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a, 14/15
14: 15 = 0 dư 14
chuyển thành 0 và 14/15
29/7
29 : 7 = 4 dư 1
chuyển thành 4 và 1/7
100/24 = 4 và 4/24
32/7 = 4 và 4/7
315/100 = 3 và 15/100
còn lại tương tự
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\(\dfrac{7}{5}=1,4\\ \dfrac{34}{20}=1,7\\ \dfrac{25}{50}=0,5\\ \dfrac{6}{25}=0,24\\ \dfrac{24}{125}=0,192\)
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c; 17\(\dfrac{2}{31}\) - (\(\dfrac{15}{17}\) + 6\(\dfrac{2}{31}\))
= 17 + \(\dfrac{2}{31}\) - \(\dfrac{15}{17}\) - 6 - \(\dfrac{2}{31}\)
= (17 - 6) - \(\dfrac{15}{17}\) + (\(\dfrac{2}{31}\) - \(\dfrac{2}{31}\))
= 11 - \(\dfrac{15}{17}\)+ 0
= \(\dfrac{172}{17}\)
b; 130\(\dfrac{25}{28}\) + 120\(\dfrac{17}{35}\)
= 130 + \(\dfrac{25}{28}\) + 120 + \(\dfrac{17}{35}\)
= (130 + 120) + (\(\dfrac{25}{28}\) + \(\dfrac{17}{35}\))
= 250 + (\(\dfrac{125}{140}\) + \(\dfrac{68}{140}\))
= 250 + \(\dfrac{193}{140}\)
= 250\(\dfrac{193}{140}\)
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Bài 1 :a,
\(17\frac{61}{100}=17+\frac{61}{100}=17+0,61=17,61\)
\(31\frac{501}{1000}=31+\frac{501}{1000}=31+0,501=31,501\)
\(30\frac{32}{100}=30+\frac{32}{100}=30+0,32=30,32\)
\(24\frac{7}{10}=24+\frac{7}{10}=24+0,7=24,7\)
\(18\frac{27}{10000}=18+0,0027=18,0027\)
b, \(5\frac{3}{10}=5+\frac{3}{10}=5+0,3=5,3\)
\(51\frac{62}{100}=51+\frac{62}{100}=51+0,62=51,62\)
\(90\frac{8}{100}=90+\frac{8}{100}=90+0,08=90,08\)
\(35\frac{3}{1000}=35+\frac{3}{1000}=35+0,003=35,003\)
\(\dfrac{31}{15}=2\dfrac{1}{15};\dfrac{89}{10}=8\dfrac{9}{10};\dfrac{25}{6}=4\dfrac{1}{6};\dfrac{124}{50}=2\dfrac{13}{25};\dfrac{35}{4}=8\dfrac{3}{4}\)
\(\dfrac{31}{15}\) = 2\(\dfrac{1}{15}\) ; \(\dfrac{89}{10}\) = 8\(\dfrac{9}{10}\) ; \(\dfrac{25}{6}\) = 4\(\dfrac{1}{6}\) ; \(\dfrac{124}{50}\) = \(\dfrac{62}{25}\) = 2\(\dfrac{12}{25}\) ; \(\dfrac{35}{4}\) = 8\(\dfrac{3}{4}\)