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16 tháng 1 2018

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a: Ta có: ΔABC cân tại A

mà AD là đường trung tuyến

nên D là trung điểm của BC

b: Ta có: ΔADC cân tại D

mà DE là đường cao

nên E là trung điểm của AC

TA có: ΔADC vuông tại D

mà DE là đường trung tuyến

nên DE=AC/2=AE

=>ΔEAD cân tại E

mà \(\widehat{DEA}=90^0\)

nên ΔEAD vuông cân tại E

28 tháng 4 2023

Hình nháp thôi em .

Ta có : \(\Delta ABC\) cân tại A 

\(\Rightarrow\) góc ABC \(=\) góc ACB 

Ta có : D là trung điểm của BC

\(\Rightarrow DB=DC\)

Xét \(\Delta BDE\) và \(\Delta CDF\) lần lượt vuông tại E và F có :

                góc ABC \(=\) góc ACB (cmt)

              \(DB=DC\left(cmt\right)\)

Do đó : \(\Delta BDE=\Delta CDF\left(ch-gn\right)\)

\(\Rightarrow DE=DF\)

\(\Rightarrow\Delta DEF\) cân tại D

28 tháng 4 2023

cíu mình với

 

22 tháng 3 2022

A B C D E F

a)Xét \(\Delta ABD\) và \(\Delta ACD\) có :

    \(BD=DC\)

     \(\widehat{ABD}=\widehat{ACD}\left(\Delta ABCcân\right)\)

     AB= AC

=>  \(\Delta ABD\) = \(\Delta ACD\) (c-g-c)

b) Vì \(\Delta ABC\) cân tại A nên AD vừa là đường trung tuyến vừa là đường cao

=> \(AD\perp BC\)

*Nếu chx học cách trên thì bạn xem cách dưới đây"

Vì  \(\Delta ABD\) = \(\Delta ACD\) nên \(\widehat{ADB}=\widehat{ADC}\)

mà \(\widehat{ADB}+\widehat{ADC}=180^o\)

=> \(\widehat{ADB}=\widehat{ADC}=\dfrac{180^o}{2}=90^o\)

=> \(AD\perp BC\)

c)Xét \(\Delta EBD\) vuông tại E và \(\Delta FCD\) vuông tại F có :

\(\widehat{EBD}=\widehat{FCD}\)

\(BD=CD\)

=> \(\Delta EBD=\Delta FCD\left(ch-gn\right)\)

d) Vì D là trung điểm của BC nên  \(DC=\dfrac{BC}{2}=\dfrac{12}{2}=6cm\)

Xét \(\Delta ADC\) vuông tại D có :

\(AC^2=AD^2+DC^2\)

\(100=AD^2+36\)

\(AD^2=100-36\)

\(AD^2=64\)

AD=8 cm

Bài 1:Cho tam giác ABC cân có AB=AC=5cm, BC= 8cm.Kẻ AH vuông góc với BC ( H thuộc BC).a, Chứng minh HB=HCb, Tính độ dài AH.c, Kẻ HD vuông góc với AB(D thuộc AB), kẻ HE vuông góc với AC ( E thuộc AC).Chứng minh tam giác HDE cân.d, So sánh HD và HC.Bài 2:Cho tam giác ABC cân tại A có đường cao AH.a, Chứng minh tam giác ABH = tam giác ACH và AH là tia phân giác của góc BAC.b, Cho BH= 8cm, AB= 10cm.Tính AH.c,, Gọi E là trung điểm...
Đọc tiếp

Bài 1:
Cho tam giác ABC cân có AB=AC=5cm, BC= 8cm.Kẻ AH vuông góc với BC ( H thuộc BC).
a, Chứng minh HB=HC
b, Tính độ dài AH.
c, Kẻ HD vuông góc với AB(D thuộc AB), kẻ HE vuông góc với AC ( E thuộc AC).Chứng minh tam giác HDE cân.
d, So sánh HD và HC.
Bài 2:
Cho tam giác ABC cân tại A có đường cao AH.
a, Chứng minh tam giác ABH = tam giác ACH và AH là tia phân giác của góc BAC.
b, Cho BH= 8cm, AB= 10cm.Tính AH.
c,, Gọi E là trung điểm của AC và G là giao điểm của BE và AH.Tính HG.
d, Vẽ Hx song song với AC, Hx cắt AB tại F. Chứng minh C, G, F thẳng hàng.
Bài 3
Cho tam giác ABC có CA= CB= 10cm, AB= 12cm.kẻ CI vuông góc với AB.Kẻ IH vuông góc với AC, IK vuông góc với BC.
a, Chứng minh IB= IC và tính độ dài CI
b, Chứng minh IH= IK.
c, HK// AC.
Bài 4:
Cho tam giác ABC cân tại A, vẽ AH vuông góc với BC tại H.Biết AB= 10cm, BH= 6cm.
a, Tính AH
b, tam giác ABH= tam giác ACH.
c, trên BA lấy D, CA lấy E sao cho BD= CE.Chứng minh tam giác HDE cân.
d, AH là trung trực của DE.
Bài 5:
Cho tam giác ABC cân tại AGọi D là trung điểm của BC.Từ D kẻ DE vuông góc với AB, DF vuông góc với AC. Chứng minh rằng:
a, tam giác ABD= tam giác ACD.
b, AD vuông góc với BC.
c, Cho AC= 10cm, BC= 12cm.Tính AD.
d, tam giác DEF cân.
Bài 6:
Cho tam giác ABC cân tại A có góc A < 900. kẻ BH vuông góc với AC ,CK vuông góc với AC.Gọi O là giao điểm của BH và CK.
a, Chứng minh tam giác ABH=Tam giác ACH.
b, Tam giác OBC cân.
c, Tam giác OBK = tam giác OCK.
d, trên nửa mặt phẳng bờ BC không chứa điểm A lấy I sao cho IB=IC.Chứng minh 3 điểm A, O, I thẳng hàng.
Bài 7
Cho tam giác ABC cân tại A. Kẻ BD vuông góc với AC, CE vuông góc với AB. BD và CE cắt nhau tại H.
a, Tam giác ABD=tam giác ACE.
b, Tam giác BHC cân.
c, ED//BC
d, AH cắt BC tại K, trên HK lấy M sao cho K là trung điểm của HM.Chứng minh tam giác ACM vuông.
Bài 8
Cho tam giác ABC cân tại A. Kẻ BD vuông góc với AC, CE vuông góc với AB. BD và CE cắt nhau tại H.
a, BD= CE.
b, Tam giác BHC cân.
c, AH là trung trực của BC
d, Trên tia BD lấy K sao cho D là trung điểm của BK.So sánh góc ECB và góc DKC.
Bài9
Cho tam giác ABC cân tại A.vẽ trung tuyến AM .từ M kẻ ME vuông góc với AB tại E.kẻ MF vuông góc với AC tại F.
a, chứng minh tam giác BEM= tam giác CFM.
b, AM là trung trực vủa EF.
c, từ B kẻ đường thẳng vuông góc với AB tại B, từ C kẻ đường thẳng vuông góc với AC tại C, hai đường này cắt nhau tại D.Chứng minh A,M,D thẳng hàng.
Bài 10
Cho tam giác ABC cân tại AGọi M là trung điểm của AC.Trên tia đối MB lấy D sao cho DM= BM.
a, Chứng minh Tam giác BMC= tam giác DMA.Suy ra AD//BC.
b, tam giác ACD cân.
c. trên tia đối CA lấy E sao cho CA= CE.Chuwngsminh DC đi qua trung điểm I của BE.
Bài 11: Cho tam giác ABC cân tại A (AB = AC ), M là trung điểm của BC. Gọi D là điểm là điểm nằm giữa A và M. Chứng minh rằng:
a) AM là tia phân giác của góc A?
b) (ABD = (ACD.
c) (BCD là tam giác cân ?
Bài 12: Cho tam giác ABC vuông tại A , đường phân giác BD. Kẻ DE vuông góc với BC (E  BC). Gọi F là giao điểm của BA và ED.

Giúp mk với các bạn đẹp trai xinh gái ai làm đúng mk tik cho 

Sắp hết Tết rùi giúp mk vs

9
26 tháng 4 2020

uôi dài v**

26 tháng 4 2020

ủa r viết ngần đó thì mất bn tg thek

28 tháng 1 2016

a)Vì tam giác abc cân ở a =>góc abc=góc acb.mà góc acb =góc ecn (đối đỉnh) =>góc abc=góc ecn.

Xét tam giác bmd và tam giác cne có :bd=ce; góc abc=góc ecn =>tam giác bmd =tam giác ecn(cạnh góc vuông và góc nhọn kề)

=>md=ne.

b)Vì dm và en cung vuông góc với bc =>dm song song với en=>góc dmc=góc enc(so le trong)

xét tam giác dim và tam giác ein có :góc dmc =góc enc;góc mid=góc nie(đối đỉnh);góc mdi=góc nei=90 độ=>tam giác dim=tam giác ein(g.g.g.)

=>di=ie=>i là trung điểm de

c)gọi h là giao của ao với bc.

ta có:xét tam giác abo bằng tam giác aco=>bo=co=>o thuộc trung trực của bc .tương tự a thuộc trung trực của bc=>ao là trung trực bc

a: Xét ΔMBD vuông tại D và ΔNCE vuông tại E co

MB=NC

góc MBD=góc NCE
=>ΔMBD=ΔNCE

=>MD=NE

b: Xet tứ giác MDNE có

MD//NE

MD=NE

=>MDNE là hình bình hành

=>MN cắt DE tại trung điểm của mỗi đường

=>I là trung điểm của DE

13 tháng 2 2016

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7 tháng 3 2017

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