(2/3-0,25+2)-(2-5/2+1/4)-(2,5-1/3) giúp mk vs
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12 tháng 11 2017
a, (-0.25) * 7.9 * 40 = [ (-0.25) * 40] * 7.9 = -10 * 7.9 = -79
b, ( 3/2 )^3 * 2^3 = ( 3/2*2) ^3 = 3^3 = 27
c, (1.75 / \(\frac{7}{2}\)) * \(\frac{4}{5}\)= ( 7/4 * 7/2 ) *4/5 = \(\frac{49}{10}\)
d, \(\frac{11}{2}\cdot4\frac{5}{3}-2\frac{5}{3}\cdot\frac{11}{2}\)= \(\frac{11}{2}\cdot\left(\frac{17}{3}-\frac{11}{3}\right)\)= \(\frac{11}{2}\cdot\frac{6}{3}\)= \(\frac{11}{2}\cdot2\)=11
1 tháng 2 2022
a: \(=\left(1.25\right)^{16}\cdot8^{16}\cdot8=8\cdot10^{16}\)
b: \(=\left(\dfrac{5}{2}\right)^{13}\cdot4^{13}\cdot4^2=10^{13}\cdot4^2\)
c: \(=\left(0.25\right)^4\cdot8^4\cdot8^2=2^4\cdot8^2=64\cdot16=1024\)
d: \(=\left(\dfrac{1}{2}\right)^{15}\cdot2^{18}=2^3=8\)
e: \(=\left(\dfrac{1}{3}\cdot6\right)^7\cdot\left(\dfrac{1}{2}\right)^7\cdot\dfrac{1}{2}=2^7\cdot\left(\dfrac{1}{2}\right)^7\cdot\dfrac{1}{2}=\dfrac{1}{2}\)
30 tháng 7 2019
\(a;0,25-\frac{1}{2}\left|1,5-x\right|=2,5\)
\(\Leftrightarrow\frac{1}{2}\left|1,5-x\right|=0,25-2,5\)
\(\Leftrightarrow\frac{1}{2}\left|1,5-x\right|=-2,25\)
\(\Leftrightarrow\left|1,5-x\right|=-2,25\cdot2=-4,5\)
Mà \(\left|1,5-x\right|\ge0\)Nên suy ra |1,5-x|=-4,5 là vô lý
\(b;\left|x+\frac{1}{6}\right|\cdot0,75+\frac{1}{4}=2\frac{1}{3}\)
\(\Leftrightarrow\left|x+\frac{1}{6}\right|\cdot\frac{3}{4}=\frac{7}{3}-\frac{1}{4}\)
\(\Leftrightarrow\left|x+\frac{1}{6}\right|\cdot\frac{3}{4}=\frac{25}{12}\)
\(\Leftrightarrow\left|x+\frac{1}{6}\right|=\frac{25}{12}\cdot\frac{4}{3}\)
\(\Leftrightarrow\left|x+\frac{1}{6}\right|=\frac{25}{9}\Leftrightarrow x+\frac{1}{6}=\pm\frac{25}{9}\)
TH1:\(x+\frac{1}{6}=\frac{25}{9}\)
\(\Leftrightarrow x=\frac{25}{9}-\frac{1}{6}=\frac{47}{18}\)
TH2:\(x+\frac{1}{6}=-\frac{25}{9}\)
\(\Leftrightarrow x=-\frac{25}{9}-\frac{1}{6}=\frac{-53}{18}\)
Vậy \(x=\frac{47}{18};-\frac{53}{18}\)
`(2/3-0,25+2)-(2-5/2+1/4)-(2,5-1/3)`
`= 2/3 -1/4 +2-2+ 5/2 -1/4 -5/2 +1/3`
`= (2/3 +1/3) +(-1/4 -1/4) + (2-2) + (5/2-5/2)`
`= 3/3 + (-1/2) + 0 + 0`
`= 1 +(-1/2)`
`= 1/2`
\(\left(\dfrac{2}{3}-0,25+2\right)-\left(2-\dfrac{5}{2}+\dfrac{1}{4}\right)-\left(2,5-\dfrac{1}{3}\right)\\ =\dfrac{2}{3}-0,25+2-2+\dfrac{5}{2}-\dfrac{1}{4}-2,5+\dfrac{1}{3}\\ =\left(\dfrac{2}{3}+\dfrac{1}{3}\right)+\left(\dfrac{5}{2}-2,5\right)+\left(2-2\right)+\left(-\dfrac{1}{4}-0,25\right)\\ =\dfrac{3}{3}+\left(2,5-2,5\right)+0+\left(-\dfrac{1}{4}-\dfrac{1}{4}\right)\\ =1+0+0+\left(-\dfrac{1}{2}\right)=\dfrac{1}{2}\)