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Ta có: \(\left(2\dfrac{2}{15}\cdot\dfrac{9}{17}\cdot\dfrac{3}{32}\right):\left(-\dfrac{3}{17}\right)\)
\(=\left(\dfrac{32}{15}\cdot\dfrac{9}{17}\cdot\dfrac{3}{32}\right):\left(-\dfrac{3}{17}\right)\)
\(=-\dfrac{\dfrac{32}{15}\cdot\dfrac{9}{17}\cdot\dfrac{3}{32}}{\dfrac{3}{17}}=\dfrac{-32}{15}\cdot\dfrac{9}{32}=-\dfrac{3}{5}\)
1) $(-81)\cdot27-3^4\cdot(-77)$
$=(-81)\cdot27-81\cdot(-77)$
$=-81\cdot[27+(-77)]$
$=-81\cdot(27-77)$
$=-81\cdot(-50)$
$=81\cdot50$
$=4050$
2) $(-16)\cdot32-(-4)^2\cdot18$
$=(-16)\cdot32-16\cdot18$
$=-16\cdot(32+18)$
$=-16\cdot50$
$=-800$
3) $(-2)^4\cdot289-16\cdot189$
$=16\cdot289+16\cdot(-189)$
$=16\cdot[289+(-189)]$
$=16\cdot(289-189)$
$=16\cdot100$
$=1600$
4) $41\cdot(-18)+41\cdot(-81)-41$
$=1\cdot(-18)+41\cdot(-81)+41\cdot(-1)$
$=41\cdot[(-18)+(-81)+(-1)]$
$=41\cdot(-18-81-1)$
$=41\cdot(-99-1)$
$=41\cdot(-100)$
$=-4100$
5) $17\cdot(-37)-23\cdot37-46\cdot(-37)$
$=17\cdot(-37)+23\cdot(-37)-46\cdot(-37)$
$=-37\cdot(17+23-46)$
$=-37\cdot(40-46)$
$=-37\cdot(-6)$
$=37\cdot6$
$=222$
6) $-48+48\cdot(-78)+48\cdot(-21)$
$=48\cdot(-1)+48\cdot(-78)+48\cdot(-21)$
$=48\cdot[(-1)+(-78)+(-21)]$
$=48\cdot(-1-78-21)$
$=48\cdot(-79-21)$
$=48\cdot(-100)$
$=-4800$
7) $29\cdot(-13)+27\cdot(-29)+(-14)\cdot(-29)$
$=-29\cdot13+27\cdot(-29)+(-14)\cdot(-29)$
$=-29\cdot[13+27+(-14)]$
$=-29\cdot(40-14)$
$=-29\cdot26$
$=-754$
$\text{#}Toru$
66x17+32x17+17x2
=(66+32+2)x17
=100x17
=1700
32x20+32x29+32x11+60x68
=32x(20+29+11+68)
=32x100
=3200
12x25x2+24x25+3x50x8
=25x(24+24+48) (mik tách 50 ra là 2x25 rùi nhân 3x2x8 ra 48 còn 24 ở đầu thì mik lấy 12x2=24 nha )
=25x100
=2500
M=2+4+6+...+98+100
có 4-2=2
6-4=2
100-98=2
có số liền trước kém số liền sau 2 đơn vị
SSH là:
(100-2):2+1=50 (số )
Tổng M là :
(100+2)x50 :2= 2550
vậy M =2550
66 x 17 + 32 x 17 + 17 x 2
= 17 ( 66 + 32 + 2 )
= 17 x 100 = 1700
32 x 20 + 32 x 29 + 32 x 11 + 60 x 68
= 32 x ( 20 + 29 + 11 ) + 60 x 68
= 32 x 60 + 60 x 68
= 60 x ( 32 + 68 )
= 60 x 100 = 6000
12 x 25 x 2 + 24 x 25 + 3 x 50 x 8
= 24 x 25 + 24 x 25 + 48 x 25
= 25 ( 24 + 24 + 48 )
= 25 x 96
a) \(31\cdot72+\left(-31\right)\cdot70-2\cdot70\)
\(=31\cdot72-31\cdot70-2\cdot70\)
\(=31\cdot\left(72-70\right)-2\cdot70\)
\(=31\cdot2-2\cdot70\)
\(=2\cdot\left(31-70\right)\)
\(=2\cdot-39\)
\(=-78\)
b) \(25\cdot\left(32+17\right)-32\cdot\left(25+47\right)\)
\(=25\cdot32+25\cdot17-32\cdot25-32\cdot47\)
\(=25\cdot\left(32-32+17\right)-32\cdot47\)
\(=25\cdot17-32\cdot47\)
\(=425-1504\)
\(=-1079\)
a)\(\frac{-5}{18}+\frac{32}{45}-\frac{9}{10}\)
\(=\frac{-25}{90}+\frac{64}{90}-\frac{81}{90}\)
\(=-\frac{42}{90}=-\frac{7}{15}\)
b)\(\frac{3}{4}-\left(-\frac{5}{8}\right)+\frac{9}{4}-\frac{3}{16}\)
\(=\frac{3}{4}+\frac{5}{8}+\frac{9}{4}-\frac{3}{16}\)
\(=\frac{12}{16}+\frac{10}{16}+\frac{36}{16}-\frac{3}{16}\)
\(=\frac{58}{16}=\frac{29}{8}\)
c) \(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{17}{14}=\frac{11}{125}\)
d) \(\frac{-2}{5}-\frac{3}{10}-\left(-\frac{1}{2}\right)\)
\(=-\frac{2}{5}-\frac{3}{10}+\frac{1}{2}\)
\(=-\frac{4}{10}-\frac{3}{10}+\frac{5}{10}\)
\(=-\frac{2}{10}=-\frac{1}{5}\)
\(\dfrac{2^{39}+2^{35}}{2^{33}\cdot4}\)
\(=\dfrac{2^{35}\cdot\left(2^4+1\right)}{2^{33}\cdot2^2}\)
\(=\dfrac{2^{35}\cdot\left(16+1\right)}{2^{35}}\)
\(=17\)
\(---\)
\(\dfrac{4^{17}+4^3}{4^{16}+4^2}\)
\(=\dfrac{4^3\cdot\left(4^{14}+1\right)}{4^2\cdot\left(4^{14}+1\right)}\)
\(=4\)
#\(Toru\)