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2 tháng 11 2016

2/3-(-1/4)+3/5-7/45-(-5/9)+1/12+1/39=79/39 nha 

2 tháng 11 2016

2/3-(-1/4)+3/5-7/45-(-5/9)+1/12+1/39

=11/12+1+17/156

=79/39

8 tháng 10 2018

Thực hiện phép tính ( bằng cách hợp lí nếu có thể ) 

A. 2/3 - (- 1/4)+3/5-(+7/45)-(-5/9)+1/12+1/39 

B. 6.(-2/3)^2 - 3(-2/3)^2 - 2 : (-3/2)+4

14 tháng 9 2021

a. \(\dfrac{-2}{3}+\dfrac{-1}{5}+\dfrac{3}{4}-\dfrac{5}{6}-\dfrac{7}{10}\)

\(\dfrac{-4}{6}+\dfrac{-2}{10}+\dfrac{3}{4}-\dfrac{5}{6}-\dfrac{7}{10}\)

\(\dfrac{-3}{2}+\dfrac{1}{2}+\dfrac{3}{4}\)

= (-1) + \(\dfrac{3}{4}\)

\(\dfrac{-4}{4}+\dfrac{3}{4}\)

\(\dfrac{-1}{4}\)

a: \(-\dfrac{4}{7}-\dfrac{5}{13}\cdot\dfrac{-39}{25}+\dfrac{-1}{42}:\dfrac{-5}{6}\)

\(=\dfrac{-4}{7}+\dfrac{3}{5}+\dfrac{1}{35}\)

\(=\dfrac{-20}{35}+\dfrac{21}{35}+\dfrac{1}{35}\)

\(=\dfrac{2}{35}\)

9 tháng 5 2016

Chào bạn, bạn hãy theo dõi bài giải của mình nhé!

\(\frac{2}{3}-\left(-\frac{1}{4}\right)+\frac{3}{5}-\frac{7}{45}-\left(-\frac{7}{9}\right)+\frac{1}{12}+\frac{1}{39}\)

\(=\frac{2}{3}+\frac{1}{4}+\frac{3}{5}-\frac{7}{45}+\frac{7}{9}+\frac{1}{12}+\frac{1}{39}\)

\(=\left(\frac{2}{3}+\frac{1}{4}+\frac{1}{12}\right)+\left(\frac{7}{9}+\frac{3}{5}-\frac{7}{45}\right)+\frac{1}{39}\)

\(=\left(\frac{8}{12}+\frac{3}{12}+\frac{1}{12}\right)+\left(\frac{35}{45}+\frac{27}{45}-\frac{7}{45}\right)+\frac{1}{39}\)

\(=\frac{12}{12}+\frac{55}{45}+\frac{1}{39}=1+\frac{11}{9}+\frac{1}{39}=\frac{351}{351}+\frac{429}{351}+\frac{9}{351}=\frac{789}{351}\)

12 tháng 9 2021

2 3 − ( − 1 4 ) + 3 5 − 7 45 − ( − 7 9 ) + 1 12 + 1 39 = 2 3 + 1 4 + 3 5 − 7 45 + 7 9 + 1 12 + 1 39 = ( 2 3 + 1 4 + 1 12 ) + ( 7 9 + 3 5 − 7 45 ) + 1 39 = ( 8 12 + 3 12 + 1 12 ) + ( 35 45 + 27 45 − 7 45 ) + 1 39 = 12 12 + 55 45 + 1 39 = 1 + 11 9 + 1 39 = 351 351 + 429 351 + 9 351 = 789 351

26 tháng 7 2023

\(a.\dfrac{-4}{7}-\dfrac{5}{13}\times\dfrac{-39}{25}+\dfrac{-1}{42}:\dfrac{-5}{6}\) 

\(=\dfrac{-4}{7}+\dfrac{3}{5}+\dfrac{1}{35}\) \(=\dfrac{1}{35}+\dfrac{1}{35}=\dfrac{2}{35}\) 

\(b.\dfrac{2}{9}\times\left[\dfrac{4}{5}:\left(\dfrac{1}{5}-\dfrac{2}{15}\right)+1\dfrac{2}{3}\right]-\dfrac{-5}{27}\) 

\(=\dfrac{2}{9}\times\left[\dfrac{4}{5}:\dfrac{1}{15}+\dfrac{5}{3}\right]-\dfrac{-5}{27}\) 

\(=\dfrac{2}{9}\times\left(12+\dfrac{5}{3}\right)-\dfrac{-5}{27}\) 

\(=\dfrac{2}{9}\times\dfrac{41}{3}-\dfrac{-5}{27}=\dfrac{82}{27}-\dfrac{-5}{27}=\dfrac{29}{9}\)

a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)

\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)

\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)

\(=\dfrac{-1621}{126}\)

b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)

\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)

\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)

\(=-\dfrac{49}{20}\)