125 : x = 2 mũ2 - (-1)
18 - ( x + 14 ) : 3 = 27
2mũ2x - mũ3 = 32
x - 11 = 185 - ( 132 + 185 )
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T
31 tháng 3 2020
\(1.\left(x^3-1\right)\left(x^2+1\right)=0\)
\(< =>\left\{{}\begin{matrix}x^3-1=0\\x^2+1=0\end{matrix}\right.\)
\(< =>\left\{{}\begin{matrix}x^3=1\\x^2=-1\left(kxđ\right)\end{matrix}\right.\)
<=>x=1
vậy ...
\(2.\left(2x+6\right)\left(3x^2-12\right)=0\)
\(< =>\left\{{}\begin{matrix}2x+6=0\\3x^2-12=0\end{matrix}\right.\)
\(< =>\left\{{}\begin{matrix}2x=-6\\3x^2=12\end{matrix}\right.\)
\(< =>\left\{{}\begin{matrix}x=-3\\x^2=4\end{matrix}\right.\)
\(< =>\left\{{}\begin{matrix}x=-3\\x=2\\x=-2\end{matrix}\right.\)
vậy ...
DN
13 tháng 1 2018
Bài 1 . Thực hiện phép tính :
a, ( 11 + 159 ) . 37 + ( 185 - 31 ) : 14
= 170 . 37 + 154 : 14
= 6290 + 11
= 6301
b, [ 25 . 103 + 7225 : 17 - ( 1500 - 125 ) : 5 ] . 32
= [ 25 . 103 + 7225 : 17 - 1375 : 5 ] . 32
= [ 2575 + 425 - 275 ] . 32
= 2725 . 32
= 87200
c, 136 . 25 + 75 . 136 - 62 . 102
= 136 . ( 25 + 75 ) - 36 . 100
= 136 . 100 - 36 . 100
= 100 . ( 136 - 36 )
= 100 . 100
= 10000
22 tháng 1 2018
a, (11+159).37+(185-31):14 b,[25.103+7225:17-(1500-125):5].32 c, 136.25+75.136 - 62.102
=170.37+154:14 =[2575+425-1375:5].32 =136.(25+75)- (6.10)2
=6290+11 =[2575+425-275].32 =136.100 - 602
=6301 =2725.32 =13600 - 3600
= 87200 =10000
HH
24 tháng 6 2018
Giải:
a) \(x\left(x-2\right)-\left(x+3\right).x+7+9x=6\)
\(\Leftrightarrow x^2-2x-\left(x^2+3x\right)+7+9x=6\)
\(\Leftrightarrow x^2-2x-x^2-3x+7+9x=6\)
\(\Leftrightarrow4x=-1\)
\(\Leftrightarrow x=-\dfrac{1}{4}\)
Vậy ...
b) \(\left(3x-5\right)\left(7-5x\right)-\left(5x+2\right)\left(2-3x\right)=4\)
\(\Leftrightarrow21x-35-15x^2+25x-\left(10x+2-15x^2+6x\right)=4\)
\(\Leftrightarrow21x-35-15x^2+25x-10x-2+15x^2-6x=4\)
\(\Leftrightarrow30x-37=4\)
\(\Leftrightarrow30x=41\)
\(\Leftrightarrow x=\dfrac{41}{30}\)
Vậy ...
c) \(\left(x+2\right)\left(x^2-2x+4\right)-\left(x^3+3\right)=14x\) (Sửa đề)
\(\Leftrightarrow x^3+8-x^3-3=14x\)
\(\Leftrightarrow5=14x\)
\(\Leftrightarrow x=\dfrac{5}{14}\)
Vậy ...
d) \(\left(x^2-x+1\right)\left(x+1\right)-x^3-3x=2\)
\(\Leftrightarrow x^3+1-x^3-3x=2\)
\(\Leftrightarrow1-3x=2\)
\(\Leftrightarrow-3x=1\)
\(\Leftrightarrow x=-\dfrac{1}{3}\)
Vậy ...
25 tháng 6 2018
a) \(x\left(x-2\right)-\left(x+3\right)x+7+9x=6\)
=> \(x^2-2x-x-3x+7+9x=6\)
=> \(x^2-2x-x^2-3x+7+9x=6\)
=> \(\left(x^2-x^2\right)+\left(-2x-3x+9x\right)=6-7\)
=> \(4x=-1\)
Vậy \(x=\dfrac{-1}{4}\)
b) \(\left(3x-5\right)\left(7-5x\right)-\left(5x+2\right)\left(2-3x\right)=4\)
=>\(21x-15x^2-35+25x-10x+15x^2-4+6x=4\)
=> \(\left(21x+25x-10x+6x\right)\)\(+\left(-15x^2+15x^2\right)\)\(=4+35+4\)
=> \(42x=43\)
Vậy \(x=\dfrac{43}{42}\)
c) \(\left(x+2\right)\left(x^2-2x+4\right)-\left(x^3+3\right)=14\)
=> \(x^3-2x^2+4x+2x^2-4x+8-x^3-3\)\(=14x\)
=>\(\left(x^3-x^3\right)+\left(-2x^2+2x^x\right)+\left(4x-4x\right)+\left(8-3\right)\)\(=14x\)
=> \(5=14x\)
Vậy \(x=\dfrac{5}{14}\)
d) \(\left(x^2-x+1\right)\left(x+1\right)-x^3-3x=2\)
=> \(x^3+x^2+x+x^2-x+1-x^3-3x=2\)
=>\(\left(x^3-x^3\right)+\left(-x^2+x^2\right)+\left(x-x-3x\right)=2-1\)
=> \(-3x=1\)
Vậy \(x=\dfrac{-1}{3}\)
125 : \(x\) = 22 - (-1)
125 : \(x\) = 4 + 1
125 : \(x\) = 5
\(x\) = 125 : 5
\(x\) = 25
18 - (\(x\) + 14) : 3 = 27
(\(x\) + 14) : 3 = 18 - 27
(\(x\) + 14) : 3 = - 9
\(x\) + 14 = - 9.3
\(x\) + 14 = -27
\(x\) = -27 - 14
\(x\) = - 41