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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
Từ đầu bài
=> 52S=52+54+56+...+5202
=>52S-S= (52+54+56+...+5202)-(1+52+54+...+5200)
=> 24.S = 5202-1
=> S = \(\frac{5^{202}-1}{24}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) S=1+52+54+.....+5200
=>52S=25S=52+54+56+.....+5202
=>25S-S=(52+54+56+....+5202)-(1+52+54+......+5200)
=>24S=5202-1
=>S=\(\frac{5^{202}-1}{24}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
[\(\dfrac{16}{3}\) - 22.\(\dfrac{5}{3}\)].[\(\dfrac{17}{3}\) - 22.\(\dfrac{5}{3}\)]...[\(\dfrac{30}{3}\) - 22.\(\dfrac{5}{3}\)]
= [\(\dfrac{16}{3}\) - \(\dfrac{20}{3}\)].[\(\dfrac{17}{3}\) - \(\dfrac{20}{3}\)][\(\dfrac{18}{3}\)-\(\dfrac{20}{3}\)][\(\dfrac{19}{3}\)-\(\dfrac{20}{3}\)].[\(\dfrac{20}{3}\)-\(\dfrac{20}{3}\)]...[\(\dfrac{30}{3}\) - \(\dfrac{20}{3}\)]
=[\(\dfrac{16}{3}\) - \(\dfrac{20}{3}\)].[\(\dfrac{17}{3}\)- \(\dfrac{20}{3}\)].[\(\dfrac{18}{3}\) - \(\dfrac{20}{3}\)].[\(\dfrac{19}{3}\) - \(\dfrac{20}{3}\)].0...[\(\dfrac{30}{3}\) - \(\dfrac{20}{3}\)]
= 0
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(VT=1+2+2^3+...+2^{100}\)
\(2VT=2\left(1+2+2^3+...+2^{100}\right)\)
\(2VT=2+2^2+2^3+...+2^{101}\)
\(2VT-VT=\left(2+2^2+2^3+...+2^{101}\right)-\left(1+2+2^2+2^3+...+2^{100}\right)\)\(VT=2^{101}-1\)
\(VT=VP\)
Thằng phúc chết tiệt, làm giúp ng` ta ko làm hết đuy, còn làm dở =))
Bài 2 :
a) Ta có :
\(3^{30}< 3^{34}\)
\(3^{30}=\left(3^3\right)^{10}=27^{10}\)
\(5^{20}=\left(5^2\right)^{10}=25^{10}\)
Vì \(27^{10}>25^{10}\Leftrightarrow3^{30}>5^{20}\) (Mà \(3^{30}< 3^{34}\))
\(\Leftrightarrow5^{20}< 3^{34}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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= 22500 nhé bạn
nhớ k mình nhé
= [—5.(—30)]^2
=150^2
=22500