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e. = 12 - 25 + 38 + 25 - 38 + 88 - 250
= ( -25 + 25) + (38 - 38) + ( 12 + 88) - 250
= -150
f. = (-12).44 + 44.(-88)
= 44 ( -12 -88 )
= 44 . 100
= 4400
g. = -48 + 54 -77 -24 + 48 + 77
= (-48 + 48) + (-77+77) + (54 -24)
= 30
h. = 11.(-42) + 11.(-26) + 42.11 + 42.26 -26.11 - 42.26
= \([11.\left(-42\right)+11.42]+\left[11.\left(-26\right)-26.11\right]+[42.26-42.26]\)
= 11. (-52)
= - 572
\(e.-\left(-12+25-38\right)+\left(25-38+88\right)-250\\ =12-25+38+25-38+88-250\\ =\left(25-25\right)+\left(38-38\right)+\left(12+88\right)-250\\ =0+0+100-250=-150\)
\(f.\left(-12\right)\cdot\left(67-23\right)+44\cdot\left(-88\right)\\ =\left(-12\right)\cdot44+44\cdot\left(-88\right)\\ =44\cdot\left[-12+\left(-88\right)\right]\\ =44\cdot\left(-100\right)=-4400\)
\(g.\left(-48+54-77\right)-\left(24-48-77\right)\\ =-48+54-77-24+48+77\\ =\left(48-48\right)+\left(54-24\right)+\left(77-77\right)\\ =0+30+0=30\)
\(h.11\cdot\left(-42-26\right)+42\cdot\left(11+26\right)-26\cdot11-42\cdot26\\ =11\cdot\left(-68\right)+42\cdot37-26\cdot11-42\cdot26\\ =-748+1554-286-1092=-572\)
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\(\left(x-5\right)^{2022}=\left(x-5\right)^{2024}\\ \Rightarrow\left(x-5\right)^{2022}-\left(x-5\right)^{2024}=0\\ \Rightarrow\left(x-5\right)^{2022}\left[1-\left(x-5\right)^2\right]=0\\ \Rightarrow\left[{}\begin{matrix}\left(x-5\right)^{2022}=0\\1-\left(x-5\right)^2=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x-5=0\\\left(x-5\right)^2=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\\\left(x-5\right)^2=\left(\pm1\right)^2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\\x=6\\x=4\end{matrix}\right.\)
`#3107.101107`
\(\left(x-5\right)^{2022}=\left(x-5\right)^{2024}\)
\(\Rightarrow\left(x-5\right)^{2022}-\left(x-5\right)^{2024}=0\\ \Rightarrow\left(x-5\right)^{2022}\cdot\left[1-\left(x-5\right)^2\right]=0\\ \Rightarrow\left[{}\begin{matrix}\left(x-5\right)^{2022}=0\\1-\left(x-5\right)^2=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x-5=0\\\left(x-5\right)^2=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\\\left(x-5\right)^2=\left(\pm1\right)^2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\\x-5=1\\x-5=-1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\\x=6\\x=4\end{matrix}\right.\)
Vậy, \(x\in\left\{4;5;6\right\}.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=\dfrac{2024^{2023}+1}{2024^{2024}+1}\)
\(2024A=\dfrac{2024^{2024}+2024}{2024^{2024}+1}=\dfrac{\left(2024^{2024}+1\right)+2023}{2024^{2024}+1}=\dfrac{2024^{2024}+1}{2024^{2024}+1}+\dfrac{2023}{2024^{2024}+1}=1+\dfrac{2023}{2024^{2024}+1}\)
\(B=\dfrac{2024^{2022}+1}{2024^{2023}+1}\)
\(2024B=\dfrac{2024^{2023}+2024}{2024^{2023}+1}=\dfrac{\left(2024^{2023}+1\right)+2023}{2024^{2023}+1}=\dfrac{2024^{2023}+1}{2024^{2023}+1}+\dfrac{2023}{2024^{2023}+1}=1+\dfrac{2023}{2024^{2023}+1}\)
Vì \(2024>2023=>2024^{2024}>2024^{2023}\)
\(=>2024^{2024}+1>2024^{2023}+1\)
\(=>\dfrac{2023}{2024^{2023}+1}>\dfrac{2023}{2024^{2024}+1}\)
\(=>A< B\)
\(#PaooNqoccc\)
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1-2+3-4+5-6+7-8+...+2023-2024
=(1−2)+(3−4)+(5−6)+(7−8)+....+(2023−2024)=(1−2)+(3−4)+(5−6)+(7−8)+....+(2023−2024)
=−1+(−1)+(−1)+(−1)+...+(−1)=−1+(−1)+(−1)+(−1)+...+(−1)
=−1.1012=−1.1012
=−1012=−1012
1-2+3-4+5-6+ ... +2023-2024
= (-1) + (-1) + ... + (-1) (1012 số)
= (-1).1012
= -1012
![](https://rs.olm.vn/images/avt/0.png?1311)
A>1√2+√3+1√4+√5+1√6+√7+...+1√2024+√2025A>12+3+14+5+16+7+...+12024+2025
⇒2A>1√1+√2+1√2+√3+1√3+√4+1√4+√5+...+1√2024+√2025⇒2A>11+2+12+3+13+4+14+5+...+12024+2025
⇒2A>√2−√1+√3−√2+√4−√3+...+√2025−√2024⇒2A>2−1+3−2+4−3+...+2025−2024
⇒2A>√2025−√1=44⇒2A>2025−1=44
⇒A>22⇒A>22