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BB
19 tháng 7 2019
a) \(\frac{-16}{5}< 0< \frac{17}{3}< 2\)
b)\(\frac{-17}{3}< 0< \frac{-30}{-2}< \frac{18}{4}< 5\)
27 tháng 7 2021
a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)
\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)
\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)
\(=\dfrac{-1621}{126}\)
b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)
\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)
\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)
\(=-\dfrac{49}{20}\)
26 tháng 6 2023
15: A= 1/3-3/4+3/5+1/2007-1/36+1/15-2/9
Sửa đề:
A=-3/4-2/9-1/36+1/3+3/5+1/15+1/2007
=-27/36-8/36-1/36+5/15+9/15+1/15+1/2007
=-1+1+1/2007=1/2007
16:
\(A=\dfrac{1}{3}+\dfrac{3}{5}+\dfrac{1}{15}-\dfrac{3}{4}-\dfrac{2}{9}-\dfrac{1}{36}+\dfrac{1}{64}\)
\(=\dfrac{5+9+1}{15}+\dfrac{-27-8-1}{36}+\dfrac{1}{64}\)
=1/64
17:
=1/2-1/2+2/3-2/3+3/4-3/4+4/5-4/5+5/6-5/6-6/7
=-6/7
VM
23 tháng 7 2019
a) \(\frac{2}{3}-4.\left(\frac{1}{2}+\frac{3}{4}\right)\)
= \(\frac{2}{3}-4.\frac{5}{4}\)
= \(\frac{2}{3}-5\)
= \(-\frac{13}{3}\).
b) Câu này là 117 hay \(\frac{11}{7}\) vậy bạn?
Chúc bạn học tốt!
[\(\dfrac{16}{3}\) - 22.\(\dfrac{5}{3}\)].[\(\dfrac{17}{3}\) - 22.\(\dfrac{5}{3}\)]...[\(\dfrac{30}{3}\) - 22.\(\dfrac{5}{3}\)]
= [\(\dfrac{16}{3}\) - \(\dfrac{20}{3}\)].[\(\dfrac{17}{3}\) - \(\dfrac{20}{3}\)][\(\dfrac{18}{3}\)-\(\dfrac{20}{3}\)][\(\dfrac{19}{3}\)-\(\dfrac{20}{3}\)].[\(\dfrac{20}{3}\)-\(\dfrac{20}{3}\)]...[\(\dfrac{30}{3}\) - \(\dfrac{20}{3}\)]
=[\(\dfrac{16}{3}\) - \(\dfrac{20}{3}\)].[\(\dfrac{17}{3}\)- \(\dfrac{20}{3}\)].[\(\dfrac{18}{3}\) - \(\dfrac{20}{3}\)].[\(\dfrac{19}{3}\) - \(\dfrac{20}{3}\)].0...[\(\dfrac{30}{3}\) - \(\dfrac{20}{3}\)]
= 0