Đề bài: điền vào dấu * *1 .(x^2+3x-1)=7x^5+*2-*3
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24 tháng 9 2021
\(1,A=\left(3x+7\right)\left(2x+3\right)-\left(2x+3\right)-\left(3x-5\right)\left(2x+11\right)\\ =6x^2+23x+21-2x-3-6x^2-23x+55\\ =73-2x\left(đề.sai\right)\\ B=x^4+x^3-x^2-2x^2-2x+2-x^4-x^3+3x^2+2x\\ =2\\ 2,\\ a,\Leftrightarrow30x^2+18x+3x-30x^2=7\\ \Leftrightarrow21x=7\Leftrightarrow x=\dfrac{1}{3}\\ b,\Leftrightarrow-63x^2+78x-15+63x^2+x-20=44\\ \Leftrightarrow79x=79\Leftrightarrow x=1\\ c,\Leftrightarrow\left(x+5\right)\left(x^2+3x+2\right)-x^3-8x^2=27\\ \Leftrightarrow x^3+3x^2+2x+5x^2+15x+10-x^3-8x^2=27\\ \Leftrightarrow17x=17\Leftrightarrow x=1\)
\(d,\Leftrightarrow7x-2x^2-3+x^2+x-6=-x^2-x+2\\ \Leftrightarrow9x=11\Leftrightarrow x=\dfrac{11}{9}\)
14 tháng 4 2023
Bài 1:
a) \(-5\left(x^2-3x+1\right)+x\left(1+5x\right)=x-2\)
\(\Rightarrow-5x^2+15x-5+x+5x^2=x-2\)
\(\Rightarrow16x-5=x-2\)
\(\Rightarrow16x-x=5-2\)
\(\Rightarrow15x=3\)
\(\Rightarrow x=\dfrac{15}{3}=5\)
b) \(12x^2-4x\left(3x+5\right)=10x-17\)
\(\Rightarrow12x^2-12x^2-20x=10x-17\)
\(\Rightarrow-20x=10x-17\)
\(\Rightarrow-20x-10x=-17\)
\(\Rightarrow-30x=-17\)
\(\Rightarrow x=\dfrac{-30}{-17}=\dfrac{30}{17}\)
c) \(-4x\left(x-5\right)+7x\left(x-4\right)-3x^2=12\)
\(\Rightarrow-4x^2+20x+7x^2-28x-3x^2=12\)
\(\Rightarrow-8x=12\)
\(\Rightarrow x=\dfrac{12}{-8}=-\dfrac{4}{3}\)
Bài 2:
a) \(\left(x+5\right)\left(x-7\right)-7x\left(x-3\right)\)
\(=x^2-7x+5x-35-7x^2+21x\)
\(=-6x^2+19x-35\)
b) \(x\left(x^2-x-2\right)-\left(x-5\right)\left(x+1\right)\)
\(=x^3-x^2-2x-x^2+x-5x-5\)
\(=x^3-2x^2-6x-5\)
c) \(\left(x-5\right)\left(x-7\right)-\left(x+4\right)\left(x-3\right)\)
\(=x^2-7x-5x+35-x^2-3x+4x-12\)
\(=11x+23\)
d) \(\left(x-1\right)\left(x-2\right)-\left(x+5\right)\left(x+2\right)\)
\(=x^2-2x-x+2-x^2+2x+5x+10\)
\(=4x+12\)
CM
22 tháng 10 2017
1 x . x x + 1 . x + 1 x + 2 . x + 2 x + 3 . x + 3 x + 4 . x + 4 x + 5 . x + 5 x + 6 . x + 6 x + 7 . x + 7 x + 8 . x + 8 x + 9 . x + 9 x + 10 . x + 10 1 = 1
NN
21 tháng 8 2023
a/
\(\dfrac{4}{15}=1-\dfrac{11}{15}\)
\(\dfrac{5}{16}=1-\dfrac{11}{16}\)
\(\dfrac{11}{15}>\dfrac{11}{16}\Rightarrow1-\dfrac{11}{15}< 1-\dfrac{11}{16}\Rightarrow\dfrac{4}{15}< \dfrac{5}{16}\)
b/
\(\dfrac{2}{113}=\dfrac{4}{226}< \dfrac{4}{115}\)
c/ \(\dfrac{2}{7}=\dfrac{4}{14}< \dfrac{4}{9}\)
d/ \(\dfrac{2}{5}=\dfrac{4}{10}< \dfrac{4}{7}\)
NM
21 tháng 8 2023
a,\(\dfrac{4}{15}< \dfrac{5}{16}\)
b,\(\dfrac{2}{113}< \dfrac{4}{115}\)
c,\(\dfrac{2}{7}< \dfrac{4}{9}\)
d,\(\dfrac{4}{7}>\dfrac{2}{5}\)
6 tháng 1 2022
Bài 2:
a: (2x-1)(x2+5x-4)
\(=2x^3+10x^2-8x-x^2-5x+4\)
\(=2x^3+9x^2-13x+4\)
b: \(=-\left(10x^2+15x-8x-12\right)\)
\(=-\left(10x^2+7x-12\right)\)
\(=-10x^2-7x+12\)
c: \(=7x^2-28x-\left(14x^3-7x^2+28x+3x^2-3x+12\right)\)
\(=7x^2-28x-14x^3+4x^2-25x-12\)
\(=-14x^3+11x^2-53x-12\)
HP
11 tháng 1 2022
\(a.\left(3x+2\right)\left(x^2-1\right)=\left(9x^2-4\right)\left(x+1\right)\)
\(\Leftrightarrow\left(3x+2\right)\left(x+1\right)\left(x-1\right)=\left(3x-2\right)\left(3x+2\right)\left(x+1\right)\)
\(\Leftrightarrow x-1=3x-2\)
\(\Leftrightarrow2x=1\)
\(\Leftrightarrow x=\dfrac{1}{2}\)
11 tháng 1 2022
c: =>x-3=0
hay x=3
d: \(\Leftrightarrow\left(3x-1\right)\cdot\left(x^2+2-7x+10\right)=0\)
\(\Leftrightarrow\left(3x-1\right)\left(x-3\right)\left(x-4\right)=0\)
hay \(x\in\left\{\dfrac{1}{3};3;4\right\}\)
