(3.4.2¹⁶)²/11.2¹³.4¹¹-16⁰
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
11 tháng 8 2019
*Bài làm:
\(\frac{3.4.2^{16}}{11.2^{13}.4^{11}-16^9}\)
= \(\frac{3.2^2.2^{16}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
= \(\frac{3.2^{18}}{11.2^{13}.2^{22}-2^{36}}\)
= \(\frac{3.2^{18}}{11.2^{35}-2^{36}}\)
= \(\frac{3.2^{18}}{2^{18}.\left(11.2^{17}-2^{18}\right)}\)
= \(\frac{3}{\left(11.2^{17}-2^{18}\right)}\)
= \(\frac{3}{2^{17}.\left(11-2\right)}\)
= \(\frac{3}{2^{17}.9}\)
= \(\frac{1}{2^{17}.3}\)
*Vậy \(\frac{3.4.2^{16}}{11.2^{13}.4^{11}-16^9}\) = \(\frac{1}{2^{17}.3}\) .
HH
1
C
8 tháng 1
\(\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\dfrac{\left(3.2^2.2^{16}\right)^2}{11.2^2.\left(2^2\right).11-\left(2^4\right)^9}\)
\(=\dfrac{3^2.\left(2^2\right)^2.\left(2^{16}\right)^2}{11.2^2.2^{22}-2^{36}}\)
\(=\dfrac{3^2.2^4.2^{32}}{11.2^{24}-2^{36}}\)
\(=\dfrac{3^2.2^{34}}{11.2^{24}-2^{36}}\)
\(=\dfrac{3^2.2^{24}.2^{10}}{11.2^{24}-2^{12}.2^{24}}\)
\(=\dfrac{3^2.2^{24}.2^{10}}{\left(11-2^{12}\right).2^{24}}\)
\(=\dfrac{3^2.2^{10}}{11-2^{12}}\)
C
1
10 tháng 1 2022
\(=\dfrac{3^2\cdot2^{36}}{11\cdot2^{13}\cdot2^{22}-2^{36}}=\dfrac{3^2\cdot2^{36}}{2^{35}\cdot9}=2\)
5 tháng 8 2018
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{\left(3.2^{18}\right)^2}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)
\(=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{3^2.2^{36}}{2^{35}.9}=\frac{3^2.2^{36}}{2^{35}.3^2}=2\)
DG
0
DD
1
27 tháng 9 2016
= 3^2 . 2^4 . 2^32 / 11.2^13 .2^22 - 2^36
=3^2 . 2^36 / 11.2^35 - 2^36
=3^2 . 2^36 / 2^35 . ( 11+2)
= 9 . 2^36 / 2^35 . 13
= 9 . 2 / 13 = 18/13
PC
0
LT
1
30 tháng 1 2018
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}=\frac{2^{35}\left(9+2\right)}{2^{35}\left(11-2\right)}=\frac{11}{9}\)
MQ
0
Câu này em viết đề lại cho chính xác giùm
Sửa đề: \(\dfrac{\left(3\cdot4\cdot2^{16}\right)^2}{11\cdot2^{13}\cdot4^{11}-16^{10}}\)\(=\dfrac{\left(3\cdot2^{18}\right)^2}{11\cdot2^{13}\cdot4^{11}-16^{10}}=\dfrac{3\cdot2^{36}}{2^{35}\left(11-2^5\right)}=\dfrac{2\cdot3}{11-32}=\dfrac{-6}{21}=\dfrac{-2}{7}\)