Rút gọn phân số :a, \(\frac{3.13-13.8}{15.40-80}\)
B,\(\frac{18.34+\left(-18\right).124}{\left(-36\right).17+9_{ }\left(-52\right)}\)
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HC
11 tháng 5 2017
\(\dfrac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\) =\(\dfrac{18.34-18.124}{9.\left(-4\right).17+9.\left(-52\right)}=\dfrac{18.\left(34-124\right)}{9.\left(-68\right)+9.\left(-52\right)}\) =\(\dfrac{18.\left(-90\right)}{9.\left(-68-52\right)}=\dfrac{18.\left(-90\right)}{9.\left(-120\right)}=\dfrac{3}{2}\)
BD
12 tháng 8 2016
\(\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}=\frac{18.34-18.124}{9.\left(-4\right)+17+9.\left(-52\right)}=\frac{18.\left(34-124\right)}{9.\left(17-52\right).\left(-4\right)}\)
\(\frac{18.\left(-90\right)}{9.\left(-35\right).\left(-4\right)}=\frac{18.\left(-90\right)}{9.140}=\frac{9.2.\left(-9\right).10}{9.7.2.10}=\frac{-9}{7}\)
10 tháng 4 2017
\(C=\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}=\frac{18.\left(34-124\right)}{9.\left(-4.17-52\right)}=\frac{18.\left(-90\right)}{9.\left(-120\right)}=\frac{3}{2}\)
10 tháng 4 2017
\(c=\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
\(=\frac{18.34+18.\left(-124\right)}{9.-3.17+9.\left(-52\right)}\)
\(=\frac{18.\left(34+\left(-124\right)\right)}{9.\left(-3+17\right).\left(52\right)}\)
tk ủng hộ mk nha!!!!!!!!!!
24 tháng 7 2020
Trả lời:
a, \(\frac{6\times9-2\times17}{63\times3-119}=\frac{2.3\times9-2\times17}{7.9\times3-7.17}\)
\(=\frac{2\times\left(3\times9-17\right)}{7\times\left(3\times9-17\right)}\)
\(=\frac{2}{7}\)
b, \(\frac{3\times13-13\times18}{15\times40-80}=\frac{13\times\left(3-18\right)}{40\times\left(15-2\right)}\)
\(=\frac{13\times-15}{40\times13}\)
\(=\frac{-3}{8}\)
c, \(\frac{-1997.1996+1}{\left(-1995\right).\left(-1997\right)+1996}=\frac{-1997.1996+1}{\left(1-1996\right).\left(-1997\right)+1996}\)
\(=\frac{-1997.1996+1}{-1997-1996.\left(-1997\right)+1996}\)
\(=\frac{-1997.1996+1}{-1996.\left(-1997\right)-1}\)
\(=\frac{-1997.1996+1}{-\left[1996.\left(-1997\right)+1\right]}\)
\(=-1\)
d, \(\frac{3.7.13.37.39-10101}{505050-70707}=\frac{10101.39-10101}{50.10101-7.10101}\)
\(=\frac{10101.\left(39-1\right)}{10101.\left(50-7\right)}\)
\(=\frac{10101.38}{10101.43}\)
\(=\frac{38}{43}\)
\(\frac{13.\left(3-8\right)}{40.\left(15-2\right)}=\frac{13.\left(-5\right)}{40.13}=\frac{-1}{8}\)
\(\frac{18.34+\left(-18\right).124}{\left(-36\right).17+9.\left(-52\right)}=\frac{18.34+18.\left(-124\right)}{\left(-36\right).17+9.\left(-4\right).13}=\frac{18.\left[34+\left(-124\right)\right]}{\left(-36\right).\left(17+13\right)}=\frac{18.\left(-90\right)}{\left(-36\right).30}=\frac{3}{2}\)
cho minh dung di