Bai 1: A= \(\dfrac{\sqrt{x}+1}{\sqrt{x}-1}\) B= \(\left(\dfrac{\sqrt{X}+1}{\sqrt{X}-1}-\dfrac{\sqrt{X}-1}{\sqrt{X}+1}\right)\) : \(\dfrac{\sqrt{X}}{\sqrt{X}-1}\) ( X> 0, X≠1)A) Rut Bb) Tim x de gia tri cua A va B trai dauBai 2: cho hpt \(\left\{{}\begin{matrix}x-2y=4m-5\\2x+y=3m\end{matrix}\right.\)a) giai pt khi m=3b) Tim de pt co nghiem (x,y) thoa man \(\dfrac{2}{x}-\dfrac{1}{y}=-1\)(mink dag can...
Đọc tiếp
Bai 1: A= \(\dfrac{\sqrt{x}+1}{\sqrt{x}-1}\) B= \(\left(\dfrac{\sqrt{X}+1}{\sqrt{X}-1}-\dfrac{\sqrt{X}-1}{\sqrt{X}+1}\right)\) : \(\dfrac{\sqrt{X}}{\sqrt{X}-1}\) ( X> 0, X≠1)
A) Rut B
b) Tim x de gia tri cua A va B trai dau
Bai 2: cho hpt \(\left\{{}\begin{matrix}x-2y=4m-5\\2x+y=3m\end{matrix}\right.\)
a) giai pt khi m=3
b) Tim de pt co nghiem (x,y) thoa man \(\dfrac{2}{x}-\dfrac{1}{y}=-1\)
(mink dag can gap)
Bài 2:
a) Thay m=3 vào hệ pt, ta được:
\(\left\{{}\begin{matrix}x-2y=7\\2x+y=9\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x-4y=14\\2x+y=9\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}-5y=5\\x-2y=7\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=-1\\x=7+2y=5\end{matrix}\right.\)
Vậy: Khi m=3 thì hệ phương trình có nghiệm duy nhất là (x,y)=(5;-1)