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Chú ý rằng trong tích có thừa số 196-142
Mà 196-142=196-196=0
Vậy tích bằng 0
Trả lời:
\(\left(196-1^2\right).\left(196-2^2\right).....\left(196-25^2\right)\)
\(=\left(196-1^2\right).\left(196-2^2\right).....\left(196-14^2\right).....\left(196-25^2\right)\)
\(=\left(196-1^2\right).\left(196-2^2\right).....\left(196-196\right).....\left(196-25^2\right)\)
\(=\left(196-1^2\right).\left(196-2^2\right).....0.\left(196-25^2\right)\)
\(=0\)
Hok tốt!
Good girl
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Số số hạng:
(200 - 20) : 2 + 1 = 91 (số)
20 + 22 + 24 + ... + 196 + 198 + 200
= (200 + 20) . 91 : 2
= 10010
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![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{\frac{2}{3}-\frac{1}{4}+\frac{5}{11}}{\frac{5}{12}+1-\frac{7}{11}}=\frac{\frac{2.14-33+5.12}{132}}{\frac{5.11+312-84}{132}}=\frac{2.14-33+5.12}{5.11+312-84}=\frac{115}{103}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(D=\left(196-1^2\right)\left(196-2^2\right)\left(196-3^2\right)...\left(196-19^2\right)\) \(D=\left(196-1^2\right)\left(196-2^2\right)\left(196-3^2\right)...\left(196-14^2\right)...\left(196-19^2\right)\) \(D=\left(196-1^2\right)\left(196-2^2\right)\left(196-3^2\right)...0...\left(196-19^2\right)\) \(D=0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
A = 196/197 + 197/198 > 196/197+198 + 197/197+198
A > 196 + 197/197 + 198
A > B
\(\left(196-1^2\right).\left(196-2^2\right)....\left(196-20^2\right)\)
ta có \(196=14^2\)
Mà Trong biểu thức trên có hiệu là (196-\(14^2\))
=> Biểu thức trên = 0
mình nghĩ thế
Trả lời:
\(\left(196-1^2\right).\left(196-2^2\right).....\left(196-20^2\right)\)
\(=\left(196-1^2\right).\left(196-2^2\right).....\left(196-14^2\right).....\left(196-20^2\right)\)
\(=\left(196-1^2\right).\left(196-2^2\right).....\left(196-196\right).....\left(196-20^2\right)\)
\(=\left(196-1^2\right).\left(196-2^2\right).....0.\left(196-20^2\right)\)
\(=0\)
Hok tốt!
Good girl