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Do \(f\left(1\right)=g\left(2\right)\) nên:
\(2.1^2+a.1+4=2^3-5.2-b\)
\(\Rightarrow a+6=-2-b\)
\(\Rightarrow a=-b-8\) (1)
Do \(f\left(-1\right)=g\left(5\right)\) nên:
\(2.\left(-1\right)^2+a.\left(-1\right)+4=5^3-5.5-b\)
\(\Rightarrow-a+6=100-b\)
\(\Rightarrow a=b-94\) (2)
(1);(2) \(\Rightarrow-b-8=b-94\)
\(\Rightarrow2b=94-8\)
\(\Rightarrow b=43\)
\(\Rightarrow a=43-94=-51\)
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\(\dfrac{9^{15}.8^{11}}{3^{29}.16^8}=\dfrac{\left(3^2\right)^{15}.\left(2^3\right)^{11}}{3^{29}.\left(2^4\right)^8}=\dfrac{3^{30}.2^{33}}{3^{29}.2^{32}}\)
Ta lấy vễ trên chia vế dưới
\(=3.2=6\)
\(\dfrac{2^{11}.9^3}{3^5.16^2}=\dfrac{2^{11}.\left(3^2\right)^3}{3^5.\left(2^4\right)^2}=\dfrac{2^{11}.3^6}{3^5.2^8}\)
Ta lấy vế trên chia vế dưới
\(=2^3.3=24\)
\(\dfrac{9^{15}.8^{11}}{3^{29}.16^8}=\dfrac{\left(3^2\right)^{15}.\left(2^3\right)^{11}}{3^{29}.\left(2^4\right)^8}=\dfrac{3^{30}.2^{33}}{3^{29}.3^{32}}=3.2=6\)
\(\dfrac{2^{11}.9^3}{3^5.16^2}=\dfrac{2^{11}.\left(3^2\right)^3}{3^5.\left(2^4\right)^2}=\dfrac{2^{11}.3^6}{3^5.2^8}=2^3.3=8.3=24\)
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a.
\(A\left(x\right)+B\left(x\right)+C\left(x\right)=\left(3x^6-5x^4+2x^2-7\right)+\left(8x^6+7x^4-x^2+11\right)+\left(x^6+7x^4-x^2+6\right)\)
\(=12x^6+9x^4+10\)
b.
\(A\left(x\right)-B\left(x\right)+C\left(x\right)=\left(3x^6-5x^4+2x^2-7\right)-\left(8x^6+7x^4-x^2+11\right)+\left(x^6+7x^4-x^2+6\right)\)
\(=-4x^6-5x^4+2x^2-12\)
c.
\(A\left(x\right)-B\left(x\right)-C\left(x\right)=\left(3x^6-5x^4+2x^2-7\right)-\left(8x^6+7x^4-x^2+11\right)-\left(x^6+7x^4-x^2+6\right)\)
\(=-6x^6-19x^4+4x^2-24\)
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Có: \(\dfrac{\left(-3\right)^{10}x15^5}{25^3x\left(-9\right)^7}=\dfrac{3^{10}.\left(3.5\right)^5x}{-\left(3^2\right)^7\left(5^2\right)^3x}\)
\(=\dfrac{3^{15}.5^5x}{-3^{14}.5^6x}\)\(=\dfrac{3^{14}.5^5\left(3x\right)}{3^{14}.5^5\left(-5x\right)}=\dfrac{3x}{-5x}=-\dfrac{3}{5}\)
Vậy...
9a.
Do \(P\left(-2\right)=7\)
\(\Rightarrow a.\left(-2\right)+5=7\)
\(\Rightarrow-2a=2\)
\(\Rightarrow a=-1\)
b.
Do \(P\left(0\right)=-2\)
\(\Rightarrow a.0+b=-2\)
\(\Rightarrow b=-2\)
Do \(P\left(-3\right)=-1\)
\(\Rightarrow a.\left(-3\right)+b=-1\)
\(\Rightarrow-3a-2=-1\)
\(\Rightarrow-3a=1\)
\(\Rightarrow a=-\dfrac{1}{3}\)
em cảm ơn ạ!!!!