Question

[Mai gia bảo]

bài 1: Tìm Phân số lớn nhất \(\dfrac{12}{8};\dfrac{9}{8};\dfrac{8}{8};\dfrac{7}{8}\) 

A. \(\dfrac{12}{8}\)             B.\(\dfrac{9}{8}\)         C. \(\dfrac{8}{8}\)       D. \(\dfrac{7}{8}\)

bài 2: sắp xếp các phân số sau theo thứ tự tăng dần\(\dfrac{5}{7};\dfrac{9}{32};\dfrac{3}{11};\dfrac{3}{4}\)

Answer 1

[『Kuroba ム Tsuki Ryoo ︵²ᵏ⁷』]

`@` `\text {Ans}`

`\downarrow`

`1,`

Ta có: `12 > 9 > 8 > 7`

`=> 12/8 > 9/8 > 8/8 > 7/8`

`=>` Phân số lớn nhất là `12/8`

`=> A.`

`2,`

So sánh \(\dfrac{3}{4}\text{ ; }\dfrac{9}{32}\)

\(\dfrac{3}{4}=\dfrac{3\times8}{4\times8}=\dfrac{24}{32}\)

Vì `24 > 9 `\(\Rightarrow\dfrac{24}{32}>\dfrac{9}{32}\) \(\Rightarrow\dfrac{3}{4}>\dfrac{9}{32}\)

\(\dfrac{9}{32}\text{;}\dfrac{3}{11}\)

\(\dfrac{9}{32}=\dfrac{9\times11}{32\times11}=\dfrac{99}{352}\)

\(\dfrac{3}{11}=\dfrac{3\times32}{11\times32}=\dfrac{96}{352}\)

Vì `99 > 96 \Rightarrow`\(\dfrac{99}{352}>\dfrac{96}{352}\Rightarrow\dfrac{9}{32}>\dfrac{3}{11}\)

Mà \(\dfrac{3}{11}< \dfrac{3}{4}\); \(\dfrac{9}{32}< \dfrac{3}{4}\)

`\Rightarrow`\(\dfrac{3}{4}>\dfrac{9}{32}>\dfrac{3}{11}\) 

So sánh \(\dfrac{5}{7};\dfrac{3}{4}\)

\(\dfrac{5}{7}=\dfrac{5\times4}{7\times4}=\dfrac{20}{28}\)

\(\dfrac{3}{4}=\dfrac{3\times7}{4\times7}=\dfrac{21}{28}\)

Vì \(20< 21\Rightarrow\dfrac{20}{28}< \dfrac{21}{28}\Rightarrow\dfrac{5}{7}< \dfrac{3}{4}\)

So sánh \(\dfrac{5}{7};\dfrac{9}{32}\)

\(\dfrac{5}{7}=\dfrac{5\times32}{7\times32}=\dfrac{160}{224}\)

\(\dfrac{9}{32}=\dfrac{9\times7}{32\times7}=\dfrac{64}{224}\)

Vì \(160>64\Rightarrow\dfrac{160}{224}>\dfrac{64}{224}\Rightarrow\dfrac{5}{7}>\dfrac{9}{32}\)

`\Rightarrow` Thứ tự sắp xếp các phân số tăng dần là: \(\dfrac{3}{11};\dfrac{9}{32};\dfrac{5}{7};\dfrac{3}{4}\)

Answer 2

[Nguyễn Thị Anh Thư]

Bài 1 : A 12/8

Bài 2 : Theo thứ tự tăng dần là : 3/11, 9/32, 5/7, 3/4