Question

[Park Chanyeol]

Tính

a) 2\(\dfrac{1}{2}\) - 3,4(12) - \(\dfrac{4}{3}\) +\(\dfrac{1}{3}\) . (\(\dfrac{1}{2}\) + 0,5 - 3\(\dfrac{1}{2}\) )

d) \([\) 0,(5) .0,(2) \(]\) : ( 3\(\dfrac{1}{3}\) : \(\dfrac{23}{25}\) ) - ( \(\dfrac{2}{5}\) . \(\dfrac{11}{3}\) ) : \(\dfrac{4}{3}\)

ĐAG CẦN GẤP

Answer 1

[Nguyễn Lê Phước Thịnh]

a: \(=\dfrac{5}{2}-\dfrac{563}{165}-\dfrac{4}{3}+\dfrac{1}{3}\cdot\left(\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{7}{2}\right)\)

\(=\dfrac{-247}{110}+\dfrac{1}{3}\cdot\dfrac{-5}{2}=\dfrac{-247}{110}+\dfrac{-5}{6}=\dfrac{-508}{165}\)

b: \(=\left[\dfrac{5}{9}\cdot\dfrac{2}{9}\right]:\left(\dfrac{10}{3}\cdot\dfrac{25}{23}\right)-\dfrac{22}{15}\cdot\dfrac{3}{4}\)

\(=\dfrac{10}{18}:\dfrac{250}{69}-\dfrac{66}{60}\)

\(=\dfrac{10}{18}\cdot\dfrac{69}{250}-\dfrac{11}{10}\)

\(=\dfrac{-71}{75}\)