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\(\dfrac{2}{67}-\left(\dfrac{3}{7}+\dfrac{2}{67}\right)\\ =\dfrac{2}{67}-\dfrac{215}{469}\\ =\dfrac{-3}{7}\)
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a) \(...=2^{14}:\left(2^6.2^5\right)=2^{14}:2^{11}=2^3=8\)
b) \(...=5^{25}.5^2:5^{24}=5^{27}:5^{24}=5^3=125\)
c) \(...=2^{22}:2^2-2^{20}=2^{20}-2^{20}=0\)
d) \(...=3^6:3^3=3^3=27\)
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\(=\dfrac{x^4+4x^2-3x^2-12+2x+1}{x^2+4}\)
\(=x^2-3+\dfrac{2x+1}{x^2+4}\)
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\(\left[\left(3-x\right)^5-7\left(x-3\right)^4-4\left(x-3\right)^2\right]:\left(x^2-6x+9\right)=\left[\left(3-x\right)^5-7\left(3-x\right)^4-4\left(3-x\right)^2\right]:\left(3-x\right)^2=\left(3-x\right)^2\left[\left(3-x\right)^3-7\left(3-x\right)^2-4\right]:\left(3-x\right)^2=\left(3-x\right)^3-7\left(3-x\right)^2-4=27-27x+9x^2-x^3-63+42x-7x^2-4=-x^3+2x^2+15x-40\)
\(\dfrac{\left(3-x\right)^5-7\left(x-3\right)^4-4\left(x-3\right)^2}{x^2-6x+9}\)
\(=\dfrac{-\left(x-3\right)^5-7\left(x-3\right)^4-4\left(x-3\right)^2}{\left(x-3\right)^2}\)
\(=-\left(x-3\right)^3-7\left(x-3\right)^2-4\)
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\(4\frac{2}{5}+2\frac{3}{7}-2\frac{2}{5}+5\frac{4}{7}\)
\(=\left(4\frac{2}{5}-2\frac{2}{5}\right)+\left(2\frac{3}{7}+5\frac{4}{7}\right)\)
\(=2+8\)
=10
4 2/5 + 2 3/7 - 2 2/5 + 5 4/7
= 22/5 + 17/7 -12/5 + 39/7
= ( 22/5 - 12/5 ) + ( 17/7 + 39/7 )
= 2 + 8
= 10
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\(A=4^3-6^3:6^2+11\cdot3^2\\ =64-6+11\cdot9\\ =58+99\\ =157\\ B=5\cdot35-5^2\cdot2\\ =5\cdot\left(35-10\right)\\ =5\cdot25\\ =125\\ C=\left(7-3^3:3^2\right):2^2+99\\ =\left(7-3\right):4+99\\ =4:4+99\\ =1+99=100\\ D=2^7:2^2+5^4:5^3\cdot2^4-3\cdot2^5\\ =2^5+5\cdot2^4-6\cdot2^4\\ =2^4\cdot\left(2+5-6\right)\\ =2^4\\ =16\)
![](https://rs.olm.vn/images/avt/0.png?1311)
bài này dễ mà bạn bạn chỉ cần đổi ra rồi tính bình thường là đc mà
Bài 1:
\(A=2^2\cdot3-4\\ =4\cdot3-4\\ =4\cdot\left(3-1\right)\\ =4\cdot2\\ =8\\ B=16-2^3\cdot2\\ =16-16\\ =0\\ C=4^2-4\cdot2\\ =4\cdot\left(4-2\right)\\ =4\cdot2\\ =8\\ D=3^3-3\cdot3^2\\ =3^3-3^3\\ =0\)
9725 : 5=1945
7120:4=1780
2 CÂU CUỐI BẠN TỰ LÀM NHA, MIK BẬN RỒI