d) 52x-3 – 2.52 = 52 .3
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52x-3-2.52 =52 . 3
⇔52x-1.52-2.52=52.3
⇔52.(52x-1-2)=52.3
⇔52x-1-2=3
⇔52x-1=5
⇔2x-1=1
⇔2x=2
⇔x=1
vay x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
a). 5x = 125
=>5x = 53
=> x = 3
b) 32x = 81
=> 32x = 34
=> 2x = 4
=> x = 2
c). 52x-3 – 2.52 = 52 .3
=>52x: 53 = 52 .3 + 2.52
=>52x: 53 = 52 .5
=>52x = 52 .5.53
=>52x = 56
=> 2x = 6
=> x=3
a) 5x = 125
x = 125 : 5
x = 25
b) 32x = 81
x = 81 : 32
x = 81/ 32
c) 52x - 3 - 2.52 = 52.3
52x - 3 - 104 = 156
x - 3 - 104 = 156 : 52
x - 3 - 104 = 3
x - 3 = 3 + 104
x - 3 = 107
x = 107 + 3
x = 110
Ko chắc lắm , sai thì Sorry nhé .
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(8x+56:14=60\)
\(\Rightarrow8x+4=60\)
\(\Rightarrow8x=56\)
\(\Rightarrow x=\dfrac{56}{8}\)
\(\Rightarrow x=7\)
b) Mình làm rồi nhé !
c) \(41-2^{x+1}=9\)
\(\Rightarrow2^{x+1}=41-9\)
\(\Rightarrow2^{x+1}=32\)
\(\Rightarrow2^{x+1}=2^5\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=4\)
d) \(3^{2x-4}-x^0=8\)
\(\Rightarrow3^{2x-4}-1=8\)
\(\Rightarrow3^{2x-4}=9\)
\(\Rightarrow3^{2x-4}=3^2\)
\(\Rightarrow2x-4=2\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
g) \(65-4^{x+2}=2014^0\)
\(\Rightarrow65-4^{x+2}=1\)
\(\Rightarrow4^{x+2}=64\)
\(\Rightarrow4^{x+2}=4^3\)
\(\Rightarrow x+2=3\)
\(\Rightarrow x=1\)
i) \(120+2\left(4x-17\right)=214\)
\(\Rightarrow2\left(4x-17\right)=214-120\)
\(\Rightarrow2\left(4x-17\right)=94\)
\(\Rightarrow4x-17=47\)
\(\Rightarrow4x=47+17\)
\(\Rightarrow4x=64\)
\(\Rightarrow x=16\)
a: \(8x+56:14=60\)
=>8x+4=60
=>8x=60-4=56
=>x=56/8=7
b: \(5^{2x-3}-2\cdot5^2=5^2\cdot3\)
=>\(5^{2x-3}=5^2\cdot3+2\cdot5^2=5^3\)
=>2x-3=3
=>2x=6
=>x=3
c: \(41-2^{x+1}=9\)
=>\(2^{x+1}=41-9=32\)
=>x+1=5
=>x=4
d: \(3^{2x-4}-x^0=8\)
=>\(3^{2x-4}-1=8\)
=>\(3^{2x-4}=8+1=9\)
=>2x-4=2
=>2x=6
=>x=3
g: \(65-4^{x+2}=2014^0\)
=>\(65-4^{x+2}=1\)
=>\(4^{x+2}=65-1=64\)
=>x+2=3
=>x=1
i: 120+2(4x-17)=214
=>2(4x-17)=214-120=94
=>4x-17=94/2=47
=>4x=64
=>\(x=\dfrac{64}{4}=16\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Rightarrow5^{2x-3}=5^2\cdot3+5^2\cdot2=5^2\cdot5=5^3\\ \Rightarrow2x-3=3\\ \Rightarrow x=3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(5^{2x-3}-2.5^2=5^2.3\)
\(\Rightarrow5^{2x-3}-50=75\)
\(\Rightarrow5^{2x-3}=125=5^3\)
\(\Rightarrow2x-3=3\Rightarrow2x=6\Rightarrow x=3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
5²ˣ⁻³ - 2.5² = 5².3
5²ˣ⁻³ - 2.25 = 25.3
5²ˣ⁻³ - 50 = 75
5²ˣ⁻³ = 75 + 50
5²ˣ⁻³ = 125
5²ˣ⁻³ =5³
2x - 3 = 3
2x = 3 + 3
2x = 6
x = 6 : 2
x = 3
\(5^{2x-3}-2.5^2=5^2.3\)
\(\Leftrightarrow5^{2x}:5^3-50=75\)
\(\Leftrightarrow5^{2x}:5^3=75+50\)
\(\Leftrightarrow5^{2x}:5^3=125\)
\(\Leftrightarrow5^{2x}=125.5^3\)
\(\Leftrightarrow5^{2x}=5^3.5^3\)
\(\Leftrightarrow5^{2x}=5^6\)
\(\Leftrightarrow2x=6\)
\(\Leftrightarrow x=6:2\)
\(\Leftrightarrow x=3\)
Vậy x=3
![](https://rs.olm.vn/images/avt/0.png?1311)
b) 32x = 81
32x = 34
=> 2x = 4
=> x = 2
a). 52x-3 – 2.52 = 52 .3
52x: 53 = 52 .3 + 2.52
52x: 53 = 52 .5
52x = 52 .5.53
52x = 56
=> 2x = 6
=> x=3
![](https://rs.olm.vn/images/avt/0.png?1311)
\(5^{2x-3}-2.5^2=5^2.3\\ 5^{2x-3}=5^2.3+5^2.2\\ 5^{2x-3}=5^2.\left(3+2\right)\\ 5^{2x-3}=5^2.5\\ 5^{2x-3}=5^3\\ 2x-3=3\\ x=3\)
`5^[2x-3]-2.5^2=5^2.3`
`5^[2x-3]-2.25=25.3`
`5^[2x-3]-50=75`
`5^[2x-3]=75+50=125`
`5^[2x-3]=5^3`
`2x-3=3`
`2x=3+3=6`
`x=6:2=3`