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19 tháng 12 2021

Đề bài yêu cầu gì?

9 tháng 5 2019

Đáp án cần chọn là: D

e. = 12 - 25 + 38 + 25 - 38 + 88  - 250 

    = ( -25 + 25) + (38 - 38) + ( 12 + 88) - 250

   = -150

f. = (-12).44 + 44.(-88)

 = 44 ( -12 -88 )

= 44 . 100

= 4400

g. = -48 + 54 -77 -24 + 48 + 77

= (-48 + 48) + (-77+77) + (54 -24)

= 30

h. = 11.(-42) + 11.(-26) + 42.11 + 42.26 -26.11 - 42.26

 = \([11.\left(-42\right)+11.42]+\left[11.\left(-26\right)-26.11\right]+[42.26-42.26]\)

= 11. (-52)

= - 572

 

 

 

9 tháng 1 2023

\(e.-\left(-12+25-38\right)+\left(25-38+88\right)-250\\ =12-25+38+25-38+88-250\\ =\left(25-25\right)+\left(38-38\right)+\left(12+88\right)-250\\ =0+0+100-250=-150\)

\(f.\left(-12\right)\cdot\left(67-23\right)+44\cdot\left(-88\right)\\ =\left(-12\right)\cdot44+44\cdot\left(-88\right)\\ =44\cdot\left[-12+\left(-88\right)\right]\\ =44\cdot\left(-100\right)=-4400\)

\(g.\left(-48+54-77\right)-\left(24-48-77\right)\\ =-48+54-77-24+48+77\\ =\left(48-48\right)+\left(54-24\right)+\left(77-77\right)\\ =0+30+0=30\)

\(h.11\cdot\left(-42-26\right)+42\cdot\left(11+26\right)-26\cdot11-42\cdot26\\ =11\cdot\left(-68\right)+42\cdot37-26\cdot11-42\cdot26\\ =-748+1554-286-1092=-572\)

8 tháng 10 2023

\(\left(x-5\right)^{2022}=\left(x-5\right)^{2024}\\ \Rightarrow\left(x-5\right)^{2022}-\left(x-5\right)^{2024}=0\\ \Rightarrow\left(x-5\right)^{2022}\left[1-\left(x-5\right)^2\right]=0\\ \Rightarrow\left[{}\begin{matrix}\left(x-5\right)^{2022}=0\\1-\left(x-5\right)^2=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x-5=0\\\left(x-5\right)^2=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\\\left(x-5\right)^2=\left(\pm1\right)^2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\\x=6\\x=4\end{matrix}\right.\)

`#3107.101107`

\(\left(x-5\right)^{2022}=\left(x-5\right)^{2024}\)

\(\Rightarrow\left(x-5\right)^{2022}-\left(x-5\right)^{2024}=0\\ \Rightarrow\left(x-5\right)^{2022}\cdot\left[1-\left(x-5\right)^2\right]=0\\ \Rightarrow\left[{}\begin{matrix}\left(x-5\right)^{2022}=0\\1-\left(x-5\right)^2=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x-5=0\\\left(x-5\right)^2=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\\\left(x-5\right)^2=\left(\pm1\right)^2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\\x-5=1\\x-5=-1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\\x=6\\x=4\end{matrix}\right.\)

Vậy, \(x\in\left\{4;5;6\right\}.\)

13 tháng 2 2023

\(A=\dfrac{2024^{2023}+1}{2024^{2024}+1}\)

\(2024A=\dfrac{2024^{2024}+2024}{2024^{2024}+1}=\dfrac{\left(2024^{2024}+1\right)+2023}{2024^{2024}+1}=\dfrac{2024^{2024}+1}{2024^{2024}+1}+\dfrac{2023}{2024^{2024}+1}=1+\dfrac{2023}{2024^{2024}+1}\)

\(B=\dfrac{2024^{2022}+1}{2024^{2023}+1}\)

\(2024B=\dfrac{2024^{2023}+2024}{2024^{2023}+1}=\dfrac{\left(2024^{2023}+1\right)+2023}{2024^{2023}+1}=\dfrac{2024^{2023}+1}{2024^{2023}+1}+\dfrac{2023}{2024^{2023}+1}=1+\dfrac{2023}{2024^{2023}+1}\)

Vì \(2024>2023=>2024^{2024}>2024^{2023}\)

\(=>2024^{2024}+1>2024^{2023}+1\)

\(=>\dfrac{2023}{2024^{2023}+1}>\dfrac{2023}{2024^{2024}+1}\)

\(=>A< B\)

 

\(#PaooNqoccc\)

13 tháng 2 2023

dễ

29 tháng 12 2023

\(5^{12}:5^{10}-160:10+2024^0\)
\(=5^2-16+1\)
\(=25-16+1\)
\(=10\)

29 tháng 12 2023

Cộng vs 20240 mà bạn ơi

3 tháng 1

1-2+3-4+5-6+7-8+...+2023-2024

 

=(1−2)+(3−4)+(5−6)+(7−8)+....+(2023−2024)=(1−2)+(3−4)+(5−6)+(7−8)+....+(2023−2024)

 

=−1+(−1)+(−1)+(−1)+...+(−1)=−1+(−1)+(−1)+(−1)+...+(−1)

 

=−1.1012=−1.1012

 

=−1012=−1012

 

 

3 tháng 1

1-2+3-4+5-6+ ... +2023-2024

= (-1) + (-1) + ... + (-1) (1012 số)

= (-1).1012

= -1012

24 tháng 2 2023

A>1√2+√3+1√4+√5+1√6+√7+...+1√2024+√2025A>12+3+14+5+16+7+...+12024+2025

⇒2A>1√1+√2+1√2+√3+1√3+√4+1√4+√5+...+1√2024+√2025⇒2A>11+2+12+3+13+4+14+5+...+12024+2025

⇒2A>√2−√1+√3−√2+√4−√3+...+√2025−√2024⇒2A>2−1+3−2+4−3+...+2025−2024

⇒2A>√2025−√1=44⇒2A>2025−1=44

⇒A>22⇒A>22 

24 tháng 2 2023

bài rất dễ hỉu =))))))))