Tìm y biết:9/4-yx5/6=1/2+2/3
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1 tháng 11 2016
\(\frac{9}{4}-y.\frac{5}{6}=\frac{1}{2}+\frac{2}{3}\)
\(\frac{9}{4}-y.\frac{5}{6}=\frac{7}{6}\)
\(y.\frac{5}{6}=\frac{9}{4}-\frac{7}{6}\)
\(y.\frac{5}{6}=\frac{13}{12}\)
\(y=\frac{13}{12}:\frac{5}{6}\)
\(y=\frac{13}{10}\)
2 tháng 1 2017
y.5 + y : 1/2 + y : 1/3
= y.5 + y.2 + y.3
= y.(5 + 2 + 3)
= y.10
DN
2
NK
31 tháng 12 2015
y x 5 + (2 + 4 + 6 +...+ 18) = 270
=> y x 5 + (18 + 2) x 9 : 2 = 270 (Công thức tính tổng)
=> y x 5 + 20 x 9 : 2 = 270
=> y x 5 + 180 : 2 = 270
=> y x 5 + 90 = 270
=> y x 5 = 270 - 90
=> y x 5 = 180
=> y = 180 : 5
=> y = 36
Vậy...
10 tháng 1 2017
\(\frac{9}{4}-y\times\frac{5}{6}=\frac{1}{2}+\frac{2}{3}\)
\(\frac{9}{4}-y\times\frac{5}{6}=\frac{7}{6}\)
\(y\times\frac{5}{6}=\frac{9}{4}-\frac{7}{6}\)
\(y\times\frac{5}{6}=\frac{13}{12}\)
\(y=\frac{13}{12}:\frac{5}{6}\)
\(y=\frac{13}{10}\)
VT
7 tháng 10 2016
9/4 - y × 5/6 = 1/2 + 1/3
9/4 - y × 5/6 = 5/6
y × 5/6 = 9/4 - 5/6
y × 5/6 = 17/12
y = 17/12 : 5/6
y = 17/10
MY
0
YN
5 tháng 10 2021
a) \(\left(3x-5\right)\left(5-3x\right)+9\left(x+1\right)^2=30\)
\(\Rightarrow15x-9x^2-25+15x+9\left(x^2+2x+1\right)-30=0\)
\(\Rightarrow30x-9x^2-25+9x^2+18x+9-30=0\)
\(\Rightarrow48x-46=0\)
\(\Rightarrow x=\frac{23}{24}\)
b) \(\left(x+4\right)^2-\left(x+1\right)\left(x-1\right)=16\)
\(\Rightarrow\left(x^2+8x+16\right)-\left(x^2-1\right)=16\)
\(\Rightarrow x^2+8x+16-x^2+1=16\)
\(\Rightarrow8x+17=16\)
\(\Rightarrow8x=-1\)
\(\Rightarrow x=\frac{-1}{8}\)
YN
5 tháng 10 2021
c) \(\left(y-2\right)^3-\left(y-3\right)\left(y^2+3y+9\right)+6\left(y+1\right)^2=49\)
\(\Rightarrow\left(y-2\right)^3-\left(y^3-3^3\right)+6\left(y^2+2y+1\right)=49\)
\(\Rightarrow y^3-6y^2+12y-8-y^3+27+6y^2+12y+6=49\)
\(\Rightarrow\left(y^3-y^3\right)+\left(-6y^2+6y^2\right)+\left(12y+12y\right)+\left(-8+27+6\right)=49\)
\(\Rightarrow24y+25=49\)
\(\Rightarrow24y=24\)
\(\Rightarrow y=1\)
d) \(\left(y+3\right)^3-\left(y+1\right)^3=56\)
\(\Rightarrow\left(y+3-y-1\right)[\left(y+3\right)^2+\left(y+3\right)\left(y+1\right)+\left(y+1\right)^2]=56\)
\(\Rightarrow2\left(y^2+6y+9+y^2+4y+3+y^2+2y+1\right)=56\)
\(\Rightarrow3y^2+12y+13=28\)
\(\Rightarrow\left(3y^2+15y\right)-\left(3y+15\right)=0\)
\(\Rightarrow3y\left(y+5\right)-3\left(y+5\right)=0\)
\(\Rightarrow3\left(y-1\right)\left(y+5\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-1=0\\x+5=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\x=-5\end{cases}}\)
\(\frac{9}{4}-y.\frac{5}{6}=\frac{1}{2}+\frac{1}{3}\)
\(\frac{9}{4}-y.\frac{5}{6}=\frac{5}{6}\)
\(y.\frac{5}{6}=\frac{9}{4}-\frac{5}{6}\)
\(y.\frac{5}{6}=\frac{17}{12}\)
\(y=\frac{17}{12}:\frac{5}{6}\)
\(y=\frac{17}{10}\)
\(\frac{9}{4}\)- y x \(\frac{5}{6}\)= \(\frac{1}{2}\)+ \(\frac{2}{3}\) = \(\frac{9}{4}\)- \(\frac{1}{2}\)- \(\frac{2}{3}\)= y x \(\frac{5}{6}\)
y x \(\frac{5}{6}\)= \(\frac{13}{12}\)
y = \(\frac{13}{12}\)x \(\frac{6}{5}\)= \(\frac{13}{10}\)