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a; 0,2.\(\dfrac{15}{36}\) - (\(\dfrac{2}{5}\) + \(\dfrac{2}{3}\)): 1%
= \(\dfrac{1}{12}\) - \(\dfrac{16}{15}\): \(\dfrac{1}{100}\)
= \(\dfrac{1}{12}\) - \(\dfrac{320}{3}\)
= \(\dfrac{1}{12}\) - \(\dfrac{1280}{12}\)
= - \(\dfrac{1279}{12}\)
b; 75% - 1\(\dfrac{1}{2}\) + 0,5 : \(\dfrac{5}{12}\)
= 0,75 - 1,5 + 1,2
= -0,75 + 1,2
= 0,45
c; 1\(\dfrac{3}{15}.0,75-\left(\dfrac{8}{15}+0,25\right)\).\(\dfrac{24}{47}\)
= \(\dfrac{28}{15}\).0,75 - \(\dfrac{47}{60}\).\(\dfrac{24}{47}\)
= \(\dfrac{7}{5}-\dfrac{2}{5}\)
= 1
d; \(\dfrac{32}{15}\): (-1\(\dfrac{1}{5}\) + 1\(\dfrac{1}{3}\))
= \(\dfrac{32}{15}\): (-\(\dfrac{6}{5}\) + \(\dfrac{4}{3}\))
= \(\dfrac{32}{15}\): \(\dfrac{2}{15}\)
= 16
Ta có
a/ 1/3x - 3/4x = 5/12 1/4x + 3/4 +x =7/8
x(1/3-3/4)=5/12 2x=7/8
-5/12x=5/12 x=7/8 : 2 =7/16
x=5/12 : -5/12
x=-1
a) \(\frac{2}{3}x-\frac{1}{2}x=\frac{5}{12}\)
\(x\left(\frac{2}{3}-\frac{1}{2}\right)=\frac{5}{12}\)
\(x\left(\frac{4}{6}-\frac{3}{6}\right)=\frac{5}{12}\)
\(\frac{1}{6}x=\frac{5}{12}\)
\(x=\frac{5}{12}:\frac{1}{6}=\frac{5}{2}\)
b) \(25\%x+\frac{3}{4}x+x=\frac{7}{8}\)
\(x\left(25\%+\frac{3}{4}+1\right)=\frac{7}{8}\)
\(x\left(\frac{1}{4}+\frac{3}{4}+1\right)=\frac{7}{8}\)
\(x\left(1+1\right)=\frac{7}{8}\)
\(2x=\frac{7}{8}\)
\(x=\frac{7}{8}:2=\frac{7}{16}\)
1/3 + 5/2 + 10/6 = 4/12 + 30/12 + 20/12 = 54/12 = 27/6
