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\(=\frac{432x2x48-432x96}{846x48x432}\)
\(=\frac{432x96-432x96}{846x48x432}\)
\(=\frac{0}{846x48x432}\)
\(=0\)
\(\frac{864\cdot48-432\cdot96}{864\cdot48\cdot432}\)
\(=\frac{432\cdot2\cdot48-432\cdot96}{864\cdot48\cdot432}\)
\(=\frac{432\cdot96-432\cdot96}{864\cdot48\cdot432}\)
\(=\frac{96\cdot\left(432-432\right)}{864\cdot48\cdot432}\)
\(=0\)
864.48-432.96/864.48-432
= ( 864.48)-(432.96) / ( 864.48)-(432.1)
= 41472-41472 / 40608 - 432
= 0/ 40376
= 0
\(\frac{864.48-432.96}{864.48+432}\)
\(=\frac{864.48-432.2.48}{864.48+432}\)
\(=\frac{864.48-864.48}{864.48+432}\)
\(=\frac{0}{864.48+432}\)
\(=0\)
Học tốt
\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}=\frac{32}{64}+\frac{16}{64}+\frac{8}{64}+\frac{4}{64}+\frac{2}{32}+\frac{1}{64}\)
\(\frac{32+16+8+4+2}{64}=\frac{62}{64}=\frac{31}{32}\)
Tk mh nhé , mơn nhìu !!!
~ HOK TỐT ~
\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\)\(+\frac{1}{64}\)
= 32/64 + 16/64 + 8/64 + 4/64 + 2/64 + 1/64
= 63/64
Đặt \(A=\frac{7}{1\cdot5}+\frac{7}{5\cdot9}+\frac{7}{9\cdot13}+\frac{7}{13\cdot17}+\frac{7}{17\cdot21}\)
\(\frac{4}{7}A=\frac{4}{7}\left(\frac{7}{1\cdot5}+\frac{7}{5\cdot9}+\frac{7}{9\cdot13}+\frac{7}{13\cdot17}+\frac{7}{17\cdot21}\right)\)
\(\frac{4}{7}A=\frac{4}{1\cdot5}+\frac{4}{5\cdot9}+\frac{4}{9\cdot13}+\frac{4}{13\cdot17}+\frac{4}{17\cdot21}\)
\(\frac{4}{7}A=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{13}-\frac{1}{17}+\frac{1}{17}-\frac{1}{21}\)
\(\frac{4}{7}A=1-\frac{1}{21}\)
\(\frac{4}{7}A=\frac{20}{21}\)
\(A=\frac{20}{21}:\frac{4}{7}=\frac{20}{21}\cdot\frac{7}{4}=\frac{5}{3}\)
Đặt biểu thức trên là A
\(\frac{4xA}{7}=\frac{4}{1x5}+\frac{4}{5x9}+\frac{4}{9x13}+\frac{4}{13x17}+\frac{4}{17x21}\)
\(\frac{4xA}{7}=\frac{5-1}{1x5}+\frac{9-5}{5x9}+\frac{13-9}{9x13}+\frac{17-13}{13x17}+\frac{21-17}{17x21}\)
\(\frac{4xA}{7}=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{13}-\frac{1}{17}+\frac{1}{17}-\frac{1}{21}\)
\(\frac{4xA}{7}=1-\frac{1}{21}=\frac{20}{21}\Rightarrow A=\frac{20}{21}.\frac{7}{4}=\frac{5}{3}\)
\(\frac{3}{5}:\frac{7}{9}\times\frac{7:9}{3:5}+1999\)
\(=\frac{3}{5}\times\frac{9}{7}\times\frac{\frac{7}{9}}{\frac{3}{5}}+1999\)
\(=\frac{3}{5}\times\frac{9}{7}\times\frac{7}{9}:\frac{3}{5}+1999\)
\(=\frac{3}{5}\times\frac{9}{7}\times\frac{7}{9}\times\frac{5}{3}+1999\)
\(=\frac{3\times9\times7\times5}{5\times7\times9\times3}+1999\)
\(=1+1999\)
\(=2000\)
Chúc bn học tốt !!!
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{7}+...+\frac{1}{32}-\frac{1}{81}\)
\(=1-\frac{1}{81}\)
\(=\frac{80}{81}\)
Theo đề =>\(0,1F=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99,100}\)
\(\Rightarrow0,1F=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\)
\(\Rightarrow0,1F=1-\frac{1}{100}=\frac{99}{100}\)
\(\Rightarrow F=\frac{99}{10}\)
Chúc bạn hc tốt :)
\(=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+...+\frac{1}{7\cdot8}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-...-\frac{1}{8}\)
\(=\frac{1}{1}-\frac{1}{8}=\frac{7}{8}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{3.7}+\frac{1}{7.8}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{7}-\frac{1}{8}\)
\(=1-\frac{1}{8}+0+0+...+0\)
\(=\frac{7}{8}\)
Đề có sai không