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15 tháng 3 2017

\(\frac{10}{56}+\frac{10}{140}+\frac{10}{260}+......+\frac{10}{1400}\)

\(=\frac{5}{4.7}+\frac{5}{7.10}+\frac{5}{10.13}+.....+\frac{5}{25.28}\)

\(=\frac{5}{3}\left(\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+......+\frac{3}{25.28}\right)\)

\(=\frac{5}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+......+\frac{1}{25}-\frac{1}{28}\right)\)

\(=\frac{5}{3}\left(\frac{1}{4}-\frac{1}{28}\right)\)

\(=\frac{5}{3}.\frac{3}{14}\)

\(=\frac{5}{14}\)

13 tháng 4 2016

Doãn Hải Anh mk lớp 7 nên quên òi 

9 tháng 8 2016

S = 10/56 + 10/140 + 10/260 + ....... + 10/1400

S = 5/28 + 5/70 + 5/130 + 5/700

3S/5 = 3/4 x 7 + 3/7 x 10 + 30/10 x 13 + ....... + 3/25 x 28

3S/5 = 1/4 - 1/7 + 1/7 - 1/10 + 1/10 - 1/13 + ........ + 1/25 - 1/28

3S/5 = 1/4 - 1/28

3S/5 = 3/14

S = 3/14 x 5/3

S = 5/14

Vậy S = 5/14

9 tháng 8 2016

\(S=\frac{10}{56}+\frac{10}{140}+\frac{10}{260}+\frac{10}{1400}\)

\(S=\frac{5}{28}+\frac{5}{70}+\frac{5}{130}+...+\frac{5}{700}\)

\(S=\frac{5}{4.7}+\frac{5}{7.10}+\frac{5}{10.13}+...+\frac{5}{25.28}\)

\(S=5.\left(\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+...+\frac{3}{25.28}\right)\)

\(S=5.\left(\frac{1}{4.7}+\frac{1}{7.10}+\frac{1}{10.13}+...+\frac{1}{25.28}\right)\)

\(S=5.\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{25}-\frac{1}{28}\right)\)

\(S=5.\left(\frac{1}{4}-\frac{1}{28}\right)\)

\(S=5.\frac{3}{14}=\frac{15}{14}\)

Vậy \(S=\frac{15}{14}\)

M = 10/56+10/140+10/260+10/1400

M= 5/28+5/70+5/130+5/700

3M/5=1/4-1/7+1/7-1/10+1/10-1/13+...+1/25

3M/5 = 3/14

M= 3/14+5/3=5/14

Mình ghi nhầm

 

31 tháng 3 2019

S= 10/56+10/140+.....+10/1400

S= 5/28+5/70+.....+5/700

S= 5/4.7+5/7.10+......+5/25.28

S=5/3( 1/4-1/7+1/7-1/10+......+1/25-1/28)

S= 5/3.(1/4-1/28)

S= 5/3. 3/14

S= 15/42

VẬY S= 15/ 42

18 tháng 6 2016

\(\frac{10}{56}+\frac{10}{140}+...+\frac{10}{1400}\)

\(=\frac{5}{28}+\frac{5}{70}+...+\frac{5}{700}\)

\(=\frac{5}{3}\left(\frac{3}{28}+\frac{3}{70}+...+\frac{3}{700}\right)\)

\(=\frac{5}{3}\left(\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{25.28}\right)\)

\(=\frac{5}{3}.\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{25}-\frac{1}{28}\right)\)

\(=\frac{5}{3}\left(\frac{1}{4}-\frac{1}{28}\right)\)

\(=\frac{5}{3}.\frac{3}{14}=\frac{5}{14}\)

25 tháng 4 2016

ai k mình thì nói cho mình biết để mình k lại

25 tháng 4 2016

\(=\frac{5}{28}+\frac{5}{70}+\frac{5}{130}+...+\frac{5}{700}\)

\(=\frac{5}{3}\left(\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{25.28}\right)\)

\(=\frac{5}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{25}-\frac{1}{28}\right)\)

\(=\frac{5}{3}\left(\frac{1}{4}-\frac{1}{28}\right)\)

\(=\frac{5}{3}\times\frac{3}{14}\)

\(=\frac{5}{14}\)

19 tháng 3 2016

A =  10/56 + 10/140 + 10/260 + .......+ 10/1400

A = 5/28 + 5/70 + 5/130 +.........+ 5/700

3A/5 = 3/4.7 + 3/7.10 + 3/10.13 +.......+ 3/25.28

3A/5 = 1/4 - 1/7 + 1/7 - 1/10 + 1/10 - 1/13 +........+ 1/25 - 1/28

3A/5 = 1/4 - 1/28

3A/5 = 3/14

A = 3/14 . 5/3

A = 5/14

Vậy A = 5/14

19 tháng 3 2016

A= 5/3.(3/28+3/70+3/130+...+3/700)                                                                                                               A=5/3.(3/4.7+3/7.10+3/10.13+...+3/25.28)

A=5/3.(1/4-1/7+1/7-1/10+1/10-1/13+...+1/25-1/28)

A=5/3(1/4-1/28)

A=5/3.(7/28-1/28)

A=5/3.3/14

A=5/14

3 tháng 4 2016

S = 5/28 + 5/70 + 5/130 + ..... + 5/700

S = 5 / 4x7 + 5 / 7x10 + 5 / 10x13 + ..... + 5 / 25x28

SX3 / 5 = 3 / 4x7 + 3 / 7x10 + ....... + 3 / 25x28

Sx3/5=1/4-1/7+1/7-1/10+1/10+.....+1/25-1/28

Sx3/5=1/4+(1/7-1/7)+(1/9-1/9)+.....+(!/25-1/25)-1/28

Sx3/5=1/4-1/28

Sx3/5=3/14

S = 3/14: 3/5

S = 5/14

Vậy S = 5 /14

tk mk nhé !

3 tháng 4 2016

\(C=\frac{10}{56}+\frac{10}{140}+\frac{10}{260}+...+\frac{10}{1400}=10\left(\frac{1}{56}+\frac{1}{140}+\frac{1}{260}+...+\frac{10}{1400}\right)\)

\(C=\frac{10}{2}\left(\frac{1}{28}+\frac{1}{70}+\frac{1}{130}+...+\frac{1}{700}\right)=5\left(\frac{1}{4\cdot7}+\frac{1}{7\cdot10}+\frac{1}{10\cdot13}+...+\frac{1}{25\cdot28}\right)\)

\(C=5\cdot\frac{1}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{25}-\frac{1}{28}\right)\)

\(C=\frac{5}{3}\cdot\left(\frac{1}{4}-\frac{1}{28}\right)=\frac{5}{3}\cdot\frac{3}{14}=\frac{5}{14}\)