2017 x 9 + 2017 - 8 x 3
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![](https://rs.olm.vn/images/avt/0.png?1311)
làm bừa thui,ai tích mình mình tích lại
Số số hạng là :
Có số cặp là :
50 : 2 = 25 ( cặp )
Mỗi cặp có giá trị là :
99 - 97 = 2
Tổng dãy trên là :
25 x 2 = 50
Đáp số : 50
\(\frac{x-2017}{5}-\frac{x-2017}{6}=\frac{x-2017}{7}-\frac{x-2017}{8}\)
\(\Leftrightarrow\frac{x-2017}{5}-\frac{x-2017}{6}-\frac{x-2017}{7}+\frac{x-2017}{8}=0\)
\(\Leftrightarrow\left(x-2017\right)\left(\frac{1}{5}-\frac{1}{6}-\frac{1}{7}+\frac{1}{8}\right)=0\)
\(\Rightarrow x-2017=0\Rightarrow x=2017\)
Vậy x=2017
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,2017\times\left(8+2\right)=2017\times10=20170\\ b,=\dfrac{3}{7}\times\left(\dfrac{9}{7}-\dfrac{2}{7}\right)=\dfrac{3}{7}\times1=\dfrac{3}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 2017 x 34 + 2017 x 65 + 2017
= 2017 x ( 34+65+1)
= 2017 x 100
= 201700
b) 3/5 x 7/9 - 3/5 x 2/9
= 3/5 x ( 7/9- 2/9)
= 3/5 x 5/9
= 1/3
a) 2017 x 34 + 2017 x 65 + 2017
= 2017 x (34 + 65 + 1)
= 2017 x 100
= 201700
b) \(\dfrac{3}{5}\) x \(\dfrac{7}{9}\) - \(\dfrac{3}{5}\) x \(\dfrac{2}{9}\)
= \(\dfrac{3}{5}\) x \(\left(\dfrac{7}{9}-\dfrac{2}{9}\right)\)
= \(\dfrac{3}{5}\) x \(\dfrac{5}{9}\)
= \(\dfrac{1}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : A =\(\frac{2017}{2018}\)x \(\frac{7}{8}\)+ \(\frac{2017}{2018}\)x \(\frac{3}{8}\)- \(\frac{2017}{2018}\)x \(\frac{1}{4}\)
= \(\frac{2017}{2018}\) x ( \(\frac{7}{8}+\frac{3}{8}-\frac{1}{4}\))
= \(\frac{2017}{2018}\)x 1
=\(\frac{2017}{2018}\)
Vậy A= : \(\frac{2017}{2018}\)
Bài giải
\(A=\frac{2017}{2018}\text{ x }\frac{7}{8}+\frac{2017}{2018}\text{ x }\frac{3}{8}-\frac{2017}{2018}\text{ x }\frac{1}{4}\)
\(A=\frac{2017}{2018}\text{ x }\frac{1}{4}\left(\frac{7}{2}+\frac{3}{2}-1\right)=\frac{2017}{2018}\text{ x }\frac{1}{4}\text{ x }4==\frac{2017}{2018}\text{ x }1=\frac{2017}{2018}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x-9-4}{2017}+\frac{x-4-2017}{9}+\frac{x-2017-9}{4}=3\)
\(\Leftrightarrow\frac{x-13}{2017}+\frac{x-2021}{9}+\frac{x-2026}{4}=3\)
\(\Leftrightarrow\frac{x}{2017}+\frac{x}{9}+\frac{x}{4}=3+\frac{2021}{9}+\frac{2026}{4}+\frac{13}{2017}\)
\(\Leftrightarrow x\left(\frac{1}{2017}+\frac{1}{9}+\frac{1}{4}\right)=....\left(\text{tự giải tiếp :3}\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
B) 2017100.(x-60)=2017101
x-60=2017101 : 2017100
x-60 = 2017
x= 2017 + 60
x= 2077
C) 5.x+3.(10-x)+x=45
5x+30 - 3x + x = 45
3x = 45-30
3x = 15
x= 5
A) (17x-25):8+65=92
(17x-25):8 = 81 - 65
(17x-25):8 = 16
17x-25= 16:8
17x = 2+27
17x = 29
x= 29/17
![](https://rs.olm.vn/images/avt/0.png?1311)
a/ 3^21 > 2^31
b/ 2017^10 + 2017^9 <2018^10
chọn mình nha . Mình cũng học lớp 6 đó (>-<)
![](https://rs.olm.vn/images/avt/0.png?1311)
Đặt: \(x-1=a;\)\(y-3=b;\)\(z-8=c\)
=> \(a+b+c=x+y+z-12=0\)(do x+y+z = 12 )
Ta dễ dàng chứng minh được:
nếu a + b + c = 0
thì: a3 + b3 + c3 = 3abc
Như vậy ta có:
\(\left(x-1\right)^3+\left(y-3\right)^3+\left(z-8\right)^3=0\)
<=> \(3\left(x-1\right)\left(y-3\right)\left(z-8\right)=0\)
đến đây bạn xử lí nốt nhé
=20146
i don't care