a) 8 phần 15 + 5=
b) 4 - 7 phần 3 =
c 1 phần 2 x 8 =
d) 4 phần 9 : 2 =
e) 3 phần 14 : + 1 phần 2 =
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25 tháng 3 2021
a) Ta có: \(\dfrac{-3}{5}x+\dfrac{-7}{4}=\dfrac{3}{10}\)
\(\Leftrightarrow\dfrac{-3}{5}x=\dfrac{3}{10}+\dfrac{7}{4}=\dfrac{41}{20}\)
\(\Leftrightarrow x=\dfrac{41}{20}:\dfrac{-3}{5}=\dfrac{41}{20}\cdot\dfrac{-5}{3}\)
hay \(x=-\dfrac{41}{12}\)
Vậy: \(x=-\dfrac{41}{12}\)
28 tháng 2 2022
a: -3/4x12=-36/4=-9
b: \(=\dfrac{7}{15}\cdot\dfrac{10}{21}=\dfrac{7}{21}\cdot\dfrac{10}{15}=\dfrac{1}{3}\cdot\dfrac{2}{3}=\dfrac{2}{9}\)
c: \(=\dfrac{7}{18}\cdot\dfrac{12}{21}=\dfrac{12}{18}\cdot\dfrac{7}{21}=\dfrac{2}{3}\cdot\dfrac{1}{3}=\dfrac{2}{9}\)
d: \(=\dfrac{11}{15}\cdot\dfrac{5}{22}=\dfrac{11}{22}\cdot\dfrac{5}{15}=\dfrac{1}{2}\cdot\dfrac{1}{3}=\dfrac{1}{6}\)
e: \(=-\dfrac{8}{15}\cdot\dfrac{5}{4}=\dfrac{-40}{60}=\dfrac{-2}{3}\)
f: \(=-15\cdot\dfrac{3}{5}=-9\)
11 tháng 6 2019
\(a,\frac{3}{17}+\frac{-5}{13}+\frac{-18}{35}+\frac{14}{17}+\frac{17}{-35}\)
=\(-\frac{5}{13}+\left(\frac{3}{17}+\frac{14}{17}\right)+\left(\frac{-18}{35}+\frac{-17}{35}\right)\)
= \(-\frac{5}{13}+1+\left(-1\right)\)
=\(-\frac{5}{13}\)
\(b,\frac{-3}{8}.\frac{1}{6}+\frac{3}{-8}.\frac{5}{6}+\frac{-10}{6}\)
=\(\frac{-3}{8}.\left(\frac{1}{6}+\frac{5}{6}\right)+\frac{-10}{6}\)
=\(\frac{-3}{8}.1+\frac{-10}{6}\)
=\(-\frac{49}{24}\)
\(c,\frac{-4}{11}.\frac{5}{15}.\frac{11}{-4}\)
=\(\left(\frac{-4}{11}.\frac{11}{-4}\right).\frac{1}{3}\)
=\(1.\frac{1}{3}=\frac{1}{3}\)
\(d,\frac{13}{8}+\frac{1}{8}:\left(0,75-\frac{1}{2}\right)-25\%.\frac{1}{2}\)
=\(\frac{13}{8}+\frac{1}{8}:\left(\frac{3}{4}-\frac{1}{2}\right)-\frac{1}{4}.\frac{1}{2}\)
=\(\frac{13}{8}+\frac{1}{8}:\frac{1}{4}-\frac{1}{8}\)
=\(\frac{13}{8}+\frac{1}{2}+\frac{-1}{8}\)
=\(\left(\frac{13}{8}+\frac{-1}{8}\right)+\frac{1}{2}\)
=\(\frac{3}{2}+\frac{1}{2}=2\)
\(e,\frac{-1}{2^2}-\left(-2\right)^2-5\)
=\(\frac{-1}{4}-4-5\)
=\(-\frac{37}{4}\)
\(f,\frac{121}{3}-\frac{5}{7}:\left(24-\frac{23}{57}\right)\)
=\(\frac{121}{3}-\frac{5}{7}:\frac{1345}{57}\)
=\(\frac{121}{3}-\frac{57}{1883}\)
\(\approx40,4\)
12 tháng 5 2020
Bài 1 :Bỏ dấu ngoặc
2007-(7-3+4)
= 2007 -7+3-4
= 1999
6+[(-5) + 4 - 1 ]
= 6-5+4-1
=4
5-[(-6+8-2]
= 5+6-8+2
=5
-10+(7-3+1)
= -10 +7-3+1
= -5
Bài 3 Tìm x
\(\dfrac{1}{3} = \dfrac{x}{6}\)
\(<=> x= \dfrac{1.6}{3}\)
\(<=> x=2\)
a) 8/15 + 5
= 8/15 + 5/1
= (8 + 5*15)/15
= (8 + 75)/15
= 83/15
b) 4 - 7/3
= 4/1 - 7/3
= (4*3 - 7)/3
= (12 - 7)/3
= 5/3
c) 1/2 * 8
= 1/2 * 8/1
= (1*8)/(2*1)
= 8/2
= 4
d) 4/9 : 2
= 4/9 * 1/2
= (4*1)/(9*2)
= 4/18
= 2/9
e) 3/14 + 1/2
= (3*2 + 1*14)/(14*2)
= (6 + 14)/28
= 20/28
= 5/7
a) \(\dfrac{8}{15}+5=\dfrac{8}{15}+\dfrac{75}{15}=\dfrac{83}{15}\)
b) \(4-\dfrac{7}{3}=\dfrac{12}{3}-\dfrac{7}{3}=\dfrac{5}{3}\)
c) \(\dfrac{1}{2}\times8=\dfrac{1\times8}{2}=\dfrac{8}{2}=4\)
d) \(\dfrac{4}{9}:2=\dfrac{4}{9}\times\dfrac{1}{2}=\dfrac{4}{18}=\dfrac{2}{9}\)
e) ( Vì bạn ghi dấu không rõ nên mik làm 2 cách, trúng câu nào thì bạn ghi vô nhé. )
+) \(\dfrac{3}{14}:\dfrac{1}{2}=\dfrac{3}{14}\times2=\dfrac{3}{7}\)
+) \(\dfrac{3}{14}+\dfrac{1}{2}=\dfrac{3}{14}+\dfrac{7}{14}=\dfrac{10}{14}=\dfrac{5}{7}\)
Chúc bạn học tốt