Tính tổng :
a ,1+2+3+..........+2015
b, 3+5+7+......+2015
c,1.2+2.3+3.4+......+2015.2016
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CB
1
4 tháng 8 2015
a) \(A=\frac{1}{8}+\frac{1}{24}+\frac{1}{48}+...+\frac{1}{10200}\)
\(A=\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+...+\frac{1}{100.102}\)
\(2A=\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+...+\frac{2}{100.102}\)
\(2A=\left(\frac{1}{2}-\frac{1}{4}\right)+\left(\frac{1}{4}-\frac{1}{6}\right)+\left(\frac{1}{6}-\frac{1}{8}\right)+...+\left(\frac{1}{100}-\frac{1}{102}\right)\)
\(2A=\frac{1}{2}-\frac{1}{102}\)
\(2A=\frac{25}{51}\)
\(A=\frac{25}{51}:2\)
\(A=\frac{25}{102}\)
Vậy \(\frac{1}{8}+\frac{1}{24}+\frac{1}{48}+...+\frac{1}{10200}=\frac{25}{102}\)
b) \(B=\frac{3}{1.2}+\frac{3}{2.3}+\frac{3}{3.4}+...+\frac{3}{2015.2016}\)
\(B=3.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2015.2016}\right)\)
\(B=3.\left[\left(\frac{1}{1}-\frac{1}{2}\right)+\left(\frac{1}{2}-\frac{1}{3}\right)+\left(\frac{1}{3}-\frac{1}{4}\right)+...+\left(\frac{1}{2015}-\frac{1}{2016}\right)\right]\)
\(B=3.\left(\frac{1}{1}-\frac{1}{2016}\right)\)
\(B=3.\frac{2015}{2016}\)
\(B=\frac{2015}{672}\)
Vậy \(\frac{3}{1.2}+\frac{3}{2.3}+\frac{3}{3.4}+...+\frac{3}{2015.2016}=\frac{2015}{672}\)
MU
27 tháng 3 2016
A= 1.2+2.3+3.4+...+2015.2016
3A=1.2.3+2.3.3+3.4.3+...+2015.2016.3
3A=1.2.3+2.3.(4-1)+3.4.(5-2)+...+2015.2016.(2017-2014)
3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+2015.2016.2017-2014.2015.2016
3A=2015.2016.2017
3A=8193538080
A=8193538080:3
A=2731179360
27 tháng 3 2016
3A = 1.2.3 + 2.3.3 + 3.4.3 + ..... + 2015.2016.3
=> 3A = 1.2.3 + 2.3.( 4 -1 ) + 3.4.( 5 - 2 ) + .... + 2015.2016.( 2017 - 2014 )
=> 3A = 1.2.3 + 2.3.4 - 1.2.3 + .... + 2015.2016.2017 - 2014.2015.2016
=> 3A = 2015.2016.2017
=> A = \(\frac{2015.2016.2017}{3}\)
9 tháng 10 2016
Đặt \(A=1.2+2.3+3.4+...+2015.2016\)
\(\Rightarrow3A=1.2.3+2.3.3+3.4.3+...+2015.2016.3\)
\(\Rightarrow3A=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+2015.2016.\left(2017-2014\right)\)
\(\Rightarrow3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+2015.2016.2017-2014.2015.2016\)
\(\Rightarrow3A=2015.2016.2017\)
\(\Rightarrow A=2015.2016.2017:3\)
\(\Rightarrow A=2015.672.2017\)
Vậy \(A=2015.672.2017\)
A
9 tháng 10 2016
1 . 2 + 2 . 3 + 3 . 4 + ... + 2015 . 2016
3M = 1 . 2 . 3 + 2 . 3 . 3 + 3 . 4 . 3 + ... + 2015 . 2016 . 3
3M = 1 . 2 ( 3 - 0 ) + 2 . 3 ( 4 - 1 ) + 3 . 4 ( 5 - 2 ) + ... + 2015 . 2016 ( 2017 - 2014 )
3M = ( 1 . 2 . 3 + 2 . 3 . 4 + 3 . 4. 5 + ... + 2015 . 2016 . 2017 ) - ( 0 . 1 . 2 + 1 . 2 . 3 + 2 . 3 . 4 + ... + 2014 . 2015 . 2016 )
3M = 2015 . 2016 . 2017
M = \(\frac{2015.2016.2017}{3}\)
M = 2731179360
21 tháng 9 2015
A=1.2+2.3+3.4+...+2015.2016
=> 3A=1.2.3+2.3.3+3.4.3+...+2015.2016.3
=> 3A=1.2.3+2.3.(4-1)+3.4.(5-2)+...+2015.2016.(2017-2014)
=>3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+ 2015.2016.2017-2014.2015.2016
=> 3A=2015.2016.2017
=> A=\(\frac{2015.2016.2017}{3}=2731179360\)
.
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NT
3
NK
3 tháng 1 2016
S = 1.2 + 2.3 + 3.4 +...+99.100
3S = 1.2.3 + 2.3.(4 - 1) + 3.4(5 - 2) +...+ 99.100(101 - 98)
3S = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 +...+ 99.100.101 - 98.99.100
3S = 99.100.101
3S = 999900
S = 333300
P = 1 + 3 + 5 + 7 +...+ 2015
P = (2015 + 1)1008 : 2
P = 1016064
T = 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 +...+ 97 + 98 - 99 - 100
T = (1 + 2 - 3 - 4) + (5 + 6 - 7 - 8) +...+ (97 + 98 - 99 - 100)
T = (-4) + (-4) +...+ (-4)
T = (-4)25
T = -100
MT
22 tháng 6 2015
\(\left(\frac{7}{1.2}+\frac{7}{2.3}+\frac{7}{3.4}+...+\frac{7}{2015.2016}\right):\frac{2015}{2016}\)
=\(7\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2015.2016}\right):\frac{2015}{2016}\)
=\(7\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2015}-\frac{1}{2016}\right):\frac{2015}{2016}\)
=\(7\left(\frac{1}{1}-\frac{1}{2016}\right):\frac{2015}{2016}=7.\frac{2015}{2016}:\frac{2015}{2016}=7\)
22 tháng 6 2015
\(\left(\frac{7}{1\cdot2}+\frac{7}{2\cdot3}+\frac{7}{3\cdot4}+...+\frac{7}{2015\cdot2016}\right):\frac{2015}{2016}\)
\(=\left(7-\frac{7}{2}+\frac{7}{2}-\frac{7}{3}+\frac{7}{3}-\frac{7}{4}+...+\frac{7}{2015}-\frac{7}{2016}\right):\frac{2015}{2016}\)
\(=\left(7-\frac{7}{2016}\right):\frac{2015}{2016}=\frac{2015}{288}:\frac{2015}{2016}=\frac{2015}{288}\cdot\frac{2016}{2015}=\frac{2016}{288}=7\)
TT
6
27 tháng 3 2017
\(S=\dfrac{3}{1.2}+\dfrac{3}{2.3}+...+\dfrac{3}{2015.2016}\)
\(=3\left(\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{2015.2016}\right)\)
\(=3\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{2015}-\dfrac{1}{2016}\right)\)
\(=3\left(1-\dfrac{1}{2016}\right)\)
\(=3.\dfrac{2015}{2016}=\dfrac{6045}{2016}\)
Vậy \(S=\dfrac{6045}{2016}\)
27 tháng 3 2017
\(S=3\left(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{2015.2016}\right)\)
\(\Rightarrow S=3\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{2015}-\dfrac{1}{2016}\right)\)
\(\Rightarrow S=3\left(1-\dfrac{1}{2016}\right)=3.\dfrac{2015}{2016}=\dfrac{6045}{2016}\)
Vậy ...
Tính tổng :
a ,1+2+3+..........+2015
SSH của tổng trên là :
(2015-1):1+1=2015(SH)
Tổng trên là:
(2015:2)x(2015+1)=2031120
b, 3+5+7+......+2015
SSH của tổng trên là :
(2015-3):2+1=1007(SH)
Tổng trên là:
(1007:2)x(2015+3)=1016063
LƯU ý: SSH=số số hạng nha
a 2029106
b508032
c1679780.53381924
tick đúng cho mk nha