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12 tháng 7 2015

72 * (56 + 44) + 12 * (44 + 56)

= 72 * 100 + 12* 100

= 7200 + 1200

= 8400

12 tháng 7 2015

72.56 - 12.44 + 72.44 - 12.56 = 72.(56 + 44) - 12.(44 + 56) = 72.100 - 12.100 = 100.(72 - 12) = 100.60 = 6000

14 tháng 7 2015

72 . 56 - 12 . 44 + 72 . 44 - 12 . 5

=72 x (56 + 44) + 12 x (44 + 56)

= 72 x 100 + 12 x 100

= 7200 + 1200

= 8400

18 tháng 7 2017

[44-(56-x)].12=384

44-(56-x)=32

56-x=12

x=44

18 tháng 7 2017

[44- (56-x) ] . 12 = 384

<=> (44-56+x) . 12 = 384

<=> (-12 + x) . 12  = 384

<=> 12x - 144       = 384

<=> 12x               = 384 + 144

<=> 12x               = 528

<=>    x                = 528 : 12

<=>    x                = 44

Vậy x = 44

Sửa đề:

\(\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}\)

\(=\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+\dfrac{1}{5\times6}+\dfrac{1}{6\times7}+\dfrac{1}{7\times8}+\dfrac{1}{8\times9}+\dfrac{1}{9\times10}\)

\(=\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}\)

\(=\dfrac{1}{3}-\dfrac{1}{10}\)

\(=\dfrac{10-3}{30}\)

\(=\dfrac{7}{30}\)

10 tháng 8 2015

\(=\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{\cdot5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}\)
=\(\left(\frac{1}{3}-\frac{1}{4}\right)+\left(\frac{1}{4}-\frac{1}{5}\right)+\left(\frac{1}{5}-\frac{1}{6}\right)+\left(\frac{1}{6}-\frac{1}{7}\right)+\left(\frac{1}{7}-\frac{1}{8}\right)+\left(\frac{1}{8}-\frac{1}{9}\right)\)
=1/3-1/9=2/9
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li-ke cho mk nha bn Vũ lệ Quyên

10 tháng 8 2015

\(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}=\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}+\frac{1}{6\times7}+\frac{1}{7\times8}+\frac{1}{8\times9}\)

\(=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}\)

\(=\frac{1}{3}-\frac{1}{9}=\frac{3}{9}-\frac{1}{9}=\frac{2}{9}\)

Ta có: \(\dfrac{1}{2}+\dfrac{5}{6}+\dfrac{11}{12}+\dfrac{19}{20}+\dfrac{41}{42}+\dfrac{55}{56}+\dfrac{71}{72}+\dfrac{89}{90}\)

\(=8-\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{42}+\dfrac{1}{56}+\dfrac{1}{72}+\dfrac{1}{90}\right)\)

\(=8-\left(\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}\right)\)

\(=8-1+\dfrac{1}{10}\)

\(=\dfrac{71}{10}\)

10 tháng 11 2020

1/2+...................+71/72

=(1-1/2)+......................+(1-1/72)

=1+1+.....+1-1/2-...................-1/72

=8-(1/2+...................+1/72)

=8-(2-1/1*2+3-2/2*3+.............+9-8/8*9)

=8-(1-1/2+1/2-1/3+1/3-..............+1/8-1/9)

=8-(1-1/9)

=8-8/9

=64/9

9 tháng 8 2016

1/12 + 1/20 1/30  + 1/42 + 1/56 + 1/72 + 1/90

= 1/3.4 + 1/4.5 + 1/5.6 + 1/6.7 + 1/7.8 + 1/8.9 + 1/9.10

= 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 + 1/7 - 1/7 + 1/8 - 1/9 + 1/9 - 1/10

= 1/3 - 1/10

= 7/30

1/12+1/20+1/30+1/42+1/56+1/72+1/90=7/30

a) \(\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+...+\frac{89}{90}\)

\(=1-\frac{1}{6}+1-\frac{1}{12}+...+1-\frac{1}{90}\)

\(=\left(1+1+1+...+1\right)-\left(\frac{1}{6}+\frac{1}{12}+...+\frac{1}{90}\right)\)

\(=\left(1+1+1+...+1\right)-\left(\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{9\cdot10}\right)\)

Từ 2 đến 9 có : ( 9 - 2 ) / 1 + 1 = 8 ( số hạng ) => có 8 số 1

\(\Rightarrow8-\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\right)\)

\(=8-\left(\frac{1}{2}-\frac{1}{10}\right)\)

\(=8-\frac{2}{5}=\frac{38}{5}\)

b) \(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+...+\frac{109}{110}\)

\(=1-\frac{1}{2}+1-\frac{1}{6}+...+1-\frac{1}{110}\)

\(=\left(1+1+1+...+1\right)-\left(\frac{1}{2}+\frac{1}{6}+...+\frac{1}{110}\right)\)

\(=\left(1+1+...+1\right)-\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+...+\frac{1}{10\cdot11}\right)\)

Từ 1 đến 10 có : ( 10 - 1 ) / 1 + 1 = 10 ( số hạng ) => có 10 số 1

\(\Rightarrow10-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{10}-\frac{1}{11}\right)\)

\(=10-\left(1-\frac{1}{11}\right)\)

\(=10-\frac{10}{11}=\frac{100}{11}\)