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\(36\cdot4-4\cdot\left[82-7\cdot11\right]^2:4-2016^0\)
=9-1-5^2
=8-25=-17
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a) 5 : 3/4 - 4 4/5 : 3/4
= 5 . 4/3 - 24/5 . 4/3
= (5 - 24/5) . 4/3
= 1/5 × 4/3
= 4/15
b) -3/5 . 2/7 + (-3/7) . 3/5 + (-3/7)
= (-3/7) . (2/5 + 3/5 + 1)
= (-3/7) . 2
= -6/7
c) [(-4 2/7) . 7/11 + 7/11 . (5 1/3)] . 5 - 5 2/3
= (-30/7 . 7/11 + 7/11 . 16/3) . 5 - 17/3
= (-30/11 + 112/33) . 5 - 17/3
= 2/3 . 5 - 17/3
= 10/3 - 17/3
= -7/3
d) 5/39 . [(7 4/5) . (1 2/3) + (8 1/3) . (7 4/5)]
= 5/39 . (39/5 . 5/3 + 25/3 . 39/5)
= 5/39 . 39/5 . (5/3 + 25/3)
= 1 . 10
= 10
=
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a) \(\frac{2}{3}x\times\frac{1}{2}=\frac{1}{10}\Rightarrow\frac{2}{3}x=\frac{1}{5}\Rightarrow x=\frac{3}{10}\)
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\(\left(11\times3^{22}\times3^7-9^{15}\right)\div6^{28}=\left[11\times3^{29}-\left(3^2\right)^{15}\right]\div\left(2\times3\right)^{28}=\left(11\times3^{29}-3^{30}\right)\div\left(2^{28}\times3^{28}\right)\)
\(=\frac{3^{29}\times\left(11-3\right)}{2^{28}\times3^{28}}=\frac{3\times8}{2^{28}}=\frac{3\times2^3}{2^{28}}=\frac{3}{2^{25}}\)
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\(\left(5^2\times2^3-7^3\times2\right)\div2\times6-7\div2^5\)
\(=\left(25\times8-343\times2\right)\div2\times6-7\div32\)
\(=\left(200-686\right)\div2\times6-7\div32\)
\(=-486\div2\times6-7\div32\)
\(=-1458-0,21875\)
\(=-1458,21875\)
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\(\left(5^2.2^3-7^3.2\right):\left(2.6-7:2^5\right)\\ =\left(25.8-343.2\right):\left(12-7:32\right)\\ =\left(200-686\right):\left(12-\dfrac{7}{32}\right)\\ =-486:\dfrac{377}{32}=-486.\dfrac{32}{377}=-\dfrac{15552}{377}\)
(5^2*2^3-7^3*2):2*6-7:2^5
=(25*8-343*2):3-7/32
=-162-7/32=-5191/32
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( 9 . x - 62 )10 = 74 : 74
( 9 . x - 62 )10 = 1
( 9 . x - 62 )10 = 110
=> 9 . x - 62 = 1
9 . x = 1 + 62
9 . x = 63
x = 63 : 9
x = 7
tích cho mik mik giải cho