Tìm x biết 4 - 2 x 3 > 4
A. x < 30
B. x > −30
C. x < −30
D. x > 30
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\(Ư\left(30\right)=\left\{1;2;3;5;6;10;15;30\right\}\\ \Rightarrow x=5\left(B\right)\\ B\left(8\right)=\left\{0;8;16;24;32;...\right\}\\ \Rightarrow x=24\left(B\right)\)
a) 2x-30=-14
2x=(-14)+30
2x=16
x=16:2
x=8
b) 230-4*(x+5)=30
4*(x+5)=230-30
4*(x+5)=200
x+5=200:4
x+5= 50
x=50-5
x=45
a, Ta có :\(-30+\left(25-x\right)=-1\)
\(\Leftrightarrow\left(-30\right)+25-x=-1\)
\(\Leftrightarrow25-x=\left(-1\right)-\left(-30\right)\)
\(\Leftrightarrow25-x=29\\ \Leftrightarrow x=25-29\)
\(\Leftrightarrow x=\left(-4\right)\)
Vậy \(x=-4\)
b,Ta có :\(\left(x+5\right)+\left(x-9\right)=x+2\)
\(\Leftrightarrow x+5+x-9=x+2\)
\(\Leftrightarrow2.x+\left(5-9\right)=x+2\)
\(\Leftrightarrow\) \(2.x+\left(-4\right)=x+2\)
\(\Leftrightarrow2.x-x=4+2\)
\(\Leftrightarrow x=6\)
Vậy \(x=6\)
a) 467 + x = 877 – 162
467 + x = 715
x = 715 – 467
x = 248
b) x – 214 = 61 + 345
x – 214 = 406
x = 406 + 214
x = 620
c) x : 5 = 10 × 2
x : 5 = 20
x = 20 × 5
x = 100
d) x × 4 = 30 – 10
x × 4 = 20
x = 20 : 4
x = 5
a)
\(x-5=-1\)
\(x=-1+5\)
\(x=4\)
b)
\(x+30=4\)
\(x=4-30\)
\(x=-26\)
c)
\(x-(-24)=3\)
\(x+24=3\)
\(x=3-24\)
\(x=-21\)
d)
\(22-(-x)=12\)
\(22+x=12\)
\(x=12-22\)
\(x=-10\)
e)
\(( x + 5 ) + ( x - 9 ) = x + 2\)
\(x+5+x-9=x+2\)
\(x+x-x=2+9-5\)
\(x=6\)
f)
\(( 27 - x ) + ( 15 + x ) = x - 24\)
\(27-x+15+x=x-24\)
\(-x+x-x=-24-15-27\)
\(-x=-66\)
\(x=66\)
x - 5 = -1 x - (-24) = 3
x = -1 + 5 x + 24 = 3
x = 4 x = 3 - 24
x + 30 = 4 x = - 21
x = 4 - 30 22 - ( -x) = 12
x = - 26 22 + x = 12
x + 5 + ( x - 9) = x + 2 x = 12 - 22
x + 5 + x - 9 = x + 2 x = -10
2x - x = 2 - 5 + 9 ( 27 - x) + ( 15 + x) = x - 24
x = - 3 + 9 27 - x + 15 + x = x - 24
x = 6 27 + 15 = x - 24
x - 24 = 42
x = 42 + 24
x = 66
a) Ta có: \(x+\left(-5\right)=-\left(-7\right)\)
\(\Leftrightarrow x-5=7\)
\(\Leftrightarrow x=7+5=12\)
Vậy: x=12
b) Ta có: \(-5\cdot\left|x\right|=-30\)
\(\Leftrightarrow\left|x\right|=-30:\left(-5\right)=6\)
hay \(x\in\left\{6;-6\right\}\)
Vậy: \(x\in\left\{6;-6\right\}\)
c) Ta có: \(2x+20=-22\)
\(\Leftrightarrow2x=-22-20=-42\)
hay x=-21
Vậy: x=-21
d) Ta có: \(\left|x+2\right|=4\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2=4\\x+2=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-6\end{matrix}\right.\)
Vậy: \(x\in\left\{2;-6\right\}\)
a) \(75\%\times x+\frac{3}{4}\times x+x=30\)
\(\frac{3}{4}\times x+\frac{3}{4}\times x+x=30\)
\(x\times\left(\frac{3}{4}+\frac{3}{4}+1\right)=30\)
\(x\times\frac{5}{2}=30\)
\(x=30\div\frac{5}{2}\)
\(x=30\times\frac{2}{5}\)
\(x=12\)
b) \(x-40\%=36\)
\(x-\frac{2}{5}=36\)
\(x=36+\frac{2}{5}\)
\(x=36\frac{2}{5}\)
c) \(30\%\times x+x=52\)
\(\frac{3}{10}\times x+x=52\)
\(x\times\left(\frac{3}{10}+1\right)=52\)
\(x\times\frac{13}{10}=52\)
\(x=52\div\frac{13}{10}\)
\(x=40\)