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13 tháng 8 2021

5/4

\(\dfrac{4}{7}-\dfrac{4}{7}+\dfrac{8}{21}+\dfrac{13}{21}+\left(-\dfrac{1}{2}\right)^2=\dfrac{1}{4}\)

AH
Akai Haruma
Giáo viên
13 tháng 8 2023

Lời giải:
$B=\frac{3}{2}-\frac{2}{21}-\frac{7}{12}+\frac{15}{21}-\frac{1}{3}+\frac{5}{4}-\frac{2}{7}-\frac{1}{3}$

$=(\frac{3}{2}+\frac{5}{4})+(\frac{-2}{21}+\frac{15}{21}+\frac{-2}{7})+(\frac{-7}{12}+\frac{-1}{3}+\frac{-1}{3})$

$=\frac{11}{4}+\frac{1}{3}-\frac{5}{4}=\frac{11}{6}$

7 tháng 12 2021

\(\dfrac{15}{34}+\dfrac{7}{21}+\dfrac{19}{34}-1\dfrac{7}{21}+\dfrac{2}{5}=\left(\dfrac{15}{34}+\dfrac{19}{34}\right)+\left(\dfrac{7}{21}-\dfrac{4}{3}\right)+\dfrac{2}{5}=1+\left(-1\right)+\dfrac{2}{5}=0+\dfrac{2}{5}=\dfrac{2}{5}\)

25 tháng 10 2023

\((\frac59-\frac37+21)-(2+\frac57-\frac29)-(\frac79-\frac87+9)\\=\frac59-\frac37+21-2-\frac57+\frac29-\frac79+\frac87-9\\=(\frac59+\frac29-\frac79)+(-\frac37-\frac57+\frac87)+(21-2-9)\\=21-2-9\\=19-9\\=10\)

20 tháng 7 2023

\(\dfrac{1}{2}\) - \(\dfrac{13}{14}\)): \(\dfrac{5}{7}\) - (- \(\dfrac{2}{21}\) + \(\dfrac{1}{7}\)) : \(\dfrac{5}{7}\)

(\(\dfrac{7}{14}\) - \(\dfrac{13}{14}\)): \(\dfrac{5}{7}\) - ( - \(\dfrac{2}{21}\) + \(\dfrac{3}{21}\)): \(\dfrac{5}{7}\)

\(\dfrac{6}{14}\)\(\dfrac{5}{7}\)  - \(\dfrac{1}{21}\)\(\dfrac{5}{7}\)

= - (\(\dfrac{3}{7}\) + \(\dfrac{1}{21}\)): \(\dfrac{5}{7}\)

= -\(\dfrac{10}{21}\)\(\dfrac{5}{7}\)

= - \(\dfrac{2}{3}\) 

 

26 tháng 10 2019

Mình làm câu này  các câu khác tương tự 

Mấu chốt làm bài này là đưa về thừa số nguyên tố

\(\frac{12^7.3^{35}.14^{21}}{9^{21}.7^{21}.2^{35}}=\frac{3^7.4^7.3^{35}.2^{21}.7^{21}}{3^{2.21}.7^{21}.2^{35}}=\frac{3^7.2^{2.7}.3^{35}.2^{21}.7^{21}}{3^{2.21}.7^{21}.2^{35}}=\frac{3^7.2^{14}.3^{35}.2^{21}.7^{21}}{3^{42}.7^{21}.2^{35}}=\frac{3^{42}.2^{35}.7^{21}}{3^{42}.7^{21}.2^{35}}=1\)

\(=\dfrac{3}{2}-\dfrac{2}{21}-\dfrac{7}{12}+\left[\dfrac{15}{21}-\dfrac{1}{3}+\dfrac{5}{4}-\dfrac{2}{7}-\dfrac{1}{3}\right]\)

=11/12-2/21+5/7-2/3+5/4-2/7

=11/12-2/3+5/4-2/21+3/7

=11/12-8/12+15/12-2/21+9/21

=18/12+7/21

=3/2+1/3

=9/6+2/6=11/6

14 tháng 8 2023

\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left\{\dfrac{7}{12}-\left[\dfrac{15}{21}-\left(\dfrac{1}{3}-\dfrac{5}{4}\right)-\left(\dfrac{2}{7}+\dfrac{1}{3}\right)\right]\right\}\)

\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left\{\dfrac{7}{12}-\left[\dfrac{15}{21}-\left(-\dfrac{11}{12}\right)-\dfrac{13}{21}\right]\right\}\)

\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left\{\dfrac{7}{12}-\dfrac{85}{84}\right\}\)

\(B=\dfrac{3}{2}-\dfrac{2}{21}-\left(-\dfrac{3}{7}\right)\)

\(B=\dfrac{11}{6}\)