=-\dfrac{2}{3}\end{matrix}\right.$$\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\x=-1\end{matrix}\right.$`q , (x-2)(2x-1)=0``@ TH1``x-2=0``=>x=0+2``=>x=2``@ TH2``2x-1=0``=>2x=0+1``=>2x=1``=>x=1/2``r, (2/3x +1/2)(-2x+3)=0``@ TH1``2/3x+1/2=0``=>2/3x=0-1/2``=>2/3x=-1/2``=>x=-1/2 : 2/3``=>x= -1/12``@ TH2``-2x+3=0``=> -2x=0-3``=>-2x=-3``=>x=3/2``s, (x^2 - 1 9/16 )(x^3+1/8)=0``@ TH1``x^2 -1 9/16=0``=>x^2 - 25/16=0``=>x^2=25/16``=>x^2=(+- 5/4)^2``=> x=(+-5/4)``@ TH2``x^3+1/8=0``=>x^3=1/8``=>x^3= (1/2)^3``=>x=1/2`

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