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\(\frac{7}{8}>\frac{7}{9}>\frac{7}{10}>\frac{7}{11}>\frac{7}{15}\)
Tính :
\(a,\frac{1}{4}+\frac{3}{8}+\frac{5}{16}=\frac{4+6+5}{16}=\frac{15}{16}\)
\(b,\frac{3}{5}-\frac{1}{3}-\frac{1}{6}=\frac{18-10-5}{30}=\frac{3}{30}=\frac{1}{10}\)
\(c,\frac{4}{7}\times\frac{5}{8}\times\frac{7}{12}=\frac{5}{14}\times\frac{7}{12}=\frac{5}{24}\)
\(d,\frac{25}{28}:\frac{15}{14}\times\frac{6}{7}=\frac{25\times14\times6}{28\times15\times7}=\frac{5}{7}\)
b) \(\frac{3}{5}-\frac{1}{3}-\frac{1}{6}=\frac{18}{30}-\frac{10}{30}-\frac{5}{30}=\frac{8}{30}-\frac{5}{30}=\frac{1}{10}\)
c) \(\frac{4}{7}\times\frac{5}{8}\times\frac{7}{12}=\frac{4\times5\times7}{8\times12\times7}=\frac{5}{2\times12}=\frac{5}{24}\)
d) \(\frac{25}{28}:\frac{15}{14}\times\frac{6}{7}=\frac{25}{28}\times\frac{14}{15}\times\frac{6}{7}=\frac{25\times3}{15\times7}=\frac{75}{105}\)
\(\frac{1}{4}+\frac{3}{8}+\frac{5}{16}=\frac{5}{8}+\frac{5}{16}=\frac{15}{16}\)
\(\frac{3}{5}-\frac{1}{3}-\frac{1}{6}=\frac{4}{15}-\frac{1}{6}=\frac{1}{10}\)
\(\frac{4}{7}\cdot\frac{5}{8}\cdot\frac{7}{12}=\frac{4.5.7}{7.8.12}=\frac{140}{672}=\frac{5}{24}\)
\(\frac{25}{28}:\frac{15}{14}\cdot\frac{6}{7}=\frac{5}{6}\cdot\frac{6}{7}=\frac{5}{7}\)
\(\frac{1}{4}+\frac{3}{8}+\frac{5}{16}=\frac{15}{16}\)
\(\frac{3}{5}-\frac{1}{3}-\frac{1}{6}=\frac{1}{10}\)
\(\frac{4}{7}\times\frac{5}{8}\times\frac{7}{12}=\frac{5}{24}\)
\(\frac{25}{28}:\frac{15}{14}\times\frac{6}{7}=\frac{5}{7}\)
a, \(\dfrac{7}{9}\) = \(\dfrac{7\times11}{9\times11}\) = \(\dfrac{77}{99}\)
\(\dfrac{8}{11}\) = \(\dfrac{8\times9}{11\times9}\) = \(\dfrac{72}{99}\)
Vậy \(\dfrac{7}{9}\) và \(\dfrac{8}{11}\) đã được quy đồng mẫu số lần lượt thành hai phân số:
\(\dfrac{77}{99}\) và \(\dfrac{72}{99}\)
b, \(\dfrac{4}{5}\) = \(\dfrac{4\times5}{5\times5}\) = \(\dfrac{20}{25}\)
Vậy hai phân số \(\dfrac{4}{5}\) và \(\dfrac{7}{25}\) đã được quy đồng mẫu số thành hai phân số: \(\dfrac{20}{25}\) và \(\dfrac{7}{25}\)
a, 1+3+5+7+...+99
Khoảng cách 2 số hạng liên tiếp:
7-5=2(đơn vị)
Số lượng số hạng;
(99-1):2 + 1= 50(số hạng)
Tổng bằng:
(1+99) : 2 x 50 = 2500
Đ.số: 2500
c, 24 - 22 + 20 - 18 + 16 - 14 + 12 - 10 + 8 - 6
=(24-22) + (20-18) + (16-14) + (12-10) + (8-6)
= 2+2+2+2+2
=10
b, 1+4+7+...+28
Hiệu 2 số hàng kề nhau:
7-4=3(đơn vị)
Số lượng số hạng:
(28-1):3 +1= 10(số hạng)
Tổng bằng:
(28+1) : 2 x 10= 145
1.3.77−1+3.7.99−3+7.9.1313−7+9.13.1515−9+\frac{19-13}{13.15.19}+13.15.1919−13
=\frac{1}{1.3}-\frac{1}{3.7}+\frac{1}{3.7}-\frac{1}{7.9}+\frac{1}{7.9}-\frac{1}{9.13}+\frac{1}{9.13}-\frac{1}{13.15}+\frac{1}{13.15}-\frac{1}{15.19}=1.31−3.71+3.71−7.91+7.91−9.131+9.131−13.151+13.151−15.191
=\frac{1}{1.3}-\frac{1}{15.19}=\frac{95}{285}-\frac{1}{285}=\frac{94}{285}=1.31−15.191=28595−2851=28594
b,=\frac{1}{6}.\left(\frac{6}{1.3.7}+\frac{6}{3.7.9}+\frac{6}{7.9.13}+\frac{6}{9.13.15}+\frac{6}{13.15.19}\right)b,=61.(1.3.76+3.7.96+7.9.136+9.13.156+13.15.196)
làm giống như trên
c,=\frac{1}{8}.\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{48.49.50}\right)c,=81.(1.2.31+2.3.41+3.4.51+...+48.49.501)
=\frac{1}{16}.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{48.49.50}\right)=161.(1.2.32+2.3.42+3.4.52+...+48.49.502)
=\frac{1}{16}.\left(\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+...+\frac{50-48}{48.49.50}\right)=161.(1.2.33−1+2.3.44−2+3.4.55−3+...+48.49.5050−48)
=\frac{1}{16}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)=161.(1.21−2.31+2.31−3.41+3.41−4.51+...+48.491−49.501)
=\frac{1}{16}.\left(\frac{1}{2}-\frac{1}{2450}\right)=\frac{1}{16}.\left(\frac{1225}{2450}-\frac{1}{2450}\right)=\frac{153}{4900}=161.(21−24501)=161.(24501225−24501)=4900153
d,=\frac{5}{7}.\left(\frac{7}{1.5.8}+\frac{7}{5.8.12}+\frac{7}{8.12.15}+...+\frac{7}{33.36.40}\right)d,=75.(1.5.87+5.8.127+8.12.157+...+33.36.407)
=\frac{5}{7}.\left(\frac{8-1}{1.5.8}+\frac{12-5}{5.8.12}+\frac{15-8}{8.12.15}+...+\frac{40-33}{33.36.40}\right)=75.(1.5.88−1+5.8.1212−5+8.12.1515−8+...+33.36.4040−33)
=\frac{5}{7}.\left(\frac{1}{1.5}-\frac{1}{5.8}+\frac{1}{5.8}-\frac{1}{8.12}+\frac{1}{8.12}-\frac{1}{12.15}+...+\frac{1}{33.36}-\frac{1}{36.40}\right)=75.(1.51−5.81+5.81−8.121+8.121−12.151+...+33.361−36.401)
=\frac{5}{7}.\left(\frac{1}{5}-\frac{1}{1440}\right)=\frac{5}{7}.\left(\frac{288}{1440}-\frac{1}{1440}\right)=\frac{41}{288}=75.(51−14401)=75.(1440288−14401)=28841
P/S: . là nhân nha
a.1/4 +3/8 +5/16=15/16
b, 3/5 - 1/3 -1/6=1/10
c, 4/7 *5/8 *7/12=5/24
d. 25/28 : 15/24 * 6/7=60/49